\({3 \over 8 x} - {5 \over 8 x} = -{2 \over 8 x} = -{1 \over 4 x}\)

\({5 \over a} - {2 \over 7 a} = {35 \over 7 a} - {2 \over 7 a} = {33 \over 7 a}\)

\({6 \over 3 a} - {5 \over 4 b} = {24 b \over 12 a b} - {15 a \over 12 a b} = {24 b - 15 a \over 12 a b} = {8 b - 5 a \over 4 a b}\)

\(2 - {5 \over 3 p} = {2 \over 1} - {5 \over 3 p} = {6 p \over 3 p} - {5 \over 3 p} = {6 p - 5 \over 3 p}\)

\({8 x \over y} + {4 \over 9 y} = {72 x \over 9 y} + {4 \over 9 y} = {72 x + 4 \over 9 y}\)

\({9 x \over x} = {9 \over 1} = 9\)

\({a \over 3 a} = {1 \over 3}\)

\({6 p \over 9 p} = \frac{2}{3}\)

\({20 x \over 4 x} = 5\)

\({-20 a b \over -35 a c} = {4 b \over 7 c}\)

\({15 q \over 35 p q} = {3 \over 7 p}\)

\({16 a b c \over 4 b c} = 4 a\)

\({4 a b \over b} - {7 a c \over c} = 4 a - 7 a = -3 a\)

\(8 x - {7 \over 6 x} = {8 x \over 1} ⋅ {6 x \over 6 x} - {7 \over 6 x} = {48 x^{2} \over 6 x} - {7 \over 6 x} = {48 x^{2} - 7 \over 6 x}\)

\({4 y \over 2 x} + {8 x \over 5 y} = {20 y^{2} \over 10 x y} + {16 x^{2} \over 10 x y} = {16 x^{2} + 20 y^{2} \over 10 x y} = {8 x^{2} + 10 y^{2} \over 5 x y}\)

\({9 \over a} ⋅ -{6 \over b} = -{54 \over a b}\)

\({a \over 9} ⋅ -{2 \over b} = -{2 a \over 9 b}\)

\(-{5 \over 4} ⋅ p = -{5 p \over 4}\)

\({9 y \over x} ⋅ {x + 5 \over 4} = {9 y (x + 5) \over 4 x} = {9 x y + 45 y \over 4 x}\)

\({8 \over a} : {5 \over b} = {8 \over a} ⋅ {b \over 5} = {8 b \over 5 a}\)

\({6 \over 5} : a = {6 \over 5} : {a \over 1} = {6 \over 5} ⋅ {1 \over a} = {6 \over 5 a}\)

\(-{6 \over 5} : {x + 3 y \over y} = -{6 \over 5} ⋅ {y \over x + 3 y} = -{6 y \over 5 (x + 3 y)} = -{6 y \over 5 x + 15 y}\)

\({5 p \over 6} + {p - 9 \over 7} = {35 p \over 42} + {6 (p - 9) \over 42} = {35 p + 6 (p - 9) \over 42} = {41 p - 54 \over 42}\)

\({-9 p + 3 \over 5 p + 4} + 8 = {-9 p + 3 \over 5 p + 4} + {8 (5 p + 4) \over 5 p + 4} = {-9 p + 3 + 8 (5 p + 4) \over 5 p + 4} = {-9 p + 3 + 40 p + 32 \over 5 p + 4} = {31 p + 35 \over 5 p + 4}\)

\({2 a^{2} - 4 a - 60 \over 2 a} = {2 a^{2} \over 2 a} - {4 a \over 2 a} - {60 \over 2 a} = a - 2 - {30 \over a}\)

\({9 x^{2} + 4 x + 3 \over 2 x^{2}} = {9 x^{2} \over 2 x^{2}} + {4 x \over 2 x^{2}} + {3 \over 2 x^{2}} = 4\frac{1}{2} + {2 \over x} + {3 \over 2 x^{2}}\)