Getal & Ruimte (13e editie) - vwo wiskunde B

'Wortels vereenvoudigen'.

2 vwo 5.3 Wortels herleiden

Wortels vereenvoudigen (5)

opgave 1

Herleid.

2p

a

\(\sqrt{500}+\sqrt{80}\)

Optellen (5)
0085 - Wortels vereenvoudigen - basis - 1ms

a

\(\sqrt{500}+\sqrt{80}=\sqrt{100}⋅\sqrt{5}+\sqrt{16}⋅\sqrt{5}=10\sqrt{5}+4\sqrt{5}\text{.}\)

1p

\(10\sqrt{5}+4\sqrt{5}=14\sqrt{5}\text{.}\)

1p

1p

b

\(\sqrt{500}\)

FactorVoorWortelteken (1)
0086 - Wortels vereenvoudigen - basis - 1ms

b

\(\sqrt{500}=\sqrt{100}⋅\sqrt{5}=10\sqrt{5}\text{.}\)

1p

1p

c

\(-6\sqrt{50}\)

FactorVoorWortelteken (2)
0087 - Wortels vereenvoudigen - basis - 1ms

c

\(-6\sqrt{50}=-6⋅\sqrt{25}⋅\sqrt{2}=-6⋅5⋅\sqrt{2}=-30\sqrt{2}\text{.}\)

1p

2p

d

\(3\sqrt{125}+7\sqrt{80}\)

Optellen (6)
0088 - Wortels vereenvoudigen - basis - 1ms

d

\(3\sqrt{125}+7\sqrt{80}=3⋅\sqrt{25}⋅\sqrt{5}+7⋅\sqrt{16}⋅\sqrt{5}\text{.}\)

1p

\(3⋅5⋅\sqrt{5}+7⋅4⋅\sqrt{5}=15\sqrt{5}+28\sqrt{5}=43\sqrt{5}\text{.}\)

1p

opgave 2

Herleid.

1p

\(\sqrt{\frac{1}{64}}\)

BreukInWortel (1)
008b - Wortels vereenvoudigen - basis - 103ms

\(\sqrt{\frac{1}{64}}={\sqrt{1} \over \sqrt{64}}=\frac{1}{8}\text{.}\)

1p

3 vwo 5.5 Wortels herleiden

Wortels vereenvoudigen (6)

opgave 1

Herleid.

1p

a

\({7 \over 4\sqrt{3}}\)

WortelInNoemer
0089 - Wortels vereenvoudigen - basis - 1ms

a

\({7 \over 4\sqrt{3}}={7 \over 4\sqrt{3}}⋅{\sqrt{3} \over \sqrt{3}}={7\sqrt{3} \over 4⋅3}=\frac{7}{12}\sqrt{3}\text{.}\)

1p

1p

b

\(\sqrt{\frac{79}{81}}\)

BreukInWortel (2)
008c - Wortels vereenvoudigen - basis - 1ms

b

\(\sqrt{\frac{79}{81}}={\sqrt{79} \over \sqrt{81}}={\sqrt{79} \over 9}=\frac{1}{9}\sqrt{79}\text{.}\)

1p

1p

c

\(\sqrt{\frac{9}{50}}\)

BreukInWortel (3)
008d - Wortels vereenvoudigen - basis - 1ms

c

\(\sqrt{\frac{9}{50}}={\sqrt{9} \over \sqrt{50}}={3 \over \sqrt{50}}⋅{\sqrt{50} \over \sqrt{50}}={3\sqrt{50} \over 50}=\frac{3}{50}\sqrt{50}=\frac{3}{50}⋅5⋅\sqrt{2}=\frac{3}{10}\sqrt{2}\text{.}\)

1p

1p

d

\(\sqrt{2\frac{4}{5}}\)

BreukInWortel (4)
008e - Wortels vereenvoudigen - basis - 1ms

d

\(\sqrt{2\frac{4}{5}}=\sqrt{\frac{14}{5}}={\sqrt{14} \over \sqrt{5}}⋅{\sqrt{5} \over \sqrt{5}}={\sqrt{70} \over 5}=\frac{1}{5}\sqrt{70}\text{.}\)

1p

opgave 2

Herleid.

1p

a

\({45\sqrt{144} \over 9\sqrt{6}}\)

Delen (4)
00dc - Wortels vereenvoudigen - basis - 16ms

a

\({45\sqrt{144} \over 9\sqrt{6}}={45 \over 9}⋅{\sqrt{144} \over \sqrt{6}}=5\sqrt{24}=5⋅\sqrt{4}⋅\sqrt{6}=5⋅2⋅\sqrt{6}=10\sqrt{6}\)

1p

1p

b

\(4\sqrt{14}⋅2\sqrt{6}\)

Vermenigvuldigen (5)
00dd - Wortels vereenvoudigen - basis - 6ms - data pool: #22 (5ms)

b

\(4\sqrt{14}⋅2\sqrt{6}=8\sqrt{84}=8⋅\sqrt{4}⋅\sqrt{21}=8⋅2⋅\sqrt{21}=16\sqrt{21}\)

1p

vwo wiskunde B 3.3 Vergelijkingen in de meetkunde

Wortels vereenvoudigen (2)

opgave 1

Herleid.

1p

a

\({-3 \over 1-\sqrt{5}}\)

SomInNoemer (1)
00r3 - Wortels vereenvoudigen - basis - 1ms

a

\({-3 \over 1-\sqrt{5}}={-3 \over 1-\sqrt{5}}⋅{1+\sqrt{5} \over 1+\sqrt{5}}\)
\(\text{}={-3(1-\sqrt{5}) \over 1-5}\)
\(\text{}=\frac{3}{4}(1-\sqrt{5})\)
\(\text{}=\frac{3}{4}-\frac{3}{4}\sqrt{5}\)

1p

1p

b

\({\sqrt{6} \over \sqrt{5}-\sqrt{3}}\)

SomInNoemer (2)
00r4 - Wortels vereenvoudigen - basis - 1ms

b

\({\sqrt{6} \over \sqrt{5}-\sqrt{3}}={\sqrt{6} \over \sqrt{5}-\sqrt{3}}⋅{\sqrt{5}+\sqrt{3} \over \sqrt{5}+\sqrt{3}}\)
\(\text{}={\sqrt{6}(\sqrt{5}+\sqrt{3}) \over 5-3}\)
\(\text{}=\frac{1}{2}\sqrt{6}(\sqrt{5}+\sqrt{3})\)
\(\text{}=\frac{1}{2}\sqrt{30}+\frac{1}{2}\sqrt{18}\)
\(\text{}=\frac{1}{2}\sqrt{30}+1\frac{1}{2}\sqrt{2}\)

1p

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