Getal & Ruimte (13e editie) - vwo wiskunde B

'Wortels vereenvoudigen'.

2 vwo 5.3 Wortels herleiden

Wortels vereenvoudigen (5)

opgave 1

Herleid.

2p

a

\(\sqrt{20} + \sqrt{500}\)

Optellen (5)
0085 - Wortels vereenvoudigen - basis - 0ms

a

\(\sqrt{20} + \sqrt{500} = \sqrt{4} ⋅ \sqrt{5} + \sqrt{100} ⋅ \sqrt{5} = 2 \sqrt{5} + 10 \sqrt{5} \text{.}\)

1p

\(2 \sqrt{5} + 10 \sqrt{5} = 12 \sqrt{5} \text{.}\)

1p

1p

b

\(\sqrt{80}\)

FactorVoorWortelteken (1)
0086 - Wortels vereenvoudigen - basis - 0ms

b

\(\sqrt{80} = \sqrt{16} ⋅ \sqrt{5} = 4 \sqrt{5} \text{.}\)

1p

1p

c

\(5 \sqrt{125}\)

FactorVoorWortelteken (2)
0087 - Wortels vereenvoudigen - basis - 0ms

c

\(5 \sqrt{125} = 5 ⋅ \sqrt{25} ⋅ \sqrt{5} = 5 ⋅ 5 ⋅ \sqrt{5} = 25 \sqrt{5} \text{.}\)

1p

2p

d

\(6 \sqrt{32} - 7 \sqrt{8}\)

Optellen (6)
0088 - Wortels vereenvoudigen - basis - 0ms

d

\(6 \sqrt{32} - 7 \sqrt{8} = 6 ⋅ \sqrt{16} ⋅ \sqrt{2} - 7 ⋅ \sqrt{4} ⋅ \sqrt{2} \text{.}\)

1p

\(6 ⋅ 4 ⋅ \sqrt{2} - 7 ⋅ 2 ⋅ \sqrt{2} = 24 \sqrt{2} - 14 \sqrt{2} = 10 \sqrt{2} \text{.}\)

1p

opgave 2

Herleid.

1p

\(\sqrt{\frac{25}{49}}\)

BreukInWortel (1)
008b - Wortels vereenvoudigen - basis - 72ms

\(\sqrt{\frac{25}{49}} = {\sqrt{25} \over \sqrt{49}} = \frac{5}{7} \text{.}\)

1p

3 vwo 5.5 Wortels herleiden

Wortels vereenvoudigen (6)

opgave 1

Herleid.

1p

a

\({5 \over 4 \sqrt{7}}\)

WortelInNoemer
0089 - Wortels vereenvoudigen - basis - 0ms

a

\({5 \over 4 \sqrt{7}} = {5 \over 4 \sqrt{7}} ⋅ {\sqrt{7} \over \sqrt{7}} = {5 \sqrt{7} \over 4 ⋅ 7} = \frac{5}{28} \sqrt{7} \text{.}\)

1p

1p

b

\(\sqrt{\frac{17}{64}}\)

BreukInWortel (2)
008c - Wortels vereenvoudigen - basis - 1ms

b

\(\sqrt{\frac{17}{64}} = {\sqrt{17} \over \sqrt{64}} = {\sqrt{17} \over 8} = \frac{1}{8} \sqrt{17} \text{.}\)

1p

1p

c

\(\sqrt{1\frac{1}{35}}\)

BreukInWortel (3)
008d - Wortels vereenvoudigen - basis - 0ms

c

\(\sqrt{1\frac{1}{35}} = \sqrt{\frac{36}{35}} = {\sqrt{36} \over \sqrt{35}} = {6 \over \sqrt{35}} ⋅ {\sqrt{35} \over \sqrt{35}} = {6 \sqrt{35} \over 35} = \frac{6}{35} \sqrt{35} \text{.}\)

1p

1p

d

\(\sqrt{1\frac{3}{8}}\)

BreukInWortel (4)
008e - Wortels vereenvoudigen - basis - 0ms

d

\(\sqrt{1\frac{3}{8}} = \sqrt{\frac{11}{8}} = {\sqrt{11} \over \sqrt{8}} ⋅ {\sqrt{8} \over \sqrt{8}} = {\sqrt{88} \over 8} = \frac{1}{8} \sqrt{88} = \frac{1}{8} ⋅ 2 ⋅ \sqrt{22} = \frac{1}{4} \sqrt{22} \text{.}\)

1p

opgave 2

Herleid.

1p

a

\({9 \sqrt{168} \over \sqrt{6}}\)

Delen (4)
00dc - Wortels vereenvoudigen - basis - 7ms

a

\({9 \sqrt{168} \over \sqrt{6}} = 9 ⋅ {\sqrt{168} \over \sqrt{6}} = 9 \sqrt{28} = 9 ⋅ \sqrt{4} ⋅ \sqrt{7} = 9 ⋅ 2 ⋅ \sqrt{7} = 18 \sqrt{7}\)

1p

1p

b

\(2 \sqrt{2} ⋅ 4 \sqrt{10}\)

Vermenigvuldigen (5)
00dd - Wortels vereenvoudigen - basis - 2ms - data pool: #22 (2ms)

b

\(2 \sqrt{2} ⋅ 4 \sqrt{10} = 8 \sqrt{20} = 8 ⋅ \sqrt{4} ⋅ \sqrt{5} = 8 ⋅ 2 ⋅ \sqrt{5} = 16 \sqrt{5}\)

1p

vwo wiskunde B 3.3 Vergelijkingen in de meetkunde

Wortels vereenvoudigen (2)

opgave 1

Herleid.

1p

a

\({2 \over 4 - \sqrt{6}}\)

SomInNoemer (1)
00r3 - Wortels vereenvoudigen - basis - 0ms

a

\({2 \over 4 - \sqrt{6}} = {2 \over 4 - \sqrt{6}} ⋅ {4 + \sqrt{6} \over 4 + \sqrt{6}}\)
\(\text{} = {2 (4 - \sqrt{6}) \over 16 - 6}\)
\(\text{} = \frac{1}{5} (4 - \sqrt{6})\)
\(\text{} = \frac{4}{5} - \frac{1}{5} \sqrt{6}\)

1p

1p

b

\({\sqrt{5} \over \sqrt{3} - \sqrt{6}}\)

SomInNoemer (2)
00r4 - Wortels vereenvoudigen - basis - 0ms

b

\({\sqrt{5} \over \sqrt{3} - \sqrt{6}} = {\sqrt{5} \over \sqrt{3} - \sqrt{6}} ⋅ {\sqrt{3} + \sqrt{6} \over \sqrt{3} + \sqrt{6}}\)
\(\text{} = {\sqrt{5} (\sqrt{3} + \sqrt{6}) \over 3 - 6}\)
\(\text{} = -\frac{1}{3} \sqrt{5} (\sqrt{3} + \sqrt{6})\)
\(\text{} = -\frac{1}{3} \sqrt{15} - \frac{1}{3} \sqrt{30}\)

1p

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