Getal & Ruimte (13e editie) - 3 havo
'Sinus, cosinus en tangens'.
| 3 havo | 6.3 Berekeningen met de tangens |
opgave 13p a Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}Q=33\text{,}\) \(\angle P=48\degree\) en \(\angle Q=90\degree\text{.}\) Tangens (1) 007m - Sinus, cosinus en tangens - basis - 0ms a Tangens in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\tan(\angle P)={Q\kern{-.8pt}R \over P\kern{-.8pt}Q}\) ofwel \(\tan(48\degree)={Q\kern{-.8pt}R \over 33}\text{.}\) 1p ○ Hieruit volgt \(Q\kern{-.8pt}R=33⋅\tan(48\degree)\text{.}\) 1p ○ Dus \(Q\kern{-.8pt}R≈36{,}7\text{.}\) 1p 3p b Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(B\kern{-.8pt}C=59\text{,}\) \(\angle A=38\degree\) en \(\angle B=90\degree\text{.}\) Tangens (2) 007n - Sinus, cosinus en tangens - basis - 0ms b Tangens in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\tan(\angle A)={B\kern{-.8pt}C \over A\kern{-.8pt}B}\) ofwel \(\tan(38\degree)={59 \over A\kern{-.8pt}B}\text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}B={59 \over \tan(38\degree)}\text{.}\) 1p ○ Dus \(A\kern{-.8pt}B≈75{,}5\text{.}\) 1p 3p c Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}B=28\text{,}\) \(B\kern{-.8pt}C=50\) en \(\angle B=90\degree\text{.}\) Tangens (3) 007o - Sinus, cosinus en tangens - basis - 0ms c Tangens in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\tan(\angle A)={B\kern{-.8pt}C \over A\kern{-.8pt}B}\) ofwel \(\tan(\angle A)={50 \over 28}\text{.}\) 1p ○ Hieruit volgt \(\angle A=\tan^{-1}({50 \over 28})\text{.}\) 1p ○ Dus \(\angle A≈60{,}8\degree\text{.}\) 1p |
|
| 3 havo | 6.4 De sinus en de cosinus |
opgave 13p a Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}R=42\text{,}\) \(\angle P=35\degree\) en \(\angle Q=90\degree\text{.}\) Sinus (1) 007g - Sinus, cosinus en tangens - basis - 0ms a Sinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\sin(\angle P)={Q\kern{-.8pt}R \over P\kern{-.8pt}R}\) ofwel \(\sin(35\degree)={Q\kern{-.8pt}R \over 42}\text{.}\) 1p ○ Hieruit volgt \(Q\kern{-.8pt}R=42⋅\sin(35\degree)\text{.}\) 1p ○ Dus \(Q\kern{-.8pt}R≈24{,}1\text{.}\) 1p 3p b Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}Q=52\text{,}\) \(\angle R=42\degree\) en \(\angle P=90\degree\text{.}\) Sinus (2) 007h - Sinus, cosinus en tangens - basis - 0ms b Sinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\sin(\angle R)={P\kern{-.8pt}Q \over Q\kern{-.8pt}R}\) ofwel \(\sin(42\degree)={52 \over Q\kern{-.8pt}R}\text{.}\) 1p ○ Hieruit volgt \(Q\kern{-.8pt}R={52 \over \sin(42\degree)}\text{.}\) 1p ○ Dus \(Q\kern{-.8pt}R≈77{,}7\text{.}\) 1p 3p c Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}M=56\text{,}\) \(K\kern{-.8pt}L=75\) en \(\angle M=90\degree\text{.}\) Sinus (3) 007i - Sinus, cosinus en tangens - basis - 0ms c Sinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\sin(\angle L)={K\kern{-.8pt}M \over K\kern{-.8pt}L}\) ofwel \(\sin(\angle L)={56 \over 75}\text{.}\) 1p ○ Hieruit volgt \(\angle L=\sin^{-1}({56 \over 75})\text{.}\) 1p ○ Dus \(\angle L≈48{,}3\degree\text{.}\) 1p 3p d Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(Q\kern{-.8pt}R=41\text{,}\) \(\angle R=37\degree\) en \(\angle P=90\degree\text{.}\) Cosinus (1) 007j - Sinus, cosinus en tangens - basis - 0ms d Cosinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\cos(\angle R)={P\kern{-.8pt}R \over Q\kern{-.8pt}R}\) ofwel \(\cos(37\degree)={P\kern{-.8pt}R \over 41}\text{.}\) 1p ○ Hieruit volgt \(P\kern{-.8pt}R=41⋅\cos(37\degree)\text{.}\) 1p ○ Dus \(P\kern{-.8pt}R≈32{,}7\text{.}\) 1p opgave 23p a Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(B\kern{-.8pt}C=57\text{,}\) \(\angle B=44\degree\) en \(\angle C=90\degree\text{.}\) Cosinus (2) 007k - Sinus, cosinus en tangens - basis - 0ms a Cosinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\cos(\angle B)={B\kern{-.8pt}C \over A\kern{-.8pt}B}\) ofwel \(\cos(44\degree)={57 \over A\kern{-.8pt}B}\text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}B={57 \over \cos(44\degree)}\text{.}\) 1p ○ Dus \(A\kern{-.8pt}B≈79{,}2\text{.}\) 1p 3p b Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}M=27\text{,}\) \(L\kern{-.8pt}M=34\) en \(\angle K=90\degree\text{.}\) Cosinus (3) 007l - Sinus, cosinus en tangens - basis - 1ms b Cosinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\cos(\angle M)={K\kern{-.8pt}M \over L\kern{-.8pt}M}\) ofwel \(\cos(\angle M)={27 \over 34}\text{.}\) 1p ○ Hieruit volgt \(\angle M=\cos^{-1}({27 \over 34})\text{.}\) 1p ○ Dus \(\angle M≈37{,}4\degree\text{.}\) 1p |