\({1 \over p^5}=p^{-5}\)

\({3x \over 7x^6}={3 \over 7}⋅{x \over x^6}={3 \over 7}⋅x^{1-6}={3 \over 7}x^{-5}\)

\({x^7 \over x^{-9}}=x^{7--9}=x^{16}\)

\(a^2⋅a^{-7}=a^{2+-7}=a^{-5}\)

\((a^8)^{-7}=a^{8⋅-7}=a^{-56}\)

\(x^3⋅{1 \over x^5}=x^3⋅x^{-5}=x^{3+-5}=x^{-2}\)

\({a^0 \over a^7}=a^{0-7}=a^{-7}\)

\({9 \over p^3}\)

\((3x)^{-5}=3^{-5}⋅x^{-5}={1 \over 3^5}⋅{1 \over x^5}={1 \over 243x^5}\)

\(x^4⋅\sqrt[8]{x}=x^4⋅x^{\frac{1}{8}}=x^{4+\frac{1}{8}}=x^{4\frac{1}{8}}\)

\(a^9⋅\sqrt[3]{a^2}=a^9⋅a^{\frac{2}{3}}=a^{9+\frac{2}{3}}=a^{9\frac{2}{3}}\)

\({p^6 \over \sqrt[7]{p^6}}={p^6 \over p^{\frac{6}{7}}}=p^{6-\frac{6}{7}}=p^{5\frac{1}{7}}\)

\({1 \over a^8}⋅\sqrt[8]{a^7}=a^{-8}⋅a^{\frac{7}{8}}=a^{-8+\frac{7}{8}}=a^{-7\frac{1}{8}}\)

\({\sqrt[4]{x^3} \over \sqrt[5]{x^3}}={x^{\frac{3}{4}} \over x^{\frac{3}{5}}}=x^{\frac{3}{4}-\frac{3}{5}}=x^{\frac{3}{20}}\)

\(\sqrt{x^6}=x^{\frac{6}{2}}=x^3\)

\({x^8 \over x^5⋅\sqrt[9]{x^7}}={x^8 \over x^5⋅x^{\frac{7}{9}}}={x^8 \over x^{5\frac{7}{9}}}=x^{8-5\frac{7}{9}}=x^{2\frac{2}{9}}\)

\(6p^{2\frac{2}{5}}=6⋅p^2⋅p^{\frac{2}{5}}=6p^2⋅\sqrt[5]{p^2}\)