\(f'(a)=9⋅2⋅a^1+8\text{.}\)

\(f'(a)=18a+8\text{.}\)

\(f'(x)=-7⋅3⋅x^2-2⋅2⋅x^1\text{.}\)

\(f'(x)=-21x^2-4x\text{.}\)

\(f'(p)=1\frac{1}{4}⋅6⋅p^5+\frac{1}{8}⋅4⋅p^3+\frac{2}{9}⋅3⋅p^2\text{.}\)

\(f'(p)=7\frac{1}{2}p^5+\frac{1}{2}p^3+\frac{2}{3}p^2\text{.}\)

Haakjes wegwerken geeft \(f(x)=(4x^5+1)(x-7)=4x^6-28x^5+x-7\)

Differentiëren geeft \(f'(x)=24x^5-140x^4+1\text{.}\)

Haakjes wegwerken geeft \(f(a)=(2a^4-3)^2=4a^8-12a^4+9\)

Differentiëren geeft \(f'(a)=32a^7-48a^3\text{.}\)

De productregel geeft \(f'(a)=-5(4a^2-8a)+(-5a-7)(8a-8)\text{.}\)

De productregel geeft \(f'(x)=(-2x+9)(6x^2+5x-5)+(-x^2+9x)(12x+5)\text{.}\)

De quotiëntregel geeft
\(f'(p)={(p+5)⋅-5-(-5p-6)⋅1 \over (p+5)^2}\text{.}\)

\(f'(p)={(-5p-25)-(-5p-6) \over (p+5)^2}={-19 \over (p+5)^2}\text{.}\)

De quotiëntregel geeft
\(f'(a)={(9a+1)⋅14a-7a^2⋅9 \over (9a+1)^2}\text{.}\)

\(f'(a)={(126a^2+14a)-63a^2 \over (9a+1)^2}={63a^2+14a \over (9a+1)^2}\text{.}\)