\({7 \over 8x}-{3 \over 8x}={4 \over 8x}={1 \over 2x}\)

\({7 \over x}-{5 \over 4x}={28 \over 4x}-{5 \over 4x}={23 \over 4x}\)

\({6 \over 2a}-{4 \over 9b}={54b \over 18ab}-{8a \over 18ab}={54b-8a \over 18ab}={27b-4a \over 9ab}\)

\(8-{7 \over 2p}={8 \over 1}-{7 \over 2p}={16p \over 2p}-{7 \over 2p}={16p-7 \over 2p}\)

\({7a \over b}+{4 \over 3b}={21a \over 3b}+{4 \over 3b}={21a+4 \over 3b}\)

\({3a \over a}={3 \over 1}=3\)

\({x \over 5x}={1 \over 5}\)

\({-12x \over 27x}=-\frac{4}{9}\)

\({-14p \over 2p}=-7\)

\({8ab \over 14ac}={4b \over 7c}\)

\({8b \over -10ab}=-{4 \over 5a}\)

\({36xyz \over 4yz}=9x\)

\({4ab \over b}+{2ac \over c}=4a+2a=6a\)

\(8a-{5 \over 2a}={8a \over 1}⋅{2a \over 2a}-{5 \over 2a}={16a^2 \over 2a}-{5 \over 2a}={16a^2-5 \over 2a}\)

\({7b \over 3a}-{6a \over 8b}={56b^2 \over 24ab}-{18a^2 \over 24ab}={-18a^2+56b^2 \over 24ab}={-9a^2+28b^2 \over 12ab}\)

\({7 \over x}⋅{6 \over y}={42 \over xy}\)

\({p \over 7}⋅-{4 \over q}=-{4p \over 7q}\)

\({1 \over 9}⋅x={x \over 9}\)

\({3b \over a}⋅{a+6 \over 2}={3b(a+6) \over 2a}={3ab+18b \over 2a}\)

\({8 \over p}:{6 \over q}={8 \over p}⋅{q \over 6}={8q \over 6p}={4q \over 3p}\)

\({8 \over 9}:a={8 \over 9}:{a \over 1}={8 \over 9}⋅{1 \over a}={8 \over 9a}\)

\(-{9 \over 5}:{x+4y \over y}=-{9 \over 5}⋅{y \over x+4y}=-{9y \over 5(x+4y)}=-{9y \over 5x+20y}\)

\({7x \over 9}+{x+2 \over 5}={35x \over 45}+{9(x+2) \over 45}={35x+9(x+2) \over 45}={44x+18 \over 45}\)

\({7a+6 \over 3a-5}+8={7a+6 \over 3a-5}+{8(3a-5) \over 3a-5}={7a+6+8(3a-5) \over 3a-5}={7a+6+24a-40 \over 3a-5}={31a-34 \over 3a-5}\)

\({x^2+3x+20 \over x}={x^2 \over x}+{3x \over x}+{20 \over x}=x+3+{20 \over x}\)

\({9a^2-4a-5 \over 2a^2}={9a^2 \over 2a^2}-{4a \over 2a^2}-{5 \over 2a^2}=4\frac{1}{2}-{2 \over a}-{5 \over 2a^2}\)