Getal & Ruimte (13e editie) - 3 vwo
'Wortels vereenvoudigen'.
| 2 vwo | 5.3 Wortels herleiden |
opgave 1Herleid. 2p a \(\sqrt{12}+\sqrt{48}\) Optellen (5) 0085 - Wortels vereenvoudigen - basis - 0ms a \(\sqrt{12}+\sqrt{48}=\sqrt{4}⋅\sqrt{3}+\sqrt{16}⋅\sqrt{3}=2\sqrt{3}+4\sqrt{3}\text{.}\) 1p ○ \(2\sqrt{3}+4\sqrt{3}=6\sqrt{3}\text{.}\) 1p 1p b \(\sqrt{50}\) FactorVoorWortelteken (1) 0086 - Wortels vereenvoudigen - basis - 0ms b \(\sqrt{50}=\sqrt{25}⋅\sqrt{2}=5\sqrt{2}\text{.}\) 1p 1p c \(-4\sqrt{20}\) FactorVoorWortelteken (2) 0087 - Wortels vereenvoudigen - basis - 0ms c \(-4\sqrt{20}=-4⋅\sqrt{4}⋅\sqrt{5}=-4⋅2⋅\sqrt{5}=-8\sqrt{5}\text{.}\) 1p 2p d \(5\sqrt{18}+3\sqrt{32}\) Optellen (6) 0088 - Wortels vereenvoudigen - basis - 1ms d \(5\sqrt{18}+3\sqrt{32}=5⋅\sqrt{9}⋅\sqrt{2}+3⋅\sqrt{16}⋅\sqrt{2}\text{.}\) 1p ○ \(5⋅3⋅\sqrt{2}+3⋅4⋅\sqrt{2}=15\sqrt{2}+12\sqrt{2}=27\sqrt{2}\text{.}\) 1p opgave 2Herleid. 1p \(\sqrt{20\frac{1}{4}}\) BreukInWortel (1) 008b - Wortels vereenvoudigen - basis - 68ms ○ \(\sqrt{20\frac{1}{4}}=\sqrt{\frac{81}{4}}={\sqrt{81} \over \sqrt{4}}=\frac{9}{2}=4\frac{1}{2}\text{.}\) 1p |
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| 3 vwo | 5.5 Wortels herleiden |
opgave 1Herleid. 1p a \({9 \over 4\sqrt{5}}\) WortelInNoemer 0089 - Wortels vereenvoudigen - basis - 1ms a \({9 \over 4\sqrt{5}}={9 \over 4\sqrt{5}}⋅{\sqrt{5} \over \sqrt{5}}={9\sqrt{5} \over 4⋅5}=\frac{9}{20}\sqrt{5}\text{.}\) 1p 1p b \(\sqrt{\frac{21}{64}}\) BreukInWortel (2) 008c - Wortels vereenvoudigen - basis - 1ms b \(\sqrt{\frac{21}{64}}={\sqrt{21} \over \sqrt{64}}={\sqrt{21} \over 8}=\frac{1}{8}\sqrt{21}\text{.}\) 1p 1p c \(\sqrt{1\frac{1}{48}}\) BreukInWortel (3) 008d - Wortels vereenvoudigen - basis - 1ms c \(\sqrt{1\frac{1}{48}}=\sqrt{\frac{49}{48}}={\sqrt{49} \over \sqrt{48}}={7 \over \sqrt{48}}⋅{\sqrt{48} \over \sqrt{48}}={7\sqrt{48} \over 48}=\frac{7}{48}\sqrt{48}=\frac{7}{48}⋅4⋅\sqrt{3}=\frac{7}{12}\sqrt{3}\text{.}\) 1p 1p d \(\sqrt{\frac{2}{23}}\) BreukInWortel (4) 008e - Wortels vereenvoudigen - basis - 1ms d \(\sqrt{\frac{2}{23}}={\sqrt{2} \over \sqrt{23}}⋅{\sqrt{23} \over \sqrt{23}}={\sqrt{46} \over 23}=\frac{1}{23}\sqrt{46}\text{.}\) 1p opgave 2Herleid. 1p a \({30\sqrt{192} \over 6\sqrt{8}}\) Delen (4) 00dc - Wortels vereenvoudigen - basis - 10ms a \({30\sqrt{192} \over 6\sqrt{8}}={30 \over 6}⋅{\sqrt{192} \over \sqrt{8}}=5\sqrt{24}=5⋅\sqrt{4}⋅\sqrt{6}=5⋅2⋅\sqrt{6}=10\sqrt{6}\) 1p 1p b \(2\sqrt{10}⋅5\sqrt{5}\) Vermenigvuldigen (5) 00dd - Wortels vereenvoudigen - basis - 3ms - data pool: #22 (3ms) b \(2\sqrt{10}⋅5\sqrt{5}=10\sqrt{50}=10⋅\sqrt{25}⋅\sqrt{2}=10⋅5⋅\sqrt{2}=50\sqrt{2}\) 1p |