\({9 \over 8 a} - {3 \over 8 a} = {6 \over 8 a} = {3 \over 4 a}\)

\({6 \over p} + {5 \over 9 p} = {54 \over 9 p} + {5 \over 9 p} = {59 \over 9 p}\)

\({7 \over 4 x} - {6 \over 5 y} = {35 y \over 20 x y} - {24 x \over 20 x y} = {35 y - 24 x \over 20 x y}\)

\(2 - {7 \over 6 a} = {2 \over 1} - {7 \over 6 a} = {12 a \over 6 a} - {7 \over 6 a} = {12 a - 7 \over 6 a}\)

\({6 x \over y} - {2 \over 4 y} = {24 x \over 4 y} - {2 \over 4 y} = {24 x - 2 \over 4 y} = {12 x - 1 \over 2 y}\)

\({6 a \over a} = {6 \over 1} = 6\)

\({x \over 6 x} = {1 \over 6}\)

\({6 p \over -14 p} = -\frac{3}{7}\)

\({25 a \over 5 a} = 5\)

\({20 x y \over -35 x z} = -{4 y \over 7 z}\)

\({-6 b \over -21 a b} = {2 \over 7 a}\)

\({-18 x y z \over 3 y z} = -6 x\)

\({4 a b \over b} + {2 a c \over c} = 4 a + 2 a = 6 a\)

\(5 p - {8 \over 9 p} = {5 p \over 1} ⋅ {9 p \over 9 p} - {8 \over 9 p} = {45 p^{2} \over 9 p} - {8 \over 9 p} = {45 p^{2} - 8 \over 9 p}\)

\({5 b \over 8 a} - {3 a \over 6 b} = {15 b^{2} \over 24 a b} - {12 a^{2} \over 24 a b} = {-12 a^{2} + 15 b^{2} \over 24 a b} = {-4 a^{2} + 5 b^{2} \over 8 a b}\)

\({7 \over x} ⋅ -{2 \over y} = -{14 \over x y}\)

\({a \over 5} ⋅ {3 \over b} = {3 a \over 5 b}\)

\(-{9 \over 7} ⋅ x = -{9 x \over 7}\)

\({6 y \over x} ⋅ {x + 2 \over 9} = {6 y (x + 2) \over 9 x} = {2 y (x + 2) \over 3 x} = {2 x y + 4 y \over 3 x}\)

\({9 \over a} : {4 \over b} = {9 \over a} ⋅ {b \over 4} = {9 b \over 4 a}\)

\(-{7 \over 6} : x = -{7 \over 6} : {x \over 1} = -{7 \over 6} ⋅ {1 \over x} = -{7 \over 6 x}\)

\(-{5 \over 8} : {p - 3 q \over q} = -{5 \over 8} ⋅ {q \over p - 3 q} = -{5 q \over 8 (p - 3 q)} = -{5 q \over 8 p - 24 q}\)

\({a \over 2} + {a + 9 \over 7} = {7 a \over 14} + {2 (a + 9) \over 14} = {7 a + 2 (a + 9) \over 14} = {9 a + 18 \over 14}\)

\({8 x + 3 \over 5 x + 7} - 1 = {8 x + 3 \over 5 x + 7} - {1 (5 x + 7) \over 5 x + 7} = {8 x + 3 - 1 (5 x + 7) \over 5 x + 7} = {8 x + 3 - 5 x - 7 \over 5 x + 7} = {3 x - 4 \over 5 x + 7}\)