Getal & Ruimte (13e editie) - vwo wiskunde B

'Differentiëren'.

vwo wiskunde B 2.3 Limiet en afgeleide

Differentiëren (5)

opgave 1

Differentieer.

2p

a

\(f(a) = 8 a^{2} + 7 a + 5\)

Machtsfunctie (1)
009w - Differentiëren - basis - basis - 1ms - dynamic variables

a

\(f'(a) = 8 ⋅ 2 ⋅ a^{1} + 7 \text{.}\)

1p

\(f'(a) = 16 a + 7 \text{.}\)

1p

2p

b

\(f(x) = 6 x^{6} + 7 x^{4} - 4 x^{3} + 8\)

Machtsfunctie (2)
009x - Differentiëren - basis - basis - 4ms - dynamic variables

b

\(f'(x) = 6 ⋅ 6 ⋅ x^{5} + 7 ⋅ 4 ⋅ x^{3} - 4 ⋅ 3 ⋅ x^{2} \text{.}\)

1p

\(f'(x) = 36 x^{5} + 28 x^{3} - 12 x^{2} \text{.}\)

1p

2p

c

\(f(a) = 1\frac{1}{2} a^{7} + 7 a^{3} + 1\frac{1}{4} a\)

Machtsfunctie (3)
009y - Differentiëren - basis - basis - 1ms - dynamic variables

c

\(f'(a) = 1\frac{1}{2} ⋅ 7 ⋅ a^{6} + 7 ⋅ 3 ⋅ a^{2} + 1\frac{1}{4} \text{.}\)

1p

\(f'(a) = 10\frac{1}{2} a^{6} + 21 a^{2} + 1\frac{1}{4} \text{.}\)

1p

2p

d

\(f(p) = (7 p^{5} - 3) (p - 9)\)

HaakjesUitwerken (1)
00df - Differentiëren - basis - eind - 0ms - dynamic variables

d

(Haakjes wegwerken)
\(f(p) = (7 p^{5} - 3) (p - 9) = 7 p^{6} - 63 p^{5} - 3 p + 27\)

1p

(Differentiëren)
\(f'(p) = 42 p^{5} - 315 p^{4} - 3 \text{.}\)

1p

opgave 2

Differentieer.

2p

\(f(x) = (3 x^{5} + 1)^{2}\)

HaakjesUitwerken (2)
00dg - Differentiëren - basis - eind - 0ms - dynamic variables

(Haakjes wegwerken)
\(f(x) = (3 x^{5} + 1)^{2} = 9 x^{10} + 6 x^{5} + 1\)

1p

(Differentiëren)
\(f'(x) = 90 x^{9} + 30 x^{4} \text{.}\)

1p

vwo wiskunde B 2.4 De productregel en de quotiëntregel

Differentiëren (4)

opgave 1

Differentieer met behulp van de productregel.

2p

a

\(f(x) = (4 x + 5) (-4 x^{2} + 6 x)\)

Productregel (1)
009z - Differentiëren - basis - basis - 1ms - dynamic variables

a

(Productregel)
\(f'(x) = 4 (-4 x^{2} + 6 x) + (4 x + 5) (-8 x + 6) \text{.}\)

2p

2p

b

\(f(p) = (9 p^{2} + p) (3 p^{2} - 2 p + 2)\)

Productregel (2)
00a0 - Differentiëren - basis - basis - 1ms - dynamic variables

b

(Productregel)
\(f'(p) = (18 p + 1) (3 p^{2} - 2 p + 2) + (9 p^{2} + p) (6 p - 2) \text{.}\)

2p

opgave 2

Differentieer.

2p

a

\(f(a) = {-2 a - 3 \over 5 a - 1}\)

Quotientregel (1)
00a1 - Differentiëren - basis - eind - 1ms - dynamic variables

a

(Quotiëntregel)
\(f'(a) = {(5 a - 1) ⋅ -2 - (-2 a - 3) ⋅ 5 \over (5 a - 1)^{2}} \text{.}\)

1p

\(f'(a) = {(-10 a + 2) - (-10 a - 15) \over (5 a - 1)^{2}} = {17 \over (5 a - 1)^{2}} \text{.}\)

1p

2p

b

\(f(x) = {9 x^{2} \over -7 x + 7}\)

Quotientregel (2)
00a2 - Differentiëren - basis - eind - 1ms - dynamic variables

b

(Quotiëntregel)
\(f'(x) = {(-7 x + 7) ⋅ 18 x - 9 x^{2} ⋅ -7 \over (-7 x + 7)^{2}} \text{.}\)

1p

\(f'(x) = {(-126 x^{2} + 126 x) - -63 x^{2} \over (-7 x + 7)^{2}} = {-63 x^{2} + 126 x \over (-7 x + 7)^{2}} \text{.}\)

1p

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