Moderne Wiskunde (13e editie) - 2 vmbo gt(h)
'Rekenvolgorde'.
| 2 vmbo gt(h) | 1.5 Rekenvolgorde |
opgave 1Bereken. 1p a \(40 : 2 : 4\) PositiefDrieDelen (1) 00ah - Rekenvolgorde - basis - 1ms a \(40 : 2 : 4 = 20 : 4 = 5 \text{.}\) 1p 1p b \(5 + 6 ⋅ 3\) PositiefDrieDelen (2) 00ai - Rekenvolgorde - basis - 1ms b \(5 + 6 ⋅ 3 = 5 + 18 = 23 \text{.}\) 1p 1p c \((7 + 3) ⋅ 5\) PositiefDrieDelen (3) 00aj - Rekenvolgorde - basis - 0ms c \((7 + 3) ⋅ 5 = 10 ⋅ 5 = 50 \text{.}\) 1p 1p d \(16 : 2 ⋅ 9\) PositiefDrieDelen (4) 00ak - Rekenvolgorde - basis - 0ms d \(16 : 2 ⋅ 9 = 8 ⋅ 9 = 72 \text{.}\) 1p opgave 2Bereken. 1p a \(5 - 6 : 2\) PositiefDrieDelen (5) 00al - Rekenvolgorde - basis - 0ms a \(5 - 6 : 2 = 5 - 3 = 2 \text{.}\) 1p 1p b \(5 + 6 ⋅ (2 + 4)\) PositiefVierDelen (1) 00am - Rekenvolgorde - basis - 0ms b \(5 + 6 ⋅ (2 + 4) = 5 + 6 ⋅ 6 = 5 + 36 = 41 \text{.}\) 1p 1p c \((9 + 5) ⋅ (7 + 6)\) PositiefVierDelen (2) 00an - Rekenvolgorde - basis - 0ms c \((9 + 5) ⋅ (7 + 6) = 14 ⋅ 13 = 182 \text{.}\) 1p 1p d \(34 - 7 ⋅ 4 + 3\) PositiefVierDelen (3) 00ao - Rekenvolgorde - basis - 0ms d \(34 - 7 ⋅ 4 + 3 = 34 - 28 + 3 = 6 + 3 = 9 \text{.}\) 1p |