\({6 \over 8a}+{3 \over 8a}={9 \over 8a}\)

\({2 \over p}+{6 \over 9p}={18 \over 9p}+{6 \over 9p}={24 \over 9p}={8 \over 3p}\)

\({9 \over 3x}+{6 \over 7y}={63y \over 21xy}+{18x \over 21xy}={63y+18x \over 21xy}={21y+6x \over 7xy}\)

\(4+{9 \over 7a}={4 \over 1}+{9 \over 7a}={28a \over 7a}+{9 \over 7a}={28a+9 \over 7a}\)

\({4x \over y}+{5 \over 8y}={32x \over 8y}+{5 \over 8y}={32x+5 \over 8y}\)

\({2a \over a}={2 \over 1}=2\)

\({a \over 3a}={1 \over 3}\)

\({6p \over 27p}=\frac{2}{9}\)

\({-14x \over -2x}=7\)

\({20xy \over 45xz}={4y \over 9z}\)

\({-35b \over 40ab}=-{7 \over 8a}\)

\({28xyz \over -4yz}=-7x\)

\({4pq \over q}-{5pr \over r}=4p-5p=-p\)

\(5x+{9 \over 7x}={5x \over 1}⋅{7x \over 7x}+{9 \over 7x}={35x^2 \over 7x}+{9 \over 7x}={35x^2+9 \over 7x}\)

\({6b \over 8a}-{2a \over 4b}={6b^2 \over 8ab}-{4a^2 \over 8ab}={-4a^2+6b^2 \over 8ab}={-2a^2+3b^2 \over 4ab}\)

\({9 \over a}⋅-{7 \over b}=-{63 \over ab}\)

\({x \over 3}⋅-{4 \over y}=-{4x \over 3y}\)

\(-{8 \over 9}⋅p=-{8p \over 9}\)

\({7b \over a}⋅{a-2 \over 6}={7b(a-2) \over 6a}={7ab-14b \over 6a}\)

\({6 \over p}:{7 \over q}={6 \over p}⋅{q \over 7}={6q \over 7p}\)

\({3 \over 8}:x={3 \over 8}:{x \over 1}={3 \over 8}⋅{1 \over x}={3 \over 8x}\)

\(-{8 \over 7}:{a-2b \over b}=-{8 \over 7}⋅{b \over a-2b}=-{8b \over 7(a-2b)}=-{8b \over 7a-14b}\)

\({4x \over 9}+{x+2 \over 7}={28x \over 63}+{9(x+2) \over 63}={28x+9(x+2) \over 63}={37x+18 \over 63}\)

\({6a+3 \over 5a-9}+8={6a+3 \over 5a-9}+{8(5a-9) \over 5a-9}={6a+3+8(5a-9) \over 5a-9}={6a+3+40a-72 \over 5a-9}={46a-69 \over 5a-9}\)