\({2 \over 9a}+{8 \over 9a}={10 \over 9a}\)

\({3 \over x}-{2 \over 4x}={12 \over 4x}-{2 \over 4x}={10 \over 4x}={5 \over 2x}\)

\({6 \over 4a}-{9 \over 8b}={12b \over 8ab}-{9a \over 8ab}={12b-9a \over 8ab}\)

\(3+{2 \over 9x}={3 \over 1}+{2 \over 9x}={27x \over 9x}+{2 \over 9x}={27x+2 \over 9x}\)

\({7p \over q}-{2 \over 9q}={63p \over 9q}-{2 \over 9q}={63p-2 \over 9q}\)

\({2p \over p}={2 \over 1}=2\)

\({x \over 5x}={1 \over 5}\)

\({-28a \over -36a}=\frac{7}{9}\)

\({-20a \over 5a}=-4\)

\({-8xy \over 28xz}=-{2y \over 7z}\)

\({25y \over 35xy}={5 \over 7x}\)

\({-27abc \over 3bc}=-9a\)

\({7pq \over q}+{6pr \over r}=7p+6p=13p\)

\(7a-{3 \over 2a}={7a \over 1}⋅{2a \over 2a}-{3 \over 2a}={14a^2 \over 2a}-{3 \over 2a}={14a^2-3 \over 2a}\)

\({2y \over 4x}-{3x \over 8y}={4y^2 \over 8xy}-{3x^2 \over 8xy}={-3x^2+4y^2 \over 8xy}\)

\({3 \over p}⋅{6 \over q}={18 \over pq}\)

\({x \over 3}⋅-{4 \over y}=-{4x \over 3y}\)

\({2 \over 7}⋅a={2a \over 7}\)

\({6y \over x}⋅{x-8 \over 2}={6y(x-8) \over 2x}={3y(x-8) \over x}={3xy-24y \over x}\)

\({3 \over a}:{7 \over b}={3 \over a}⋅{b \over 7}={3b \over 7a}\)

\({5 \over 7}:a={5 \over 7}:{a \over 1}={5 \over 7}⋅{1 \over a}={5 \over 7a}\)

\({3 \over 8}:{p+5q \over q}={3 \over 8}⋅{q \over p+5q}={3q \over 8(p+5q)}={3q \over 8p+40q}\)

\({2x \over 9}+{x-8 \over 7}={14x \over 63}+{9(x-8) \over 63}={14x+9(x-8) \over 63}={23x-72 \over 63}\)

\({4x+3 \over 5x-8}+6={4x+3 \over 5x-8}+{6(5x-8) \over 5x-8}={4x+3+6(5x-8) \over 5x-8}={4x+3+30x-48 \over 5x-8}={34x-45 \over 5x-8}\)

\({6x^2+9x-30 \over 3x}={6x^2 \over 3x}+{9x \over 3x}-{30 \over 3x}=2x+3-{10 \over x}\)

\({6a^2-9a-2 \over 8a^2}={6a^2 \over 8a^2}-{9a \over 8a^2}-{2 \over 8a^2}=\frac{3}{4}-{9 \over 8a}-{1 \over 4a^2}\)