Getal & Ruimte (13e editie) - 3 vwo
'Ontbinden in factoren'.
| 2 vwo | 7.1 Buiten haakjes brengen |
opgave 1Ontbind in factoren. 1p a \(a^{2} + 3 a\) BuitenHaakjes (1) 00hd - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} + 3 a = a (a + 3)\) 1p 1p b \(4 x^{2} + 7 x\) BuitenHaakjes (2) 00he - Ontbinden in factoren - basis - 0ms - dynamic variables b \(4 x^{2} + 7 x = x (4 x + 7)\) 1p 1p c \(16 a b + 36 a\) BuitenHaakjes (3) 00hf - Ontbinden in factoren - basis - 0ms - dynamic variables c \(16 a b + 36 a = 4 a (4 b + 9)\) 1p 1p d \(10 x y + 15 x z\) BuitenHaakjes (4) 00hg - Ontbinden in factoren - basis - 0ms - dynamic variables d \(10 x y + 15 x z = 5 x (2 y + 3 z)\) 1p opgave 2Ontbind in factoren. 1p a \(10 p q r + 14 p q\) BuitenHaakjes (5) 00hh - Ontbinden in factoren - basis - 0ms - dynamic variables a \(10 p q r + 14 p q = 2 p q (5 r + 7)\) 1p 1p b \(15 p^{4} + 24 p^{5}\) BuitenHaakjes (6) 00hi - Ontbinden in factoren - basis - 0ms - dynamic variables b \(15 p^{4} + 24 p^{5} = 3 p^{4} (5 + 8 p)\) 1p 1p c \(4 x + 7 x^{3} + x^{8}\) BuitenHaakjes (7) 00hj - Ontbinden in factoren - basis - 0ms - dynamic variables c \(4 x + 7 x^{3} + x^{8} = x (4 + 7 x^{2} + x^{7})\) 1p 1p d \(12 a^{2} b^{2} + 32 a^{5} b^{4}\) BuitenHaakjes (8) 00hk - Ontbinden in factoren - basis - 0ms - dynamic variables d \(12 a^{2} b^{2} + 32 a^{5} b^{4} = 4 a^{2} b^{2} (3 + 8 a^{3} b^{2})\) 1p opgave 3Ontbind in factoren. 1p a \(x^{2} - 121\) Verschil2Kwadraten (1) 00hl - Ontbinden in factoren - basis - 0ms - dynamic variables a \(x^{2} - 121 = (x - 11) (x + 11)\) 1p 1p b \(25 a^{2} - 9\) Verschil2Kwadraten (2) 00hm - Ontbinden in factoren - basis - 0ms - dynamic variables b \(25 a^{2} - 9 = (5 a - 3) (5 a + 3)\) 1p 1p c \(9 - 64 x^{2}\) Verschil2Kwadraten (3) 00hs - Ontbinden in factoren - basis - 0ms - dynamic variables c \(9 - 64 x^{2} = (3 - 8 x) (3 + 8 x)\) 1p 1p d \(81 x^{12} - 49\) Verschil2Kwadraten (4) 00ht - Ontbinden in factoren - basis - 0ms - dynamic variables d \(81 x^{12} - 49 = (9 x^{6} - 7) (9 x^{6} + 7)\) 1p opgave 4Ontbind in factoren. 1p a \(75 p^{2} - 3\) Verschil2Kwadraten (5) 00hu - Ontbinden in factoren - basis - 0ms - dynamic variables a \(75 p^{2} - 3 = 3 (25 p^{2} - 1) = 3 (5 p - 1) (5 p + 1)\) 1p 1p b \(75 a^{5} - 48 a^{3}\) Verschil2Kwadraten (6) 00hv - Ontbinden in factoren - basis - 0ms - dynamic variables b \(75 a^{5} - 48 a^{3} = 3 a^{3} (25 a^{2} - 16) = 3 a^{3} (5 a - 4) (5 a + 4)\) 1p 1p c \(a^{4} - 