\({6 \over 5 p} + {2 \over 5 p} = {8 \over 5 p}\)

\({7 \over x} + {3 \over 4 x} = {28 \over 4 x} + {3 \over 4 x} = {31 \over 4 x}\)

\({4 \over 2 a} - {5 \over 9 b} = {36 b \over 18 a b} - {10 a \over 18 a b} = {36 b - 10 a \over 18 a b} = {18 b - 5 a \over 9 a b}\)

\(2 - {6 \over 5 x} = {2 \over 1} - {6 \over 5 x} = {10 x \over 5 x} - {6 \over 5 x} = {10 x - 6 \over 5 x}\)

\({2 a \over b} + {8 \over 4 b} = {8 a \over 4 b} + {8 \over 4 b} = {8 a + 8 \over 4 b} = {2 a + 2 \over b}\)

\({9 x \over x} = {9 \over 1} = 9\)

\({a \over 3 a} = {1 \over 3}\)

\({4 a \over -14 a} = -\frac{2}{7}\)

\({-32 x \over -4 x} = 8\)

\({-12 p q \over 15 p r} = -{4 q \over 5 r}\)

\({6 q \over 8 p q} = {3 \over 4 p}\)

\({16 a b c \over -2 b c} = -8 a\)

\({5 x y \over y} + {3 x z \over z} = 5 x + 3 x = 8 x\)

\(3 p - {9 \over 7 p} = {3 p \over 1} ⋅ {7 p \over 7 p} - {9 \over 7 p} = {21 p^{2} \over 7 p} - {9 \over 7 p} = {21 p^{2} - 9 \over 7 p}\)

\({7 y \over 6 x} + {2 x \over 8 y} = {28 y^{2} \over 24 x y} + {6 x^{2} \over 24 x y} = {6 x^{2} + 28 y^{2} \over 24 x y} = {3 x^{2} + 14 y^{2} \over 12 x y}\)

\({7 \over x} ⋅ -{6 \over y} = -{42 \over x y}\)

\({a \over 3} ⋅ -{4 \over b} = -{4 a \over 3 b}\)

\({2 \over 7} ⋅ a = {2 a \over 7}\)

\({2 y \over x} ⋅ {x + 6 \over 4} = {2 y (x + 6) \over 4 x} = {y (x + 6) \over 2 x} = {x y + 6 y \over 2 x}\)

\({7 \over x} : {8 \over y} = {7 \over x} ⋅ {y \over 8} = {7 y \over 8 x}\)

\(-{4 \over 3} : a = -{4 \over 3} : {a \over 1} = -{4 \over 3} ⋅ {1 \over a} = -{4 \over 3 a}\)

\(-{4 \over 5} : {a - 6 b \over b} = -{4 \over 5} ⋅ {b \over a - 6 b} = -{4 b \over 5 (a - 6 b)} = -{4 b \over 5 a - 30 b}\)

\({9 p \over 2} + {p + 3 \over 5} = {45 p \over 10} + {2 (p + 3) \over 10} = {45 p + 2 (p + 3) \over 10} = {47 p + 6 \over 10}\)

\({5 p - 1 \over 6 p + 2} - 3 = {5 p - 1 \over 6 p + 2} - {3 (6 p + 2) \over 6 p + 2} = {5 p - 1 - 3 (6 p + 2) \over 6 p + 2} = {5 p - 1 - 18 p - 6 \over 6 p + 2} = {-13 p - 7 \over 6 p + 2}\)

\({6 a^{2} + 9 a + 30 \over 3 a} = {6 a^{2} \over 3 a} + {9 a \over 3 a} + {30 \over 3 a} = 2 a + 3 + {10 \over a}\)

\({4 x^{2} + 7 x + 6 \over 9 x^{2}} = {4 x^{2} \over 9 x^{2}} + {7 x \over 9 x^{2}} + {6 \over 9 x^{2}} = \frac{4}{9} + {7 \over 9 x} + {2 \over 3 x^{2}}\)