Moderne Wiskunde (13e editie) - 2 vmbo gt(h)

'Rekenvolgorde'.

2 vmbo gt(h) 1.5 Rekenvolgorde

Rekenvolgorde (8)

opgave 1

Bereken.

1p

a

\(30 : 3 : 2\)

PositiefDrieDelen (1)
00ah - Rekenvolgorde - basis - 0ms

a

\(30 : 3 : 2 = 10 : 2 = 5 \text{.}\)

1p

1p

b

\(4 + 3 ⋅ 5\)

PositiefDrieDelen (2)
00ai - Rekenvolgorde - basis - 0ms

b

\(4 + 3 ⋅ 5 = 4 + 15 = 19 \text{.}\)

1p

1p

c

\((2 + 9) ⋅ 8\)

PositiefDrieDelen (3)
00aj - Rekenvolgorde - basis - 0ms

c

\((2 + 9) ⋅ 8 = 11 ⋅ 8 = 88 \text{.}\)

1p

1p

d

\(6 : 3 ⋅ 5\)

PositiefDrieDelen (4)
00ak - Rekenvolgorde - basis - 0ms

d

\(6 : 3 ⋅ 5 = 2 ⋅ 5 = 10 \text{.}\)

1p

opgave 2

Bereken.

1p

a

\(4 - 6 : 2\)

PositiefDrieDelen (5)
00al - Rekenvolgorde - basis - 0ms

a

\(4 - 6 : 2 = 4 - 3 = 1 \text{.}\)

1p

1p

b

\(7 + 3 ⋅ (5 + 2)\)

PositiefVierDelen (1)
00am - Rekenvolgorde - basis - 0ms

b

\(7 + 3 ⋅ (5 + 2) = 7 + 3 ⋅ 7 = 7 + 21 = 28 \text{.}\)

1p

1p

c

\((7 + 2) ⋅ (6 + 5)\)

PositiefVierDelen (2)
00an - Rekenvolgorde - basis - 0ms

c

\((7 + 2) ⋅ (6 + 5) = 9 ⋅ 11 = 99 \text{.}\)

1p

1p

d

\(55 - 8 ⋅ 6 + 2\)

PositiefVierDelen (3)
00ao - Rekenvolgorde - basis - 0ms

d

\(55 - 8 ⋅ 6 + 2 = 55 - 48 + 2 = 7 + 2 = 9 \text{.}\)

1p
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