16\) Verschil2Kwadraten (7) 00hw - Ontbinden in factoren - basis - 0ms - dynamic variables c \(a^{4} - 16 = (a^{2} - 4) (a^{2} + 4) = (a - 2) (a + 2) (a^{2} + 4)\) 1p 1p d \(p^{6} - 81 p^{2}\) Verschil2Kwadraten (8) 00hx - Ontbinden in factoren - basis - 0ms - dynamic variables d \(p^{6} - 81 p^{2} = p^{2} (p^{4} - 81) = p^{2} (p^{2} - 9) (p^{2} + 9) = p^{2} (p - 3) (p + 3) (p^{2} + 9)\) 1p opgave 5Ontbind in factoren. 1p \(a^{10} b^{12} - 81 c^{12}\) Verschil2Kwadraten (9) 00hz - Ontbinden in factoren - basis - 0ms - dynamic variables ○ \(a^{10} b^{12} - 81 c^{12} = (a^{5} b^{6} - 9 c^{6}) (a^{5} b^{6} + 9 c^{6})\) 1p |
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| 2 vwo | 7.2 De product-som methode |
opgave 1Ontbind in factoren. 1p a \(p^{2} + 9 p + 14\) SomProductmethode (1) 00hn - Ontbinden in factoren - basis - 0ms - dynamic variables a \(p^{2} + 9 p + 14 = (p + 7) (p + 2)\) 1p 1p b \(a^{2} + 2 a - 24\) SomProductmethode (2) 00ho - Ontbinden in factoren - basis - 0ms - dynamic variables b \(a^{2} + 2 a - 24 = (a + 6) (a - 4)\) 1p 1p c \(x^{2} - 10 x + 24\) SomProductmethode (3) 00hp - Ontbinden in factoren - basis - 0ms - dynamic variables c \(x^{2} - 10 x + 24 = (x - 4) (x - 6)\) 1p 1p d \(x^{2} - 14 x + 49\) SomProductmethode (4) 00hq - Ontbinden in factoren - basis - 0ms - dynamic variables d \(x^{2} - 14 x + 49 = (x - 7) (x - 7)\) 1p opgave 2Ontbind in factoren. 1p a \(2 a^{5} - 28 a^{4} + 90 a^{3}\) SomProductmethode (5) 00hr - Ontbinden in factoren - basis - 0ms - dynamic variables a \(2 a^{5} - 28 a^{4} + 90 a^{3} = 2 a^{3} (a^{2} - 14 a + 45) = 2 a^{3} (a - 9) (a - 5)\) 1p 1p b \(x^{6} - x^{3} - 30\) SomProductmethode (6) 00hy - Ontbinden in factoren - basis - 0ms - dynamic variables b \(x^{6} - x^{3} - 30 = (x^{3} - 6) (x^{3} + 5)\) 1p |
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| 3 vwo | 5.2 Kwadraatafsplitsen |
opgave 1Splits het kwadraat af. 1p a \(x^{2} + x\) KwadraatAfsplitsen (1) 00r8 - Ontbinden in factoren - basis - 0ms a \(x^{2} + x = (x + \frac{1}{2})^{2} - \frac{1}{4}\) 1p 2p b \(x^{2} + 2 x - 16\) KwadraatAfsplitsen (2) 00r9 - Ontbinden in factoren - basis - 0ms b \(x^{2} + 2 x - 16 = (x + 1)^{2} - 1 - 16\) 1p ○ \(\text{} = (x + 1)^{2} - 17\) 1p 3p c \(3 x^{2} + 6 x - 13\) KwadraatAfsplitsen (3) 00ra - Ontbinden in factoren - basis - 0ms c \(3 x^{2} + 6 x - 13 = 3 (x^{2} + 2 x) - 13\) 1p ○ \(\text{} = 3 ((x + 1)^{2} - 1) - 13\) 1p ○ \(\text{} = 3 (x + 1)^{2} - 3 - 13\) 1p |