Getal & Ruimte (13e editie) - havo wiskunde A
'Breuken herleiden'.
| 2 havo/vwo | 1.2 Breuken optellen |
opgave 1Herleid tot één breuk. 1p a \({3 \over 5 a} - {2 \over 5 a}\) Optellen (1) 008u - Breuken herleiden - basis - 0ms - dynamic variables a \({3 \over 5 a} - {2 \over 5 a} = {1 \over 5 a}\) 1p 1p b \({9 \over a} + {3 \over 4 a}\) Optellen (2) 008v - Breuken herleiden - basis - 0ms - dynamic variables b \({9 \over a} + {3 \over 4 a} = {36 \over 4 a} + {3 \over 4 a} = {39 \over 4 a}\) 1p 1p c \({4 \over 7 x} + {2 \over 6 y}\) Optellen (3) 008w - Breuken herleiden - basis - 0ms - dynamic variables c \({4 \over 7 x} + {2 \over 6 y} = {24 y \over 42 x y} + {14 x \over 42 x y} = {24 y + 14 x \over 42 x y} = {12 y + 7 x \over 21 x y}\) 1p 1p d \(9 - {4 \over 7 x}\) Optellen (4) 008x - Breuken herleiden - basis - 0ms - dynamic variables d \(9 - {4 \over 7 x} = {9 \over 1} - {4 \over 7 x} = {63 x \over 7 x} - {4 \over 7 x} = {63 x - 4 \over 7 x}\) 1p opgave 2Herleid tot één breuk. 1p a \(3 p - {7 \over 8 p}\) Optellen (5) 008y - Breuken herleiden - basis - 0ms - dynamic variables a \(3 p - {7 \over 8 p} = {3 p \over 1} ⋅ {8 p \over 8 p} - {7 \over 8 p} = {24 p^{2} \over 8 p} - {7 \over 8 p} = {24 p^{2} - 7 \over 8 p}\) 1p 1p b \({3 p \over q} + {7 \over 5 q}\) Optellen (6) 008z - Breuken herleiden - basis - 0ms - dynamic variables b \({3 p \over q} + {7 \over 5 q} = {15 p \over 5 q} + {7 \over 5 q} = {15 p + 7 \over 5 q}\) 1p 1p c \({3 b \over 9 a} - {5 a \over 4 b}\) Optellen (7) 0090 - Breuken herleiden - basis - 0ms - dynamic variables c \({3 b \over 9 a} - {5 a \over 4 b} = {12 b^{2} \over 36 a b} - {45 a^{2} \over 36 a b} = {-45 a^{2} + 12 b^{2} \over 36 a b} = {-15 a^{2} + 4 b^{2} \over 12 a b}\) 1p opgave 3Herleid. 1p a \({5 x \over x}\) Vereenvoudigen (1) 00h5 - Breuken herleiden - basis - 0ms - dynamic variables a \({5 x \over x} = {5 \over 1} = 5\) 1p 1p b \({a \over 6 a}\) Vereenvoudigen (2) 00h6 - Breuken herleiden - basis - 0ms - dynamic variables b \({a \over 6 a} = {1 \over 6}\) 1p 1p c \({-8 x \over 28 x}\) Vereenvoudigen (3) 00h7 - Breuken herleiden - basis - 0ms - dynamic variables c \({-8 x \over 28 x} = -\frac{2}{7}\) 1p 1p d \({-16 a \over 2 a}\) Vereenvoudigen (4) 00h8 - Breuken herleiden - basis - 0ms - dynamic variables d \({-16 a \over 2 a} = -8\) 1p opgave 4Herleid. 1p a \({18 x y \over 21 x z}\) Vereenvoudigen (5) 00h9 - Breuken herleiden - basis - 0ms - dynamic variables a \({18 x y \over 21 x z} = {6 y \over 7 z}\) 1p 1p b \({-18 q \over 21 p q}\) Vereenvoudigen (6) 00ha - Breuken herleiden - basis - 0ms - dynamic variables b \({-18 q \over 21 p q} = -{6 \over 7 p}\) 1p 1p c \({8 x y z \over 4 y z}\) Vereenvoudigen (7) 00hb - Breuken herleiden - basis - 0ms - dynamic variables c \({8 x y z \over 4 y z} = 2 x\) 1p 1p d \({3 a b \over b} + {2 a c \over c}\) Vereenvoudigen (8) 00hc - Breuken herleiden - basis - 0ms - dynamic variables d \({3 a b \over b} + {2 a c \over c} = 3 a + 2 a = 5 a\) 1p |
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| 2 havo/vwo | 1.3 Breuken vermenigvuldigen en delen |
opgave 1Herleid tot één breuk. 1p a \({9 \over x} ⋅ {4 \over y}\) Vermenigvuldiging (1) 0091 - Breuken herleiden - basis - 0ms - dynamic variables a \({9 \over x} ⋅ {4 \over y} = {36 \over x y}\) 1p 1p b \({x \over 9} ⋅ -{7 \over y}\) Vermenigvuldiging (2) 0092 - Breuken herleiden - basis - 0ms - dynamic variables b \({x \over 9} ⋅ -{7 \over y} = -{7 x \over 9 y}\) 1p 1p c \(-{2 \over 9} ⋅ p\) Vermenigvuldiging (3) 0093 - Breuken herleiden - basis - 0ms - dynamic variables c \(-{2 \over 9} ⋅ p = -{2 p \over 9}\) 1p 1p d \({3 \over a} : {9 \over b}\) Deling (1) 0095 - Breuken herleiden - basis - 0ms - dynamic variables d \({3 \over a} : {9 \over b} = {3 \over a} ⋅ {b \over 9} = {3 b \over 9 a} = {b \over 3 a}\) 1p opgave 2Herleid tot één breuk. 1p \({6 \over 7} : a\) Deling (2) 0096 - Breuken herleiden - basis - 0ms - dynamic variables ○ \({6 \over 7} : a = {6 \over 7} : {a \over 1} = {6 \over 7} ⋅ {1 \over a} = {6 \over 7 a}\) 1p |
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| 3 havo | 5.2 Breuken met letters herleiden |
opgave 1Herleid tot één breuk. 1p \({8 a \over 9} + {a + 6 \over 2}\) Optellen (8) 0098 - Breuken herleiden - basis - 0ms - dynamic variables ○ \({8 a \over 9} + {a + 6 \over 2} = {16 a \over 18} + {9 (a + 6) \over 18} = {16 a + 9 (a + 6) \over 18} = {25 a + 54 \over 18}\) 1p |
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| havo wiskunde A | 6.2 Formules met breuken |
opgave 1Herleid tot één breuk. 1p a \(-{2 \over 9} : {p + 3 q \over q}\) Deling (3) 0097 - Breuken herleiden - basis - 0ms - dynamic variables a \(-{2 \over 9} : {p + 3 q \over q} = -{2 \over 9} ⋅ {q \over p + 3 q} = -{2 q \over 9 (p + 3 q)} = -{2 q \over 9 p + 27 q}\) 1p 1p b \({2 a - 4 \over -3 a - 9} + 6\) Optellen (9) 00eh - Breuken herleiden - basis - 1ms - dynamic variables b \({2 a - 4 \over -3 a - 9} + 6 = {2 a - 4 \over -3 a - 9} - {-6 (-3 a - 9) \over -3 a - 9} = {2 a - 4 + 6 (-3 a - 9) \over -3 a - 9} = {2 a - 4 - 18 a - 54 \over -3 a - 9} = {-16 a - 58 \over -3 a - 9}\) 1p |