\({6 \over 3x}-{8 \over 3x}=-{2 \over 3x}\)

\({8 \over a}-{4 \over 9a}={72 \over 9a}-{4 \over 9a}={68 \over 9a}\)

\({3 \over 8a}-{4 \over 2b}={3b \over 8ab}-{16a \over 8ab}={3b-16a \over 8ab}\)

\(6-{4 \over 9x}={6 \over 1}-{4 \over 9x}={54x \over 9x}-{4 \over 9x}={54x-4 \over 9x}\)

\({2p \over q}-{3 \over 6q}={12p \over 6q}-{3 \over 6q}={12p-3 \over 6q}={4p-1 \over 2q}\)

\({4a \over a}={4 \over 1}=4\)

\({x \over 2x}={1 \over 2}\)

\({-14a \over 16a}=-\frac{7}{8}\)

\({35p \over 5p}=7\)

\({-14xy \over 18xz}=-{7y \over 9z}\)

\({8y \over 10xy}={4 \over 5x}\)

\({12xyz \over -4yz}=-3x\)

\({2ab \over b}+{7ac \over c}=2a+7a=9a\)

\(8p-{4 \over 5p}={8p \over 1}⋅{5p \over 5p}-{4 \over 5p}={40p^2 \over 5p}-{4 \over 5p}={40p^2-4 \over 5p}\)

\({2b \over 7a}-{5a \over 8b}={16b^2 \over 56ab}-{35a^2 \over 56ab}={-35a^2+16b^2 \over 56ab}\)

\({7 \over x}⋅-{4 \over y}=-{28 \over xy}\)

\({a \over 9}⋅{2 \over b}={2a \over 9b}\)

\({5 \over 4}⋅x={5x \over 4}\)

\({9b \over a}⋅{a+4 \over 8}={9b(a+4) \over 8a}={9ab+36b \over 8a}\)

\({3 \over x}:{9 \over y}={3 \over x}⋅{y \over 9}={3y \over 9x}={y \over 3x}\)

\({4 \over 7}:a={4 \over 7}:{a \over 1}={4 \over 7}⋅{1 \over a}={4 \over 7a}\)

\(-{8 \over 9}:{x-5y \over y}=-{8 \over 9}⋅{y \over x-5y}=-{8y \over 9(x-5y)}=-{8y \over 9x-45y}\)

\({p \over 7}+{p-9 \over 5}={5p \over 35}+{7(p-9) \over 35}={5p+7(p-9) \over 35}={12p-63 \over 35}\)

\({2a+4 \over 6a-1}-7={2a+4 \over 6a-1}-{7(6a-1) \over 6a-1}={2a+4-7(6a-1) \over 6a-1}={2a+4-42a+7 \over 6a-1}={-40a+11 \over 6a-1}\)

\({6p^2-9p+30 \over 3p}={6p^2 \over 3p}-{9p \over 3p}+{30 \over 3p}=2p-3+{10 \over p}\)

\({6a^2+8a+4 \over 5a^2}={6a^2 \over 5a^2}+{8a \over 5a^2}+{4 \over 5a^2}=1\frac{1}{5}+{8 \over 5a}+{4 \over 5a^2}\)