Moderne Wiskunde (13e editie) - 2 vmbo gt(h)

'Rekenvolgorde'.

2 vmbo gt(h) 1.5 Rekenvolgorde

Rekenvolgorde (8)

opgave 1

Bereken.

1p

a

\(180 : 5 : 4\)

PositiefDrieDelen (1)
00ah - Rekenvolgorde - basis - 0ms

a

\(180 : 5 : 4 = 36 : 4 = 9 \text{.}\)

1p

1p

b

\(7 + 2 ⋅ 4\)

PositiefDrieDelen (2)
00ai - Rekenvolgorde - basis - 0ms

b

\(7 + 2 ⋅ 4 = 7 + 8 = 15 \text{.}\)

1p

1p

c

\((4 + 8) ⋅ 2\)

PositiefDrieDelen (3)
00aj - Rekenvolgorde - basis - 0ms

c

\((4 + 8) ⋅ 2 = 12 ⋅ 2 = 24 \text{.}\)

1p

1p

d

\(12 : 4 ⋅ 7\)

PositiefDrieDelen (4)
00ak - Rekenvolgorde - basis - 0ms

d

\(12 : 4 ⋅ 7 = 3 ⋅ 7 = 21 \text{.}\)

1p

opgave 2

Bereken.

1p

a

\(8 - 21 : 3\)

PositiefDrieDelen (5)
00al - Rekenvolgorde - basis - 0ms

a

\(8 - 21 : 3 = 8 - 7 = 1 \text{.}\)

1p

1p

b

\(6 + 8 ⋅ (5 + 7)\)

PositiefVierDelen (1)
00am - Rekenvolgorde - basis - 0ms

b

\(6 + 8 ⋅ (5 + 7) = 6 + 8 ⋅ 12 = 6 + 96 = 102 \text{.}\)

1p

1p

c

\((8 + 2) ⋅ (5 + 6)\)

PositiefVierDelen (2)
00an - Rekenvolgorde - basis - 0ms

c

\((8 + 2) ⋅ (5 + 6) = 10 ⋅ 11 = 110 \text{.}\)

1p

1p

d

\(33 - 4 ⋅ 6 + 2\)

PositiefVierDelen (3)
00ao - Rekenvolgorde - basis - 0ms

d

\(33 - 4 ⋅ 6 + 2 = 33 - 24 + 2 = 9 + 2 = 11 \text{.}\)

1p
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