\({9 \over 6 x} + {4 \over 6 x} = {13 \over 6 x}\)

\({2 \over a} - {3 \over 7 a} = {14 \over 7 a} - {3 \over 7 a} = {11 \over 7 a}\)

\({2 \over 5 a} - {8 \over 7 b} = {14 b \over 35 a b} - {40 a \over 35 a b} = {14 b - 40 a \over 35 a b}\)

\(6 + {7 \over 8 x} = {6 \over 1} + {7 \over 8 x} = {48 x \over 8 x} + {7 \over 8 x} = {48 x + 7 \over 8 x}\)

\({9 p \over q} - {3 \over 2 q} = {18 p \over 2 q} - {3 \over 2 q} = {18 p - 3 \over 2 q}\)

\({2 x \over x} = {2 \over 1} = 2\)

\({a \over 9 a} = {1 \over 9}\)

\({20 x \over 32 x} = \frac{5}{8}\)

\({-12 a \over 2 a} = -6\)

\({15 p q \over -35 p r} = -{3 q \over 7 r}\)

\({14 b \over -18 a b} = -{7 \over 9 a}\)

\({16 a b c \over 2 b c} = 8 a\)

\({7 x y \over y} + {5 x z \over z} = 7 x + 5 x = 12 x\)

\(2 a - {9 \over 8 a} = {2 a \over 1} ⋅ {8 a \over 8 a} - {9 \over 8 a} = {16 a^{2} \over 8 a} - {9 \over 8 a} = {16 a^{2} - 9 \over 8 a}\)

\({6 b \over 5 a} + {9 a \over 2 b} = {12 b^{2} \over 10 a b} + {45 a^{2} \over 10 a b} = {45 a^{2} + 12 b^{2} \over 10 a b}\)

\({4 \over p} ⋅ {9 \over q} = {36 \over p q}\)

\({x \over 4} ⋅ -{2 \over y} = -{2 x \over 4 y} = -{x \over 2 y}\)

\(-{2 \over 5} ⋅ x = -{2 x \over 5}\)

\({8 b \over a} ⋅ {a + 5 \over 3} = {8 b (a + 5) \over 3 a} = {8 a b + 40 b \over 3 a}\)

\({8 \over x} : {5 \over y} = {8 \over x} ⋅ {y \over 5} = {8 y \over 5 x}\)

\({1 \over 3} : x = {1 \over 3} : {x \over 1} = {1 \over 3} ⋅ {1 \over x} = {1 \over 3 x}\)

\({6 \over 5} : {a + 9 b \over b} = {6 \over 5} ⋅ {b \over a + 9 b} = {6 b \over 5 (a + 9 b)} = {6 b \over 5 a + 45 b}\)

\({7 p \over 6} + {p - 8 \over 5} = {35 p \over 30} + {6 (p - 8) \over 30} = {35 p + 6 (p - 8) \over 30} = {41 p - 48 \over 30}\)

\({-5 a + 2 \over 3 a - 8} - 6 = {-5 a + 2 \over 3 a - 8} - {6 (3 a - 8) \over 3 a - 8} = {-5 a + 2 - 6 (3 a - 8) \over 3 a - 8} = {-5 a + 2 - 18 a + 48 \over 3 a - 8} = {-23 a + 50 \over 3 a - 8}\)

\({2 a^{2} + 3 a + 10 \over a} = {2 a^{2} \over a} + {3 a \over a} + {10 \over a} = 2 a + 3 + {10 \over a}\)

\({3 p^{2} + 2 p - 6 \over 4 p^{2}} = {3 p^{2} \over 4 p^{2}} + {2 p \over 4 p^{2}} - {6 \over 4 p^{2}} = \frac{3}{4} + {1 \over 2 p} - {3 \over 2 p^{2}}\)