\({5 \over 6 a} + {3 \over 6 a} = {8 \over 6 a} = {4 \over 3 a}\)

\({2 \over x} - {3 \over 5 x} = {10 \over 5 x} - {3 \over 5 x} = {7 \over 5 x}\)

\({8 \over 3 p} - {4 \over 9 q} = {24 q \over 9 p q} - {4 p \over 9 p q} = {24 q - 4 p \over 9 p q}\)

\(5 + {4 \over 3 a} = {5 \over 1} + {4 \over 3 a} = {15 a \over 3 a} + {4 \over 3 a} = {15 a + 4 \over 3 a}\)

\({6 x \over y} - {5 \over 2 y} = {12 x \over 2 y} - {5 \over 2 y} = {12 x - 5 \over 2 y}\)

\({9 x \over x} = {9 \over 1} = 9\)

\({x \over 3 x} = {1 \over 3}\)

\({-15 p \over 18 p} = -\frac{5}{6}\)

\({-35 a \over 5 a} = -7\)

\({6 a b \over 21 a c} = {2 b \over 7 c}\)

\({20 b \over 28 a b} = {5 \over 7 a}\)

\({16 x y z \over -2 y z} = -8 x\)

\({7 x y \over y} + {4 x z \over z} = 7 x + 4 x = 11 x\)

\(2 x - {8 \over 3 x} = {2 x \over 1} ⋅ {3 x \over 3 x} - {8 \over 3 x} = {6 x^{2} \over 3 x} - {8 \over 3 x} = {6 x^{2} - 8 \over 3 x}\)

\({9 b \over 2 a} + {8 a \over 5 b} = {45 b^{2} \over 10 a b} + {16 a^{2} \over 10 a b} = {16 a^{2} + 45 b^{2} \over 10 a b}\)

\({9 \over x} ⋅ {5 \over y} = {45 \over x y}\)

\({p \over 9} ⋅ {4 \over q} = {4 p \over 9 q}\)

\({6 \over 5} ⋅ a = {6 a \over 5}\)

\({2 q \over p} ⋅ {p + 4 \over 8} = {2 q (p + 4) \over 8 p} = {q (p + 4) \over 4 p} = {p q + 4 q \over 4 p}\)

\({8 \over a} : {2 \over b} = {8 \over a} ⋅ {b \over 2} = {8 b \over 2 a} = {4 b \over a}\)

\(-{4 \over 7} : a = -{4 \over 7} : {a \over 1} = -{4 \over 7} ⋅ {1 \over a} = -{4 \over 7 a}\)

\(-{8 \over 7} : {x - 2 y \over y} = -{8 \over 7} ⋅ {y \over x - 2 y} = -{8 y \over 7 (x - 2 y)} = -{8 y \over 7 x - 14 y}\)

\({x \over 6} + {x + 5 \over 7} = {7 x \over 42} + {6 (x + 5) \over 42} = {7 x + 6 (x + 5) \over 42} = {13 x + 30 \over 42}\)

\({4 a - 8 \over 5 a + 6} - 7 = {4 a - 8 \over 5 a + 6} - {7 (5 a + 6) \over 5 a + 6} = {4 a - 8 - 7 (5 a + 6) \over 5 a + 6} = {4 a - 8 - 35 a - 42 \over 5 a + 6} = {-31 a - 50 \over 5 a + 6}\)

\({3 a^{2} - 2 a + 10 \over a} = {3 a^{2} \over a} - {2 a \over a} + {10 \over a} = 3 a - 2 + {10 \over a}\)

\({5 a^{2} - 7 a - 6 \over 2 a^{2}} = {5 a^{2} \over 2 a^{2}} - {7 a \over 2 a^{2}} - {6 \over 2 a^{2}} = 2\frac{1}{2} - {7 \over 2 a} - {3 \over a^{2}}\)