\({3 \over 8x}+{5 \over 8x}={8 \over 8x}={1 \over x}\)

\({7 \over x}+{5 \over 6x}={42 \over 6x}+{5 \over 6x}={47 \over 6x}\)

\({7 \over 8p}+{4 \over 2q}={7q \over 8pq}+{16p \over 8pq}={7q+16p \over 8pq}\)

\(4+{7 \over 2a}={4 \over 1}+{7 \over 2a}={8a \over 2a}+{7 \over 2a}={8a+7 \over 2a}\)

\({3a \over b}-{9 \over 8b}={24a \over 8b}-{9 \over 8b}={24a-9 \over 8b}\)

\({9a \over a}={9 \over 1}=9\)

\({a \over 3a}={1 \over 3}\)

\({35x \over -45x}=-\frac{7}{9}\)

\({18x \over -3x}=-6\)

\({-15pq \over -18pr}={5q \over 6r}\)

\({8y \over 20xy}={2 \over 5x}\)

\({10xyz \over -2yz}=-5x\)

\({7pq \over q}+{4pr \over r}=7p+4p=11p\)

\(2p+{3 \over 8p}={2p \over 1}⋅{8p \over 8p}+{3 \over 8p}={16p^2 \over 8p}+{3 \over 8p}={16p^2+3 \over 8p}\)

\({3y \over 7x}-{9x \over 4y}={12y^2 \over 28xy}-{63x^2 \over 28xy}={-63x^2+12y^2 \over 28xy}\)

\({4 \over a}⋅-{6 \over b}=-{24 \over ab}\)

\({x \over 4}⋅{7 \over y}={7x \over 4y}\)

\({8 \over 7}⋅a={8a \over 7}\)

\({6y \over x}⋅{x-9 \over 2}={6y(x-9) \over 2x}={3y(x-9) \over x}={3xy-27y \over x}\)

\({7 \over a}:{5 \over b}={7 \over a}⋅{b \over 5}={7b \over 5a}\)

\(-{9 \over 8}:a=-{9 \over 8}:{a \over 1}=-{9 \over 8}⋅{1 \over a}=-{9 \over 8a}\)

\(-{9 \over 2}:{p-4q \over q}=-{9 \over 2}⋅{q \over p-4q}=-{9q \over 2(p-4q)}=-{9q \over 2p-8q}\)

\({2x \over 3}+{x-7 \over 8}={16x \over 24}+{3(x-7) \over 24}={16x+3(x-7) \over 24}={19x-21 \over 24}\)

\({-6p+1 \over 2p+9}+4={-6p+1 \over 2p+9}+{4(2p+9) \over 2p+9}={-6p+1+4(2p+9) \over 2p+9}={-6p+1+8p+36 \over 2p+9}={2p+37 \over 2p+9}\)

\({a^2+3a+20 \over a}={a^2 \over a}+{3a \over a}+{20 \over a}=a+3+{20 \over a}\)

\({7x^2+6x+2 \over 4x^2}={7x^2 \over 4x^2}+{6x \over 4x^2}+{2 \over 4x^2}=1\frac{3}{4}+{3 \over 2x}+{1 \over 2x^2}\)