\({3 \over 8x}-{5 \over 8x}=-{2 \over 8x}=-{1 \over 4x}\)

\({2 \over x}-{9 \over 4x}={8 \over 4x}-{9 \over 4x}=-{1 \over 4x}\)

\({6 \over 8p}-{9 \over 2q}={6q \over 8pq}-{36p \over 8pq}={6q-36p \over 8pq}={3q-18p \over 4pq}\)

\(8+{2 \over 9a}={8 \over 1}+{2 \over 9a}={72a \over 9a}+{2 \over 9a}={72a+2 \over 9a}\)

\({8a \over b}-{3 \over 5b}={40a \over 5b}-{3 \over 5b}={40a-3 \over 5b}\)

\({6p \over p}={6 \over 1}=6\)

\({a \over 8a}={1 \over 8}\)

\({-20x \over -36x}=\frac{5}{9}\)

\({-15a \over -5a}=3\)

\({12xy \over -16xz}=-{3y \over 4z}\)

\({-8q \over -28pq}={2 \over 7p}\)

\({-12xyz \over -2yz}=6x\)

\({4ab \over b}-{3ac \over c}=4a-3a=a\)

\(2x-{7 \over 6x}={2x \over 1}⋅{6x \over 6x}-{7 \over 6x}={12x^2 \over 6x}-{7 \over 6x}={12x^2-7 \over 6x}\)

\({6b \over 2a}-{9a \over 3b}={18b^2 \over 6ab}-{18a^2 \over 6ab}={-18a^2+18b^2 \over 6ab}={-3a^2+3b^2 \over ab}\)

\({9 \over a}⋅{8 \over b}={72 \over ab}\)

\({p \over 8}⋅-{9 \over q}=-{9p \over 8q}\)

\({7 \over 9}⋅x={7x \over 9}\)

\({8y \over x}⋅{x-6 \over 3}={8y(x-6) \over 3x}={8xy-48y \over 3x}\)

\({3 \over a}:{9 \over b}={3 \over a}⋅{b \over 9}={3b \over 9a}={b \over 3a}\)

\(-{8 \over 9}:a=-{8 \over 9}:{a \over 1}=-{8 \over 9}⋅{1 \over a}=-{8 \over 9a}\)

\({6 \over 7}:{x-2y \over y}={6 \over 7}⋅{y \over x-2y}={6y \over 7(x-2y)}={6y \over 7x-14y}\)

\({9p \over 8}+{p-3 \over 7}={63p \over 56}+{8(p-3) \over 56}={63p+8(p-3) \over 56}={71p-24 \over 56}\)

\({3x+7 \over -9x+6}+8={3x+7 \over -9x+6}-{-8(-9x+6) \over -9x+6}={3x+7+8(-9x+6) \over -9x+6}={3x+7-72x+48 \over -9x+6}={-69x+55 \over -9x+6}\)

\({p^2-3p-20 \over p}={p^2 \over p}-{3p \over p}-{20 \over p}=p-3-{20 \over p}\)

\({a^2+2a-8 \over 4a^2}={a^2 \over 4a^2}+{2a \over 4a^2}-{8 \over 4a^2}=\frac{1}{4}+{1 \over 2a}-{2 \over a^2}\)