Getal & Ruimte (13e editie) - 3 vwo
'Ontbinden in factoren'.
| 2 vwo | 7.1 Buiten haakjes brengen |
opgave 1Ontbind in factoren. 1p a \(a^2+5a\) BuitenHaakjes (1) 00hd - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^2+5a=a(a+5)\) 1p 1p b \(15x^2+21x\) BuitenHaakjes (2) 00he - Ontbinden in factoren - basis - 0ms - dynamic variables b \(15x^2+21x=3x(5x+7)\) 1p 1p c \(15pq+35p\) BuitenHaakjes (3) 00hf - Ontbinden in factoren - basis - 0ms - dynamic variables c \(15pq+35p=5p(3q+7)\) 1p 1p d \(15ab+20ac\) BuitenHaakjes (4) 00hg - Ontbinden in factoren - basis - 0ms - dynamic variables d \(15ab+20ac=5a(3b+4c)\) 1p opgave 2Ontbind in factoren. 1p a \(4xyz+18xy\) BuitenHaakjes (5) 00hh - Ontbinden in factoren - basis - 0ms - dynamic variables a \(4xyz+18xy=2xy(2z+9)\) 1p 1p b \(8a^2-10a^5\) BuitenHaakjes (6) 00hi - Ontbinden in factoren - basis - 0ms - dynamic variables b \(8a^2-10a^5=2a^2(4-5a^3)\) 1p 1p c \(2x^3-5x^2+x^5\) BuitenHaakjes (7) 00hj - Ontbinden in factoren - basis - 0ms - dynamic variables c \(2x^3-5x^2+x^5=x^2(2x-5+x^3)\) 1p 1p d \(25p^5q-40p^2q^3\) BuitenHaakjes (8) 00hk - Ontbinden in factoren - basis - 0ms - dynamic variables d \(25p^5q-40p^2q^3=5p^2q(5p^3-8q^2)\) 1p opgave 3Ontbind in factoren. 1p a \(x^2-64\) Verschil2Kwadraten (1) 00hl - Ontbinden in factoren - basis - 0ms - dynamic variables a \(x^2-64=(x-8)(x+8)\) 1p 1p b \(81a^2-100\) Verschil2Kwadraten (2) 00hm - Ontbinden in factoren - basis - 1ms - dynamic variables b \(81a^2-100=(9a-10)(9a+10)\) 1p 1p c \(81-4a^2\) Verschil2Kwadraten (3) 00hs - Ontbinden in factoren - basis - 1ms - dynamic variables c \(81-4a^2=(9-2a)(9+2a)\) 1p 1p d \(121a^{10}-49\) Verschil2Kwadraten (4) 00ht - Ontbinden in factoren - basis - 0ms - dynamic variables d \(121a^{10}-49=(11a^5-7)(11a^5+7)\) 1p opgave 4Ontbind in factoren. 1p a \(80x^2-45\) Verschil2Kwadraten (5) 00hu - Ontbinden in factoren - basis - 1ms - dynamic variables a \(80x^2-45=5(16x^2-9)=5(4x-3)(4x+3)\) 1p 1p b \(50p^4-18p^2\) Verschil2Kwadraten (6) 00hv - Ontbinden in factoren - basis - 1ms - dynamic variables b \(50p^4-18p^2=2p^2(25p^2-9)=2p^2(5p-3)(5p+3)\) 1p 1p c \(x^4-1\) Verschil2Kwadraten (7) 00hw - Ontbinden in factoren - basis - 1ms - dynamic variables c \(x^4-1=(x^2-1)(x^2+1)=(x-1)(x+1)(x^2+1)\) 1p 1p d \(2p^{13}-162p\) Verschil2Kwadraten (8) 00hx - Ontbinden in factoren - basis - 1ms - dynamic variables d \(2p^{13}-162p=2p(p^{12}-81)=2p(p^6-9)(p^6+9)=2p(p^3-3)(p^3+3)(p^6+9)\) 1p opgave 5Ontbind in factoren. 1p \(x^8y^{12}-64z^{12}\) Verschil2Kwadraten (9) 00hz - Ontbinden in factoren - basis - 0ms - dynamic variables ○ \(x^8y^{12}-64z^{12}=(x^4y^6-8z^6)(x^4y^6+8z^6)\) 1p |
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| 2 vwo | 7.2 De product-som methode |
opgave 1Ontbind in factoren. 1p a \(p^2+10p+24\) SomProductmethode (1) 00hn - Ontbinden in factoren - basis - 0ms - dynamic variables a \(p^2+10p+24=(p+4)(p+6)\) 1p 1p b \(x^2+7x-18\) SomProductmethode (2) 00ho - Ontbinden in factoren - basis - 0ms - dynamic variables b \(x^2+7x-18=(x-2)(x+9)\) 1p 1p c \(a^2-6a+5\) SomProductmethode (3) 00hp - Ontbinden in factoren - basis - 0ms - dynamic variables c \(a^2-6a+5=(a-5)(a-1)\) 1p 1p d \(a^2-18a+81\) SomProductmethode (4) 00hq - Ontbinden in factoren - basis - 0ms - dynamic variables d \(a^2-18a+81=(a-9)(a-9)\) 1p opgave 2Ontbind in factoren. 1p a \(4x^4-16x^3-20x^2\) SomProductmethode (5) 00hr - Ontbinden in factoren - basis - 1ms - dynamic variables a \(4x^4-16x^3-20x^2=4x^2(x^2-4x-5)=4x^2(x-5)(x+1)\) 1p 1p b \(x^6+12x^3+35\) SomProductmethode (6) 00hy - Ontbinden in factoren - basis - 0ms - dynamic variables b \(x^6+12x^3+35=(x^3+5)(x^3+7)\) 1p |
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| 3 vwo | 5.2 Kwadraatafsplitsen |
opgave 1Splits het kwadraat af. 1p a \(x^2-18x\) KwadraatAfsplitsen (1) 00r8 - Ontbinden in factoren - basis - 0ms a \(x^2-18x=(x-9)^2-81\) 1p 2p b \(x^2+16x+12\) KwadraatAfsplitsen (2) 00r9 - Ontbinden in factoren - basis - 0ms b \(x^2+16x+12=(x+8)^2-64+12\) 1p ○ \(\text{}=(x+8)^2-52\) 1p 3p c \(2x^2+10x-9\) KwadraatAfsplitsen (3) 00ra - Ontbinden in factoren - basis - 0ms c \(2x^2+10x-9=2(x^2+5x)-9\) 1p ○ \(\text{}=2((x+2\frac{1}{2})^2-6\frac{1}{4})-9\) 1p ○ \(\text{}=2(x+2\frac{1}{2})^2-12\frac{1}{2}-9\) 1p |