\({7 \over 5 x} - {3 \over 5 x} = {4 \over 5 x}\)

\({4 \over p} + {9 \over 6 p} = {24 \over 6 p} + {9 \over 6 p} = {33 \over 6 p} = {11 \over 2 p}\)

\({3 \over 6 a} - {8 \over 9 b} = {9 b \over 18 a b} - {16 a \over 18 a b} = {9 b - 16 a \over 18 a b}\)

\(5 + {3 \over 4 a} = {5 \over 1} + {3 \over 4 a} = {20 a \over 4 a} + {3 \over 4 a} = {20 a + 3 \over 4 a}\)

\({6 x \over y} + {9 \over 4 y} = {24 x \over 4 y} + {9 \over 4 y} = {24 x + 9 \over 4 y}\)

\({5 p \over p} = {5 \over 1} = 5\)

\({a \over 5 a} = {1 \over 5}\)

\({10 x \over 15 x} = \frac{2}{3}\)

\({-27 a \over -3 a} = 9\)

\({-8 x y \over -12 x z} = {2 y \over 3 z}\)

\({28 q \over 36 p q} = {7 \over 9 p}\)

\({-20 a b c \over -5 b c} = 4 a\)

\({4 x y \over y} + {3 x z \over z} = 4 x + 3 x = 7 x\)

\(9 x - {8 \over 7 x} = {9 x \over 1} ⋅ {7 x \over 7 x} - {8 \over 7 x} = {63 x^{2} \over 7 x} - {8 \over 7 x} = {63 x^{2} - 8 \over 7 x}\)

\({6 b \over 2 a} + {9 a \over 7 b} = {42 b^{2} \over 14 a b} + {18 a^{2} \over 14 a b} = {18 a^{2} + 42 b^{2} \over 14 a b} = {9 a^{2} + 21 b^{2} \over 7 a b}\)

\({5 \over p} ⋅ {8 \over q} = {40 \over p q}\)

\({a \over 3} ⋅ {7 \over b} = {7 a \over 3 b}\)

\({2 \over 3} ⋅ x = {2 x \over 3}\)

\({6 q \over p} ⋅ {p + 8 \over 5} = {6 q (p + 8) \over 5 p} = {6 p q + 48 q \over 5 p}\)

\({8 \over a} : {6 \over b} = {8 \over a} ⋅ {b \over 6} = {8 b \over 6 a} = {4 b \over 3 a}\)

\(-{4 \over 7} : a = -{4 \over 7} : {a \over 1} = -{4 \over 7} ⋅ {1 \over a} = -{4 \over 7 a}\)

\(-{1 \over 4} : {x - 8 y \over y} = -{1 \over 4} ⋅ {y \over x - 8 y} = -{y \over 4 (x - 8 y)} = -{y \over 4 x - 32 y}\)

\({x \over 6} + {x - 4 \over 7} = {7 x \over 42} + {6 (x - 4) \over 42} = {7 x + 6 (x - 4) \over 42} = {13 x - 24 \over 42}\)

\({-5 p - 4 \over -2 p - 1} - 7 = {-5 p - 4 \over -2 p - 1} + {-7 (-2 p - 1) \over -2 p - 1} = {-5 p - 4 - 7 (-2 p - 1) \over -2 p - 1} = {-5 p - 4 + 14 p + 7 \over -2 p - 1} = {9 p + 3 \over -2 p - 1}\)

\({2 x^{2} - x + 30 \over x} = {2 x^{2} \over x} - {x \over x} + {30 \over x} = 2 x - 1 + {30 \over x}\)

\({5 x^{2} - 8 x + 9 \over 4 x^{2}} = {5 x^{2} \over 4 x^{2}} - {8 x \over 4 x^{2}} + {9 \over 4 x^{2}} = 1\frac{1}{4} - {2 \over x} + {9 \over 4 x^{2}}\)