Moderne Wiskunde (13e editie) - 2 vmbo gt(h)
'Rekenvolgorde'.
| 2 vmbo gt(h) | 1.5 Rekenvolgorde |
opgave 1Bereken. 1p a \(270 : 6 : 5\) PositiefDrieDelen (1) 00ah - Rekenvolgorde - basis - 1ms a \(270 : 6 : 5 = 45 : 5 = 9 \text{.}\) 1p 1p b \(3 + 5 ⋅ 2\) PositiefDrieDelen (2) 00ai - Rekenvolgorde - basis - 1ms b \(3 + 5 ⋅ 2 = 3 + 10 = 13 \text{.}\) 1p 1p c \((2 + 4) ⋅ 6\) PositiefDrieDelen (3) 00aj - Rekenvolgorde - basis - 0ms c \((2 + 4) ⋅ 6 = 6 ⋅ 6 = 36 \text{.}\) 1p 1p d \(18 : 9 ⋅ 8\) PositiefDrieDelen (4) 00ak - Rekenvolgorde - basis - 0ms d \(18 : 9 ⋅ 8 = 2 ⋅ 8 = 16 \text{.}\) 1p opgave 2Bereken. 1p a \(6 - 12 : 3\) PositiefDrieDelen (5) 00al - Rekenvolgorde - basis - 0ms a \(6 - 12 : 3 = 6 - 4 = 2 \text{.}\) 1p 1p b \(4 + 9 ⋅ (2 + 5)\) PositiefVierDelen (1) 00am - Rekenvolgorde - basis - 0ms b \(4 + 9 ⋅ (2 + 5) = 4 + 9 ⋅ 7 = 4 + 63 = 67 \text{.}\) 1p 1p c \((6 + 3) ⋅ (4 + 2)\) PositiefVierDelen (2) 00an - Rekenvolgorde - basis - 0ms c \((6 + 3) ⋅ (4 + 2) = 9 ⋅ 6 = 54 \text{.}\) 1p 1p d \(76 - 9 ⋅ 8 + 3\) PositiefVierDelen (3) 00ao - Rekenvolgorde - basis - 0ms d \(76 - 9 ⋅ 8 + 3 = 76 - 72 + 3 = 4 + 3 = 7 \text{.}\) 1p |