Getal & Ruimte (13e editie) - vwo wiskunde B

'Differentiëren'.

vwo wiskunde B 2.3 Limiet en afgeleide

Differentiëren (5)

opgave 1

Differentieer.

2p

a

\(f(a) = a^{3} + 6\)

Machtsfunctie (1)
009w - Differentiëren - basis - basis - 1ms - dynamic variables

a

\(f'(a) = 3 ⋅ a^{2} \text{.}\)

1p

○

\(f'(a) = 3 a^{2} \text{.}\)

1p

2p

b

\(f(x) = 7 x^{9} + x^{4} + 4 x\)

Machtsfunctie (2)
009x - Differentiëren - basis - basis - 2ms - dynamic variables

b

\(f'(x) = 7 ⋅ 9 ⋅ x^{8} + 4 ⋅ x^{3} + 4 \text{.}\)

1p

○

\(f'(x) = 63 x^{8} + 4 x^{3} + 4 \text{.}\)

1p

2p

c

\(f(x) = \frac{1}{3} x^{6} + 3 x^{3} + 1\frac{1}{4} x^{2} + 7\)

Machtsfunctie (3)
009y - Differentiëren - basis - basis - 0ms - dynamic variables

c

\(f'(x) = \frac{1}{3} ⋅ 6 ⋅ x^{5} + 3 ⋅ 3 ⋅ x^{2} + 1\frac{1}{4} ⋅ 2 ⋅ x^{1} \text{.}\)

1p

○

\(f'(x) = 2 x^{5} + 9 x^{2} + 2\frac{1}{2} x \text{.}\)

1p

2p

d

\(f(p) = (8 p^{4} - 5) (p + 6)\)

HaakjesUitwerken (1)
00df - Differentiëren - basis - eind - 0ms - dynamic variables

d

(Haakjes wegwerken)
\(f(p) = (8 p^{4} - 5) (p + 6) = 8 p^{5} + 48 p^{4} - 5 p - 30\)

1p

○

(Differentiëren)
\(f'(p) = 40 p^{4} + 192 p^{3} - 5 \text{.}\)

1p

opgave 2

Differentieer.

2p

\(f(a) = (4 a^{3} + 2)^{2}\)

HaakjesUitwerken (2)
00dg - Differentiëren - basis - eind - 0ms - dynamic variables

○

(Haakjes wegwerken)
\(f(a) = (4 a^{3} + 2)^{2} = 16 a^{6} + 16 a^{3} + 4\)

1p

○

(Differentiëren)
\(f'(a) = 96 a^{5} + 48 a^{2} \text{.}\)

1p

vwo wiskunde B 2.4 De productregel en de quotiëntregel

Differentiëren (4)

opgave 1

Differentieer met behulp van de productregel.

2p

a

\(f(x) = (-2 x + 7) (-4 x^{2} - 5 x)\)

Productregel (1)
009z - Differentiëren - basis - basis - 1ms - dynamic variables

a

(Productregel)
\(f'(x) = -2 (-4 x^{2} - 5 x) + (-2 x + 7) (-8 x - 5) \text{.}\)

2p

2p

b

\(f(a) = (-3 a^{2} + 8 a) (-2 a^{2} + 7 a + 1)\)

Productregel (2)
00a0 - Differentiëren - basis - basis - 0ms - dynamic variables

b

(Productregel)
\(f'(a) = (-6 a + 8) (-2 a^{2} + 7 a + 1) + (-3 a^{2} + 8 a) (-4 a + 7) \text{.}\)

2p

opgave 2

Differentieer.

2p

a

\(f(x) = {4 x - 6 \over -x - 7}\)

Quotientregel (1)
00a1 - Differentiëren - basis - eind - 1ms - dynamic variables

a

(Quotiëntregel)
\(f'(x) = {(-x - 7) ⋅ 4 - (4 x - 6) ⋅ -1 \over (-x - 7)^{2}} \text{.}\)

1p

○

\(f'(x) = {(-4 x - 28) - (-4 x + 6) \over (-x - 7)^{2}} = {-34 \over (-x - 7)^{2}} \text{.}\)

1p

2p

b

\(f(p) = {-7 p^{2} \over 2 p + 8}\)

Quotientregel (2)
00a2 - Differentiëren - basis - eind - 0ms - dynamic variables

b

(Quotiëntregel)
\(f'(p) = {(2 p + 8) ⋅ -14 p - -7 p^{2} ⋅ 2 \over (2 p + 8)^{2}} \text{.}\)

1p

○

\(f'(p) = {(-28 p^{2} - 112 p) - -14 p^{2} \over (2 p + 8)^{2}} = {-14 p^{2} - 112 p \over (2 p + 8)^{2}} \text{.}\)

1p

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