\({7 \over 8p}-{5 \over 8p}={2 \over 8p}={1 \over 4p}\)

\({6 \over x}+{9 \over 3x}={18 \over 3x}+{9 \over 3x}={27 \over 3x}={9 \over x}\)

\({4 \over 8a}+{3 \over 2b}={4b \over 8ab}+{12a \over 8ab}={4b+12a \over 8ab}={b+3a \over 2ab}\)

\(2+{7 \over 9a}={2 \over 1}+{7 \over 9a}={18a \over 9a}+{7 \over 9a}={18a+7 \over 9a}\)

\({5x \over y}-{8 \over 3y}={15x \over 3y}-{8 \over 3y}={15x-8 \over 3y}\)

\({5x \over x}={5 \over 1}=5\)

\({a \over 8a}={1 \over 8}\)

\({-35x \over -40x}=\frac{7}{8}\)

\({-32p \over 4p}=-8\)

\({-25ab \over 45ac}=-{5b \over 9c}\)

\({-10b \over 12ab}=-{5 \over 6a}\)

\({14pqr \over -2qr}=-7p\)

\({3xy \over y}+{7xz \over z}=3x+7x=10x\)

\(5a-{2 \over 3a}={5a \over 1}⋅{3a \over 3a}-{2 \over 3a}={15a^2 \over 3a}-{2 \over 3a}={15a^2-2 \over 3a}\)

\({5q \over 8p}+{6p \over 7q}={35q^2 \over 56pq}+{48p^2 \over 56pq}={48p^2+35q^2 \over 56pq}\)

\({8 \over x}⋅{2 \over y}={16 \over xy}\)

\({x \over 7}⋅-{8 \over y}=-{8x \over 7y}\)

\({9 \over 4}⋅a={9a \over 4}\)

\({8y \over x}⋅{x-6 \over 2}={8y(x-6) \over 2x}={4y(x-6) \over x}={4xy-24y \over x}\)

\({4 \over p}:{7 \over q}={4 \over p}⋅{q \over 7}={4q \over 7p}\)

\({8 \over 5}:a={8 \over 5}:{a \over 1}={8 \over 5}⋅{1 \over a}={8 \over 5a}\)

\(-{9 \over 7}:{a-8b \over b}=-{9 \over 7}⋅{b \over a-8b}=-{9b \over 7(a-8b)}=-{9b \over 7a-56b}\)

\({9x \over 8}+{x-7 \over 5}={45x \over 40}+{8(x-7) \over 40}={45x+8(x-7) \over 40}={53x-56 \over 40}\)

\({-3x-1 \over 2x-7}+6={-3x-1 \over 2x-7}+{6(2x-7) \over 2x-7}={-3x-1+6(2x-7) \over 2x-7}={-3x-1+12x-42 \over 2x-7}={9x-43 \over 2x-7}\)

\({a^2-2a+30 \over a}={a^2 \over a}-{2a \over a}+{30 \over a}=a-2+{30 \over a}\)

\({8x^2-6x-9 \over 5x^2}={8x^2 \over 5x^2}-{6x \over 5x^2}-{9 \over 5x^2}=1\frac{3}{5}-{6 \over 5x}-{9 \over 5x^2}\)