Getal & Ruimte (13e editie) - 2 vwo
'Ontbinden in factoren'.
| 2 vwo | 7.1 Buiten haakjes brengen |
opgave 1Ontbind in factoren. 1p a \(a^{2} + a\) BuitenHaakjes (1) 00hd - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} + a = a (a + 1)\) 1p 1p b \(6 x^{2} + 8 x\) BuitenHaakjes (2) 00he - Ontbinden in factoren - basis - 0ms - dynamic variables b \(6 x^{2} + 8 x = 2 x (3 x + 4)\) 1p 1p c \(18 p q + 21 p\) BuitenHaakjes (3) 00hf - Ontbinden in factoren - basis - 0ms - dynamic variables c \(18 p q + 21 p = 3 p (6 q + 7)\) 1p 1p d \(6 a b + 14 a c\) BuitenHaakjes (4) 00hg - Ontbinden in factoren - basis - 0ms - dynamic variables d \(6 a b + 14 a c = 2 a (3 b + 7 c)\) 1p opgave 2Ontbind in factoren. 1p a \(28 x y z + 32 x y\) BuitenHaakjes (5) 00hh - Ontbinden in factoren - basis - 0ms - dynamic variables a \(28 x y z + 32 x y = 4 x y (7 z + 8)\) 1p 1p b \(12 x^{3} + 32 x^{4}\) BuitenHaakjes (6) 00hi - Ontbinden in factoren - basis - 0ms - dynamic variables b \(12 x^{3} + 32 x^{4} = 4 x^{3} (3 + 8 x)\) 1p 1p c \(2 p^{4} - 7 p + p^{8}\) BuitenHaakjes (7) 00hj - Ontbinden in factoren - basis - 0ms - dynamic variables c \(2 p^{4} - 7 p + p^{8} = p (2 p^{3} - 7 + p^{7})\) 1p 1p d \(12 x^{5} y^{4} + 15 x y^{5}\) BuitenHaakjes (8) 00hk - Ontbinden in factoren - basis - 0ms - dynamic variables d \(12 x^{5} y^{4} + 15 x y^{5} = 3 x y^{4} (4 x^{4} + 5 y)\) 1p opgave 3Ontbind in factoren. 1p a \(a^{2} - 100\) Verschil2Kwadraten (1) 00hl - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} - 100 = (a - 10) (a + 10)\) 1p 1p b \(64 a^{2} - 49\) Verschil2Kwadraten (2) 00hm - Ontbinden in factoren - basis - 0ms - dynamic variables b \(64 a^{2} - 49 = (8 a - 7) (8 a + 7)\) 1p 1p c \(25 - 49 x^{2}\) Verschil2Kwadraten (3) 00hs - Ontbinden in factoren - basis - 0ms - dynamic variables c \(25 - 49 x^{2} = (5 - 7 x) (5 + 7 x)\) 1p 1p d \(a^{6} - 49\) Verschil2Kwadraten (4) 00ht - Ontbinden in factoren - basis - 0ms - dynamic variables d \(a^{6} - 49 = (a^{3} - 7) (a^{3} + 7)\) 1p opgave 4Ontbind in factoren. 1p a \(75 p^{2} - 48\) Verschil2Kwadraten (5) 00hu - Ontbinden in factoren - basis - 0ms - dynamic variables a \(75 p^{2} - 48 = 3 (25 p^{2} - 16) = 3 (5 p - 4) (5 p + 4)\) 1p 1p b \(45 a^{4} - 20 a^{2}\) Verschil2Kwadraten (6) 00hv - Ontbinden in factoren - basis - 0ms - dynamic variables b \(45 a^{4} - 20 a^{2} = 5 a^{2} (9 a^{2} - 4) = 5 a^{2} (3 a - 2) (3 a + 2)\) 1p 1p c \(x^{8} - 81\) Verschil2Kwadraten (7) 00hw - Ontbinden in factoren - basis - 0ms - dynamic variables c \(x^{8} - 81 = (x^{4} - 9) (x^{4} + 9) = (x^{2} - 3) (x^{2} + 3) (x^{4} + 9)\) 1p 1p d \(2 x^{9} - 32 x\) Verschil2Kwadraten (8) 00hx - Ontbinden in factoren - basis - 0ms - dynamic variables d \(2 x^{9} - 32 x = 2 x (x^{8} - 16) = 2 x (x^{4} - 4) (x^{4} + 4) = 2 x (x^{2} - 2) (x^{2} + 2) (x^{4} + 4)\) 1p opgave 5Ontbind in factoren. 1p \(a^{8} b^{12} - 121 c^{10}\) Verschil2Kwadraten (9) 00hz - Ontbinden in factoren - basis - 0ms - dynamic variables ○ \(a^{8} b^{12} - 121 c^{10} = (a^{4} b^{6} - 11 c^{5}) (a^{4} b^{6} + 11 c^{5})\) 1p |
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| 2 vwo | 7.2 De product-som methode |
opgave 1Ontbind in factoren. 1p a \(a^{2} + 14 a + 45\) SomProductmethode (1) 00hn - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} + 14 a + 45 = (a + 9) (a + 5)\) 1p 1p b \(p^{2} + p - 2\) SomProductmethode (2) 00ho - Ontbinden in factoren - basis - 0ms - dynamic variables b \(p^{2} + p - 2 = (p + 2) (p - 1)\) 1p 1p c \(x^{2} - 10 x + 21\) SomProductmethode (3) 00hp - Ontbinden in factoren - basis - 0ms - dynamic variables c \(x^{2} - 10 x + 21 = (x - 3) (x - 7)\) 1p 1p d \(x^{2} - 2 x + 1\) SomProductmethode (4) 00hq - Ontbinden in factoren - basis - 0ms - dynamic variables d \(x^{2} - 2 x + 1 = (x - 1) (x - 1)\) 1p opgave 2Ontbind in factoren. 1p a \(5 a^{4} - 5 a^{3} - 150 a^{2}\) SomProductmethode (5) 00hr - Ontbinden in factoren - basis - 0ms - dynamic variables a \(5 a^{4} - 5 a^{3} - 150 a^{2} = 5 a^{2} (a^{2} - a - 30) = 5 a^{2} (a + 5) (a - 6)\) 1p 1p b \(a^{14} + 7 a^{7} + 10\) SomProductmethode (6) 00hy - Ontbinden in factoren - basis - 0ms - dynamic variables b \(a^{14} + 7 a^{7} + 10 = (a^{7} + 2) (a^{7} + 5)\) 1p |