Getal & Ruimte (13e editie) - 3 vwo
'Ontbinden in factoren'.
| 2 vwo | 7.1 Buiten haakjes brengen |
opgave 1Ontbind in factoren. 1p a \(a^{2} + 2 a\) BuitenHaakjes (1) 00hd - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} + 2 a = a (a + 2)\) 1p 1p b \(14 a^{2} - 18 a\) BuitenHaakjes (2) 00he - Ontbinden in factoren - basis - 0ms - dynamic variables b \(14 a^{2} - 18 a = 2 a (7 a - 9)\) 1p 1p c \(10 x y + 14 x\) BuitenHaakjes (3) 00hf - Ontbinden in factoren - basis - 0ms - dynamic variables c \(10 x y + 14 x = 2 x (5 y + 7)\) 1p 1p d \(10 x y + 35 x z\) BuitenHaakjes (4) 00hg - Ontbinden in factoren - basis - 0ms - dynamic variables d \(10 x y + 35 x z = 5 x (2 y + 7 z)\) 1p opgave 2Ontbind in factoren. 1p a \(12 p q r + 21 p q\) BuitenHaakjes (5) 00hh - Ontbinden in factoren - basis - 0ms - dynamic variables a \(12 p q r + 21 p q = 3 p q (4 r + 7)\) 1p 1p b \(6 a^{3} - 27 a^{4}\) BuitenHaakjes (6) 00hi - Ontbinden in factoren - basis - 0ms - dynamic variables b \(6 a^{3} - 27 a^{4} = 3 a^{3} (2 - 9 a)\) 1p 1p c \(4 p^{7} + 5 p^{6} + p^{5}\) BuitenHaakjes (7) 00hj - Ontbinden in factoren - basis - 0ms - dynamic variables c \(4 p^{7} + 5 p^{6} + p^{5} = p^{5} (4 p^{2} + 5 p + 1)\) 1p 1p d \(10 x^{2} y^{5} + 18 x^{5} y^{4}\) BuitenHaakjes (8) 00hk - Ontbinden in factoren - basis - 0ms - dynamic variables d \(10 x^{2} y^{5} + 18 x^{5} y^{4} = 2 x^{2} y^{4} (5 y + 9 x^{3})\) 1p opgave 3Ontbind in factoren. 1p a \(x^{2} - 16\) Verschil2Kwadraten (1) 00hl - Ontbinden in factoren - basis - 0ms - dynamic variables a \(x^{2} - 16 = (x - 4) (x + 4)\) 1p 1p b \(25 a^{2} - 64\) Verschil2Kwadraten (2) 00hm - Ontbinden in factoren - basis - 0ms - dynamic variables b \(25 a^{2} - 64 = (5 a - 8) (5 a + 8)\) 1p 1p c \(144 - 25 x^{2}\) Verschil2Kwadraten (3) 00hs - Ontbinden in factoren - basis - 0ms - dynamic variables c \(144 - 25 x^{2} = (12 - 5 x) (12 + 5 x)\) 1p 1p d \(16 a^{12} - 121\) Verschil2Kwadraten (4) 00ht - Ontbinden in factoren - basis - 0ms - dynamic variables d \(16 a^{12} - 121 = (4 a^{6} - 11) (4 a^{6} + 11)\) 1p opgave 4Ontbind in factoren. 1p a \(36 x^{2} - 100\) Verschil2Kwadraten (5) 00hu - Ontbinden in factoren - basis - 0ms - dynamic variables a \(36 x^{2} - 100 = 4 (9 x^{2} - 25) = 4 (3 x - 5) (3 x + 5)\) 1p 1p b \(45 a^{3} - 20 a\) Verschil2Kwadraten (6) 00hv - Ontbinden in factoren - basis - 0ms - dynamic variables b \(45 a^{3} - 20 a = 5 a (9 a^{2} - 4) = 5 a (3 a - 2) (3 a + 2)\) 1p 1p c \(p^{8} - 16\) Verschil2Kwadraten (7) 00hw - Ontbinden in factoren - basis - 0ms - dynamic variables c \(p^{8} - 16 = (p^{4} - 4) (p^{4} + 4) = (p^{2} - 2) (p^{2} + 2) (p^{4} + 4)\) 1p 1p d \(2 x^{5} - 162 x\) Verschil2Kwadraten (8) 00hx - Ontbinden in factoren - basis - 0ms - dynamic variables d \(2 x^{5} - 162 x = 2 x (x^{4} - 81) = 2 x (x^{2} - 9) (x^{2} + 9) = 2 x (x - 3) (x + 3) (x^{2} + 9)\) 1p opgave 5Ontbind in factoren. 1p \(a^{2} b^{12} - 4 c^{8}\) Verschil2Kwadraten (9) 00hz - Ontbinden in factoren - basis - 0ms - dynamic variables ○ \(a^{2} b^{12} - 4 c^{8} = (a b^{6} - 2 c^{4}) (a b^{6} + 2 c^{4})\) 1p |
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| 2 vwo | 7.2 De product-som methode |
opgave 1Ontbind in factoren. 1p a \(a^{2} + 8 a + 12\) SomProductmethode (1) 00hn - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} + 8 a + 12 = (a + 2) (a + 6)\) 1p 1p b \(a^{2} - 5 a - 14\) SomProductmethode (2) 00ho - Ontbinden in factoren - basis - 0ms - dynamic variables b \(a^{2} - 5 a - 14 = (a - 7) (a + 2)\) 1p 1p c \(x^{2} - 6 x + 8\) SomProductmethode (3) 00hp - Ontbinden in factoren - basis - 0ms - dynamic variables c \(x^{2} - 6 x + 8 = (x - 2) (x - 4)\) 1p 1p d \(p^{2} - 4 p + 4\) SomProductmethode (4) 00hq - Ontbinden in factoren - basis - 0ms - dynamic variables d \(p^{2} - 4 p + 4 = (p - 2) (p - 2)\) 1p opgave 2Ontbind in factoren. 1p a \(5 x^{4} + 20 x^{3} + 15 x^{2}\) SomProductmethode (5) 00hr - Ontbinden in factoren - basis - 0ms - dynamic variables a \(5 x^{4} + 20 x^{3} + 15 x^{2} = 5 x^{2} (x^{2} + 4 x + 3) = 5 x^{2} (x + 3) (x + 1)\) 1p 1p b \(a^{10} - 2 a^{5} - 48\) SomProductmethode (6) 00hy - Ontbinden in factoren - basis - 0ms - dynamic variables b \(a^{10} - 2 a^{5} - 48 = (a^{5} - 8) (a^{5} + 6)\) 1p |
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| 3 vwo | 5.2 Kwadraatafsplitsen |
opgave 1Splits het kwadraat af. 1p a \(x^{2} - 17 x\) KwadraatAfsplitsen (1) 00r8 - Ontbinden in factoren - basis - 0ms a \(x^{2} - 17 x = (x - 8\frac{1}{2})^{2} - 72\frac{1}{4}\) 1p 2p b \(x^{2} - 15 x + 16\) KwadraatAfsplitsen (2) 00r9 - Ontbinden in factoren - basis - 0ms b \(x^{2} - 15 x + 16 = (x - 7\frac{1}{2})^{2} - 56\frac{1}{4} + 16\) 1p ○ \(\text{} = (x - 7\frac{1}{2})^{2} - 40\frac{1}{4}\) 1p 3p c \(3 x^{2} + 3 x - 11\) KwadraatAfsplitsen (3) 00ra - Ontbinden in factoren - basis - 0ms c \(3 x^{2} + 3 x - 11 = 3 (x^{2} + x) - 11\) 1p ○ \(\text{} = 3 ((x + \frac{1}{2})^{2} - \frac{1}{4}) - 11\) 1p ○ \(\text{} = 3 (x + \frac{1}{2})^{2} - \frac{3}{4} - 11\) 1p |