Getal & Ruimte (13e editie) - vwo wiskunde B
'Wortels vereenvoudigen'.
| 2 vwo | 5.3 Wortels herleiden |
opgave 1Herleid. 2p a \(\sqrt{20} + \sqrt{500}\) Optellen (5) 0085 - Wortels vereenvoudigen - basis - 0ms a \(\sqrt{20} + \sqrt{500} = \sqrt{4} ⋅ \sqrt{5} + \sqrt{100} ⋅ \sqrt{5} = 2 \sqrt{5} + 10 \sqrt{5} \text{.}\) 1p ○ \(2 \sqrt{5} + 10 \sqrt{5} = 12 \sqrt{5} \text{.}\) 1p 1p b \(\sqrt{80}\) FactorVoorWortelteken (1) 0086 - Wortels vereenvoudigen - basis - 0ms b \(\sqrt{80} = \sqrt{16} ⋅ \sqrt{5} = 4 \sqrt{5} \text{.}\) 1p 1p c \(5 \sqrt{125}\) FactorVoorWortelteken (2) 0087 - Wortels vereenvoudigen - basis - 0ms c \(5 \sqrt{125} = 5 ⋅ \sqrt{25} ⋅ \sqrt{5} = 5 ⋅ 5 ⋅ \sqrt{5} = 25 \sqrt{5} \text{.}\) 1p 2p d \(6 \sqrt{32} - 7 \sqrt{8}\) Optellen (6) 0088 - Wortels vereenvoudigen - basis - 0ms d \(6 \sqrt{32} - 7 \sqrt{8} = 6 ⋅ \sqrt{16} ⋅ \sqrt{2} - 7 ⋅ \sqrt{4} ⋅ \sqrt{2} \text{.}\) 1p ○ \(6 ⋅ 4 ⋅ \sqrt{2} - 7 ⋅ 2 ⋅ \sqrt{2} = 24 \sqrt{2} - 14 \sqrt{2} = 10 \sqrt{2} \text{.}\) 1p opgave 2Herleid. 1p \(\sqrt{\frac{25}{49}}\) BreukInWortel (1) 008b - Wortels vereenvoudigen - basis - 72ms ○ \(\sqrt{\frac{25}{49}} = {\sqrt{25} \over \sqrt{49}} = \frac{5}{7} \text{.}\) 1p |
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| 3 vwo | 5.5 Wortels herleiden |
opgave 1Herleid. 1p a \({5 \over 4 \sqrt{7}}\) WortelInNoemer 0089 - Wortels vereenvoudigen - basis - 0ms a \({5 \over 4 \sqrt{7}} = {5 \over 4 \sqrt{7}} ⋅ {\sqrt{7} \over \sqrt{7}} = {5 \sqrt{7} \over 4 ⋅ 7} = \frac{5}{28} \sqrt{7} \text{.}\) 1p 1p b \(\sqrt{\frac{17}{64}}\) BreukInWortel (2) 008c - Wortels vereenvoudigen - basis - 1ms b \(\sqrt{\frac{17}{64}} = {\sqrt{17} \over \sqrt{64}} = {\sqrt{17} \over 8} = \frac{1}{8} \sqrt{17} \text{.}\) 1p 1p c \(\sqrt{1\frac{1}{35}}\) BreukInWortel (3) 008d - Wortels vereenvoudigen - basis - 0ms c \(\sqrt{1\frac{1}{35}} = \sqrt{\frac{36}{35}} = {\sqrt{36} \over \sqrt{35}} = {6 \over \sqrt{35}} ⋅ {\sqrt{35} \over \sqrt{35}} = {6 \sqrt{35} \over 35} = \frac{6}{35} \sqrt{35} \text{.}\) 1p 1p d \(\sqrt{1\frac{3}{8}}\) BreukInWortel (4) 008e - Wortels vereenvoudigen - basis - 0ms d \(\sqrt{1\frac{3}{8}} = \sqrt{\frac{11}{8}} = {\sqrt{11} \over \sqrt{8}} ⋅ {\sqrt{8} \over \sqrt{8}} = {\sqrt{88} \over 8} = \frac{1}{8} \sqrt{88} = \frac{1}{8} ⋅ 2 ⋅ \sqrt{22} = \frac{1}{4} \sqrt{22} \text{.}\) 1p opgave 2Herleid. 1p a \({9 \sqrt{168} \over \sqrt{6}}\) Delen (4) 00dc - Wortels vereenvoudigen - basis - 7ms a \({9 \sqrt{168} \over \sqrt{6}} = 9 ⋅ {\sqrt{168} \over \sqrt{6}} = 9 \sqrt{28} = 9 ⋅ \sqrt{4} ⋅ \sqrt{7} = 9 ⋅ 2 ⋅ \sqrt{7} = 18 \sqrt{7}\) 1p 1p b \(2 \sqrt{2} ⋅ 4 \sqrt{10}\) Vermenigvuldigen (5) 00dd - Wortels vereenvoudigen - basis - 2ms - data pool: #22 (2ms) b \(2 \sqrt{2} ⋅ 4 \sqrt{10} = 8 \sqrt{20} = 8 ⋅ \sqrt{4} ⋅ \sqrt{5} = 8 ⋅ 2 ⋅ \sqrt{5} = 16 \sqrt{5}\) 1p |
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| vwo wiskunde B | 3.3 Vergelijkingen in de meetkunde |
opgave 1Herleid. 1p a \({2 \over 4 - \sqrt{6}}\) SomInNoemer (1) 00r3 - Wortels vereenvoudigen - basis - 0ms a \({2 \over 4 - \sqrt{6}} = {2 \over 4 - \sqrt{6}} ⋅ {4 + \sqrt{6} \over 4 + \sqrt{6}}\) 1p 1p b \({\sqrt{5} \over \sqrt{3} - \sqrt{6}}\) SomInNoemer (2) 00r4 - Wortels vereenvoudigen - basis - 0ms b \({\sqrt{5} \over \sqrt{3} - \sqrt{6}} = {\sqrt{5} \over \sqrt{3} - \sqrt{6}} ⋅ {\sqrt{3} + \sqrt{6} \over \sqrt{3} + \sqrt{6}}\) 1p |