Getal & Ruimte (13e editie) - vwo wiskunde B
'Wortels vereenvoudigen'.
| 2 vwo | 5.3 Wortels herleiden |
opgave 1Herleid. 2p a \(\sqrt{500}+\sqrt{80}\) Optellen (5) 0085 - Wortels vereenvoudigen - basis - 1ms a \(\sqrt{500}+\sqrt{80}=\sqrt{100}⋅\sqrt{5}+\sqrt{16}⋅\sqrt{5}=10\sqrt{5}+4\sqrt{5}\text{.}\) 1p ○ \(10\sqrt{5}+4\sqrt{5}=14\sqrt{5}\text{.}\) 1p 1p b \(\sqrt{500}\) FactorVoorWortelteken (1) 0086 - Wortels vereenvoudigen - basis - 1ms b \(\sqrt{500}=\sqrt{100}⋅\sqrt{5}=10\sqrt{5}\text{.}\) 1p 1p c \(-6\sqrt{50}\) FactorVoorWortelteken (2) 0087 - Wortels vereenvoudigen - basis - 1ms c \(-6\sqrt{50}=-6⋅\sqrt{25}⋅\sqrt{2}=-6⋅5⋅\sqrt{2}=-30\sqrt{2}\text{.}\) 1p 2p d \(3\sqrt{125}+7\sqrt{80}\) Optellen (6) 0088 - Wortels vereenvoudigen - basis - 1ms d \(3\sqrt{125}+7\sqrt{80}=3⋅\sqrt{25}⋅\sqrt{5}+7⋅\sqrt{16}⋅\sqrt{5}\text{.}\) 1p ○ \(3⋅5⋅\sqrt{5}+7⋅4⋅\sqrt{5}=15\sqrt{5}+28\sqrt{5}=43\sqrt{5}\text{.}\) 1p opgave 2Herleid. 1p \(\sqrt{\frac{1}{64}}\) BreukInWortel (1) 008b - Wortels vereenvoudigen - basis - 103ms ○ \(\sqrt{\frac{1}{64}}={\sqrt{1} \over \sqrt{64}}=\frac{1}{8}\text{.}\) 1p |
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| 3 vwo | 5.5 Wortels herleiden |
opgave 1Herleid. 1p a \({7 \over 4\sqrt{3}}\) WortelInNoemer 0089 - Wortels vereenvoudigen - basis - 1ms a \({7 \over 4\sqrt{3}}={7 \over 4\sqrt{3}}⋅{\sqrt{3} \over \sqrt{3}}={7\sqrt{3} \over 4⋅3}=\frac{7}{12}\sqrt{3}\text{.}\) 1p 1p b \(\sqrt{\frac{79}{81}}\) BreukInWortel (2) 008c - Wortels vereenvoudigen - basis - 1ms b \(\sqrt{\frac{79}{81}}={\sqrt{79} \over \sqrt{81}}={\sqrt{79} \over 9}=\frac{1}{9}\sqrt{79}\text{.}\) 1p 1p c \(\sqrt{\frac{9}{50}}\) BreukInWortel (3) 008d - Wortels vereenvoudigen - basis - 1ms c \(\sqrt{\frac{9}{50}}={\sqrt{9} \over \sqrt{50}}={3 \over \sqrt{50}}⋅{\sqrt{50} \over \sqrt{50}}={3\sqrt{50} \over 50}=\frac{3}{50}\sqrt{50}=\frac{3}{50}⋅5⋅\sqrt{2}=\frac{3}{10}\sqrt{2}\text{.}\) 1p 1p d \(\sqrt{2\frac{4}{5}}\) BreukInWortel (4) 008e - Wortels vereenvoudigen - basis - 1ms d \(\sqrt{2\frac{4}{5}}=\sqrt{\frac{14}{5}}={\sqrt{14} \over \sqrt{5}}⋅{\sqrt{5} \over \sqrt{5}}={\sqrt{70} \over 5}=\frac{1}{5}\sqrt{70}\text{.}\) 1p opgave 2Herleid. 1p a \({45\sqrt{144} \over 9\sqrt{6}}\) Delen (4) 00dc - Wortels vereenvoudigen - basis - 16ms a \({45\sqrt{144} \over 9\sqrt{6}}={45 \over 9}⋅{\sqrt{144} \over \sqrt{6}}=5\sqrt{24}=5⋅\sqrt{4}⋅\sqrt{6}=5⋅2⋅\sqrt{6}=10\sqrt{6}\) 1p 1p b \(4\sqrt{14}⋅2\sqrt{6}\) Vermenigvuldigen (5) 00dd - Wortels vereenvoudigen - basis - 6ms - data pool: #22 (5ms) b \(4\sqrt{14}⋅2\sqrt{6}=8\sqrt{84}=8⋅\sqrt{4}⋅\sqrt{21}=8⋅2⋅\sqrt{21}=16\sqrt{21}\) 1p |
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| vwo wiskunde B | 3.3 Vergelijkingen in de meetkunde |
opgave 1Herleid. 1p a \({-3 \over 1-\sqrt{5}}\) SomInNoemer (1) 00r3 - Wortels vereenvoudigen - basis - 1ms a \({-3 \over 1-\sqrt{5}}={-3 \over 1-\sqrt{5}}⋅{1+\sqrt{5} \over 1+\sqrt{5}}\) 1p 1p b \({\sqrt{6} \over \sqrt{5}-\sqrt{3}}\) SomInNoemer (2) 00r4 - Wortels vereenvoudigen - basis - 1ms b \({\sqrt{6} \over \sqrt{5}-\sqrt{3}}={\sqrt{6} \over \sqrt{5}-\sqrt{3}}⋅{\sqrt{5}+\sqrt{3} \over \sqrt{5}+\sqrt{3}}\) 1p |