\({5 \over 3 a} + {8 \over 3 a} = {13 \over 3 a}\)

\({2 \over p} - {7 \over 3 p} = {6 \over 3 p} - {7 \over 3 p} = -{1 \over 3 p}\)

\({6 \over 7 a} + {2 \over 9 b} = {54 b \over 63 a b} + {14 a \over 63 a b} = {54 b + 14 a \over 63 a b}\)

\(5 + {3 \over 2 x} = {5 \over 1} + {3 \over 2 x} = {10 x \over 2 x} + {3 \over 2 x} = {10 x + 3 \over 2 x}\)

\({9 x \over y} - {7 \over 2 y} = {18 x \over 2 y} - {7 \over 2 y} = {18 x - 7 \over 2 y}\)

\({8 a \over a} = {8 \over 1} = 8\)

\({p \over 8 p} = {1 \over 8}\)

\({-8 x \over 36 x} = -\frac{2}{9}\)

\({28 a \over 4 a} = 7\)

\({12 x y \over 15 x z} = {4 y \over 5 z}\)

\({-18 q \over 21 p q} = -{6 \over 7 p}\)

\({10 a b c \over 2 b c} = 5 a\)

\({7 x y \over y} - {4 x z \over z} = 7 x - 4 x = 3 x\)

\(2 a - {5 \over 3 a} = {2 a \over 1} ⋅ {3 a \over 3 a} - {5 \over 3 a} = {6 a^{2} \over 3 a} - {5 \over 3 a} = {6 a^{2} - 5 \over 3 a}\)

\({6 b \over 8 a} - {4 a \over 2 b} = {6 b^{2} \over 8 a b} - {16 a^{2} \over 8 a b} = {-16 a^{2} + 6 b^{2} \over 8 a b} = {-8 a^{2} + 3 b^{2} \over 4 a b}\)

\({7 \over x} ⋅ -{8 \over y} = -{56 \over x y}\)

\({x \over 4} ⋅ -{6 \over y} = -{6 x \over 4 y} = -{3 x \over 2 y}\)

\(-{5 \over 3} ⋅ p = -{5 p \over 3}\)

\({7 y \over x} ⋅ {x - 6 \over 3} = {7 y (x - 6) \over 3 x} = {7 x y - 42 y \over 3 x}\)

\({8 \over p} : {4 \over q} = {8 \over p} ⋅ {q \over 4} = {8 q \over 4 p} = {2 q \over p}\)

\({4 \over 7} : a = {4 \over 7} : {a \over 1} = {4 \over 7} ⋅ {1 \over a} = {4 \over 7 a}\)

\(-{6 \over 5} : {a + b \over b} = -{6 \over 5} ⋅ {b \over a + b} = -{6 b \over 5 (a + b)} = -{6 b \over 5 a + 5 b}\)

\({4 x \over 9} + {x + 2 \over 8} = {32 x \over 72} + {9 (x + 2) \over 72} = {32 x + 9 (x + 2) \over 72} = {41 x + 18 \over 72}\)

\({4 x + 6 \over -5 x - 2} + 8 = {4 x + 6 \over -5 x - 2} - {-8 (-5 x - 2) \over -5 x - 2} = {4 x + 6 + 8 (-5 x - 2) \over -5 x - 2} = {4 x + 6 - 40 x - 16 \over -5 x - 2} = {-36 x - 10 \over -5 x - 2}\)