Moderne Wiskunde (13e editie) - 2 vmbo gt(h)

'Rekenvolgorde'.

2 vmbo gt(h) 1.5 Rekenvolgorde

Rekenvolgorde (8)

opgave 1

Bereken.

1p

a

\(120 : 6 : 4\)

PositiefDrieDelen (1)
00ah - Rekenvolgorde - basis - 0ms

a

\(120 : 6 : 4 = 20 : 4 = 5 \text{.}\)

1p

1p

b

\(6 + 5 ⋅ 4\)

PositiefDrieDelen (2)
00ai - Rekenvolgorde - basis - 0ms

b

\(6 + 5 ⋅ 4 = 6 + 20 = 26 \text{.}\)

1p

1p

c

\((9 + 6) ⋅ 3\)

PositiefDrieDelen (3)
00aj - Rekenvolgorde - basis - 0ms

c

\((9 + 6) ⋅ 3 = 15 ⋅ 3 = 45 \text{.}\)

1p

1p

d

\(18 : 3 ⋅ 5\)

PositiefDrieDelen (4)
00ak - Rekenvolgorde - basis - 0ms

d

\(18 : 3 ⋅ 5 = 6 ⋅ 5 = 30 \text{.}\)

1p

opgave 2

Bereken.

1p

a

\(8 - 10 : 2\)

PositiefDrieDelen (5)
00al - Rekenvolgorde - basis - 0ms

a

\(8 - 10 : 2 = 8 - 5 = 3 \text{.}\)

1p

1p

b

\(2 + 4 ⋅ (5 + 8)\)

PositiefVierDelen (1)
00am - Rekenvolgorde - basis - 0ms

b

\(2 + 4 ⋅ (5 + 8) = 2 + 4 ⋅ 13 = 2 + 52 = 54 \text{.}\)

1p

1p

c

\((4 + 2) ⋅ (7 + 9)\)

PositiefVierDelen (2)
00an - Rekenvolgorde - basis - 0ms

c

\((4 + 2) ⋅ (7 + 9) = 6 ⋅ 16 = 96 \text{.}\)

1p

1p

d

\(21 - 8 ⋅ 2 + 9\)

PositiefVierDelen (3)
00ao - Rekenvolgorde - basis - 0ms

d

\(21 - 8 ⋅ 2 + 9 = 21 - 16 + 9 = 5 + 9 = 14 \text{.}\)

1p
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