Getal & Ruimte (13e editie) - 3 vwo
'Ontbinden in factoren'.
| 2 vwo | 7.1 Buiten haakjes brengen |
opgave 1Ontbind in factoren. 1p a \(p^{2} + p\) BuitenHaakjes (1) 00hd - Ontbinden in factoren - basis - 0ms - dynamic variables a \(p^{2} + p = p (p + 1)\) 1p 1p b \(25 x^{2} - 40 x\) BuitenHaakjes (2) 00he - Ontbinden in factoren - basis - 0ms - dynamic variables b \(25 x^{2} - 40 x = 5 x (5 x - 8)\) 1p 1p c \(8 a b + 20 a\) BuitenHaakjes (3) 00hf - Ontbinden in factoren - basis - 0ms - dynamic variables c \(8 a b + 20 a = 4 a (2 b + 5)\) 1p 1p d \(10 x y + 15 x z\) BuitenHaakjes (4) 00hg - Ontbinden in factoren - basis - 0ms - dynamic variables d \(10 x y + 15 x z = 5 x (2 y + 3 z)\) 1p opgave 2Ontbind in factoren. 1p a \(10 a b c + 15 a b\) BuitenHaakjes (5) 00hh - Ontbinden in factoren - basis - 0ms - dynamic variables a \(10 a b c + 15 a b = 5 a b (2 c + 3)\) 1p 1p b \(20 a^{2} + 45 a^{3}\) BuitenHaakjes (6) 00hi - Ontbinden in factoren - basis - 0ms - dynamic variables b \(20 a^{2} + 45 a^{3} = 5 a^{2} (4 + 9 a)\) 1p 1p c \(2 x^{3} + 9 x^{4} + x^{5}\) BuitenHaakjes (7) 00hj - Ontbinden in factoren - basis - 0ms - dynamic variables c \(2 x^{3} + 9 x^{4} + x^{5} = x^{3} (2 + 9 x + x^{2})\) 1p 1p d \(10 a^{4} b^{3} + 16 a^{2} b^{4}\) BuitenHaakjes (8) 00hk - Ontbinden in factoren - basis - 0ms - dynamic variables d \(10 a^{4} b^{3} + 16 a^{2} b^{4} = 2 a^{2} b^{3} (5 a^{2} + 8 b)\) 1p opgave 3Ontbind in factoren. 1p a \(x^{2} - 64\) Verschil2Kwadraten (1) 00hl - Ontbinden in factoren - basis - 0ms - dynamic variables a \(x^{2} - 64 = (x - 8) (x + 8)\) 1p 1p b \(36 p^{2} - 25\) Verschil2Kwadraten (2) 00hm - Ontbinden in factoren - basis - 1ms - dynamic variables b \(36 p^{2} - 25 = (6 p - 5) (6 p + 5)\) 1p 1p c \(25 - 81 x^{2}\) Verschil2Kwadraten (3) 00hs - Ontbinden in factoren - basis - 1ms - dynamic variables c \(25 - 81 x^{2} = (5 - 9 x) (5 + 9 x)\) 1p 1p d \(81 a^{4} - 121\) Verschil2Kwadraten (4) 00ht - Ontbinden in factoren - basis - 1ms - dynamic variables d \(81 a^{4} - 121 = (9 a^{2} - 11) (9 a^{2} + 11)\) 1p opgave 4Ontbind in factoren. 1p a \(50 p^{2} - 18\) Verschil2Kwadraten (5) 00hu - Ontbinden in factoren - basis - 1ms - dynamic variables a \(50 p^{2} - 18 = 2 (25 p^{2} - 9) = 2 (5 p - 3) (5 p + 3)\) 1p 1p b \(3 x^{3} - 48 x\) Verschil2Kwadraten (6) 00hv - Ontbinden in factoren - basis - 1ms - dynamic variables b \(3 x^{3} - 48 x = 3 x (x^{2} - 16) = 3 x (x - 4) (x + 4)\) 1p 1p c \(a^{4} - 16\) Verschil2Kwadraten (7) 00hw - Ontbinden in factoren - basis - 0ms - dynamic variables c \(a^{4} - 16 = (a^{2} - 4) (a^{2} + 4) = (a - 2) (a + 2) (a^{2} + 4)\) 1p 1p d \(2 a^{7} - 32 a^{3}\) Verschil2Kwadraten (8) 00hx - Ontbinden in factoren - basis - 1ms - dynamic variables d \(2 a^{7} - 32 a^{3} = 2 a^{3} (a^{4} - 16) = 2 a^{3} (a^{2} - 4) (a^{2} + 4) = 2 a^{3} (a - 2) (a + 2) (a^{2} + 4)\) 1p opgave 5Ontbind in factoren. 1p \(p^{12} q^{2} - r^{6}\) Verschil2Kwadraten (9) 00hz - Ontbinden in factoren - basis - 0ms - dynamic variables ○ \(p^{12} q^{2} - r^{6} = (p^{6} q - r^{3}) (p^{6} q + r^{3})\) 1p |
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| 2 vwo | 7.2 De product-som methode |
opgave 1Ontbind in factoren. 1p a \(a^{2} + 5 a + 4\) SomProductmethode (1) 00hn - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} + 5 a + 4 = (a + 1) (a + 4)\) 1p 1p b \(x^{2} + 7 x - 8\) SomProductmethode (2) 00ho - Ontbinden in factoren - basis - 0ms - dynamic variables b \(x^{2} + 7 x - 8 = (x + 8) (x - 1)\) 1p 1p c \(x^{2} - 11 x + 18\) SomProductmethode (3) 00hp - Ontbinden in factoren - basis - 0ms - dynamic variables c \(x^{2} - 11 x + 18 = (x - 9) (x - 2)\) 1p 1p d \(a^{2} - 6 a + 9\) SomProductmethode (4) 00hq - Ontbinden in factoren - basis - 0ms - dynamic variables d \(a^{2} - 6 a + 9 = (a - 3) (a - 3)\) 1p opgave 2Ontbind in factoren. 1p a \(2 p^{5} - 10 p^{4} + 12 p^{3}\) SomProductmethode (5) 00hr - Ontbinden in factoren - basis - 1ms - dynamic variables a \(2 p^{5} - 10 p^{4} + 12 p^{3} = 2 p^{3} (p^{2} - 5 p + 6) = 2 p^{3} (p - 3) (p - 2)\) 1p 1p b \(x^{4} + 11 x^{2} + 24\) SomProductmethode (6) 00hy - Ontbinden in factoren - basis - 0ms - dynamic variables b \(x^{4} + 11 x^{2} + 24 = (x^{2} + 8) (x^{2} + 3)\) 1p |
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| 3 vwo | 5.2 Kwadraatafsplitsen |
opgave 1Splits het kwadraat af. 1p a \(x^{2} - 11 x\) KwadraatAfsplitsen (1) 00r8 - Ontbinden in factoren - basis - 0ms a \(x^{2} - 11 x = (x - 5\frac{1}{2})^{2} - 30\frac{1}{4}\) 1p 2p b \(x^{2} - x + 19\) KwadraatAfsplitsen (2) 00r9 - Ontbinden in factoren - basis - 0ms b \(x^{2} - x + 19 = (x - \frac{1}{2})^{2} - \frac{1}{4} + 19\) 1p ○ \(\text{} = (x - \frac{1}{2})^{2} + 18\frac{3}{4}\) 1p 3p c \(-2 x^{2} + 2 x - 7\) KwadraatAfsplitsen (3) 00ra - Ontbinden in factoren - basis - 0ms c \(-2 x^{2} + 2 x - 7 = -2 (x^{2} - x) - 7\) 1p ○ \(\text{} = -2 ((x - \frac{1}{2})^{2} - \frac{1}{4}) - 7\) 1p ○ \(\text{} = -2 (x - \frac{1}{2})^{2} + \frac{1}{2} - 7\) 1p |