\({8 \over 5x}+{3 \over 5x}={11 \over 5x}\)

\({6 \over x}-{7 \over 3x}={18 \over 3x}-{7 \over 3x}={11 \over 3x}\)

\({3 \over 8a}-{4 \over 6b}={9b \over 24ab}-{16a \over 24ab}={9b-16a \over 24ab}\)

\(6+{9 \over 7p}={6 \over 1}+{9 \over 7p}={42p \over 7p}+{9 \over 7p}={42p+9 \over 7p}\)

\({9a \over b}-{4 \over 8b}={72a \over 8b}-{4 \over 8b}={72a-4 \over 8b}={18a-1 \over 2b}\)

\({8x \over x}={8 \over 1}=8\)

\({p \over 8p}={1 \over 8}\)

\({-24a \over -28a}=\frac{6}{7}\)

\({40x \over -5x}=-8\)

\({12ab \over 20ac}={3b \over 5c}\)

\({-8b \over -28ab}={2 \over 7a}\)

\({-24pqr \over -4qr}=6p\)

\({3ab \over b}+{4ac \over c}=3a+4a=7a\)

\(5x-{4 \over 7x}={5x \over 1}⋅{7x \over 7x}-{4 \over 7x}={35x^2 \over 7x}-{4 \over 7x}={35x^2-4 \over 7x}\)

\({4q \over 6p}-{3p \over 8q}={16q^2 \over 24pq}-{9p^2 \over 24pq}={-9p^2+16q^2 \over 24pq}\)

\({6 \over a}⋅-{2 \over b}=-{12 \over ab}\)

\({a \over 7}⋅{4 \over b}={4a \over 7b}\)

\({5 \over 6}⋅x={5x \over 6}\)

\({4y \over x}⋅{x+8 \over 2}={4y(x+8) \over 2x}={2y(x+8) \over x}={2xy+16y \over x}\)

\({7 \over p}:{4 \over q}={7 \over p}⋅{q \over 4}={7q \over 4p}\)

\(-{6 \over 5}:a=-{6 \over 5}:{a \over 1}=-{6 \over 5}⋅{1 \over a}=-{6 \over 5a}\)

\(-{5 \over 7}:{a-9b \over b}=-{5 \over 7}⋅{b \over a-9b}=-{5b \over 7(a-9b)}=-{5b \over 7a-63b}\)

\({6x \over 7}+{x-8 \over 5}={30x \over 35}+{7(x-8) \over 35}={30x+7(x-8) \over 35}={37x-56 \over 35}\)

\({-2a-1 \over -8a+9}-3={-2a-1 \over -8a+9}+{-3(-8a+9) \over -8a+9}={-2a-1-3(-8a+9) \over -8a+9}={-2a-1+24a-27 \over -8a+9}={22a-28 \over -8a+9}\)

\({2x^2+3x+10 \over x}={2x^2 \over x}+{3x \over x}+{10 \over x}=2x+3+{10 \over x}\)

\({9p^2-p-8 \over 7p^2}={9p^2 \over 7p^2}-{p \over 7p^2}-{8 \over 7p^2}=1\frac{2}{7}-{1 \over 7p}-{8 \over 7p^2}\)