\({5 \over 9 p} + {8 \over 9 p} = {13 \over 9 p}\)

\({7 \over x} - {8 \over 3 x} = {21 \over 3 x} - {8 \over 3 x} = {13 \over 3 x}\)

\({2 \over 8 a} - {6 \over 4 b} = {2 b \over 8 a b} - {12 a \over 8 a b} = {2 b - 12 a \over 8 a b} = {b - 6 a \over 4 a b}\)

\(9 + {3 \over 2 a} = {9 \over 1} + {3 \over 2 a} = {18 a \over 2 a} + {3 \over 2 a} = {18 a + 3 \over 2 a}\)

\({3 x \over y} - {2 \over 6 y} = {18 x \over 6 y} - {2 \over 6 y} = {18 x - 2 \over 6 y} = {9 x - 1 \over 3 y}\)

\({2 a \over a} = {2 \over 1} = 2\)

\({x \over 4 x} = {1 \over 4}\)

\({-32 p \over 36 p} = -\frac{8}{9}\)

\({40 x \over -5 x} = -8\)

\({-6 a b \over 14 a c} = -{3 b \over 7 c}\)

\({-20 y \over -32 x y} = {5 \over 8 x}\)

\({-6 a b c \over -2 b c} = 3 a\)

\({3 a b \over b} + {7 a c \over c} = 3 a + 7 a = 10 a\)

\(2 a + {5 \over 7 a} = {2 a \over 1} ⋅ {7 a \over 7 a} + {5 \over 7 a} = {14 a^{2} \over 7 a} + {5 \over 7 a} = {14 a^{2} + 5 \over 7 a}\)

\({3 b \over 5 a} + {4 a \over 9 b} = {27 b^{2} \over 45 a b} + {20 a^{2} \over 45 a b} = {20 a^{2} + 27 b^{2} \over 45 a b}\)

\({6 \over p} ⋅ {4 \over q} = {24 \over p q}\)

\({x \over 8} ⋅ -{5 \over y} = -{5 x \over 8 y}\)

\(-{7 \over 3} ⋅ x = -{7 x \over 3}\)

\({7 b \over a} ⋅ {a + 9 \over 2} = {7 b (a + 9) \over 2 a} = {7 a b + 63 b \over 2 a}\)

\({5 \over a} : {7 \over b} = {5 \over a} ⋅ {b \over 7} = {5 b \over 7 a}\)

\({9 \over 2} : x = {9 \over 2} : {x \over 1} = {9 \over 2} ⋅ {1 \over x} = {9 \over 2 x}\)

\(-{3 \over 7} : {p - q \over q} = -{3 \over 7} ⋅ {q \over p - q} = -{3 q \over 7 (p - q)} = -{3 q \over 7 p - 7 q}\)

\({x \over 5} + {x + 8 \over 3} = {3 x \over 15} + {5 (x + 8) \over 15} = {3 x + 5 (x + 8) \over 15} = {8 x + 40 \over 15}\)

\({-3 a + 7 \over -6 a + 8} - 4 = {-3 a + 7 \over -6 a + 8} + {-4 (-6 a + 8) \over -6 a + 8} = {-3 a + 7 - 4 (-6 a + 8) \over -6 a + 8} = {-3 a + 7 + 24 a - 32 \over -6 a + 8} = {21 a - 25 \over -6 a + 8}\)

\({2 a^{2} + 6 a - 40 \over 2 a} = {2 a^{2} \over 2 a} + {6 a \over 2 a} - {40 \over 2 a} = a + 3 - {20 \over a}\)

\({3 x^{2} - 4 x - 1 \over 7 x^{2}} = {3 x^{2} \over 7 x^{2}} - {4 x \over 7 x^{2}} - {1 \over 7 x^{2}} = \frac{3}{7} - {4 \over 7 x} - {1 \over 7 x^{2}}\)