Getal & Ruimte (13e editie) - 2 vwo
'Ontbinden in factoren'.
| 2 vwo | 7.1 Buiten haakjes brengen |
opgave 1Ontbind in factoren. 1p a \(p^{2} + 4 p\) BuitenHaakjes (1) 00hd - Ontbinden in factoren - basis - 0ms - dynamic variables a \(p^{2} + 4 p = p (p + 4)\) 1p 1p b \(4 a^{2} - 10 a\) BuitenHaakjes (2) 00he - Ontbinden in factoren - basis - 0ms - dynamic variables b \(4 a^{2} - 10 a = 2 a (2 a - 5)\) 1p 1p c \(25 a b + 35 a\) BuitenHaakjes (3) 00hf - Ontbinden in factoren - basis - 0ms - dynamic variables c \(25 a b + 35 a = 5 a (5 b + 7)\) 1p 1p d \(6 x y + 9 x z\) BuitenHaakjes (4) 00hg - Ontbinden in factoren - basis - 0ms - dynamic variables d \(6 x y + 9 x z = 3 x (2 y + 3 z)\) 1p opgave 2Ontbind in factoren. 1p a \(25 x y z + 35 x y\) BuitenHaakjes (5) 00hh - Ontbinden in factoren - basis - 0ms - dynamic variables a \(25 x y z + 35 x y = 5 x y (5 z + 7)\) 1p 1p b \(24 a^{3} - 27 a^{5}\) BuitenHaakjes (6) 00hi - Ontbinden in factoren - basis - 0ms - dynamic variables b \(24 a^{3} - 27 a^{5} = 3 a^{3} (8 - 9 a^{2})\) 1p 1p c \(5 x + 6 x^{7} + x^{3}\) BuitenHaakjes (7) 00hj - Ontbinden in factoren - basis - 0ms - dynamic variables c \(5 x + 6 x^{7} + x^{3} = x (5 + 6 x^{6} + x^{2})\) 1p 1p d \(25 a b + 35 a^{3} b^{2}\) BuitenHaakjes (8) 00hk - Ontbinden in factoren - basis - 0ms - dynamic variables d \(25 a b + 35 a^{3} b^{2} = 5 a b (5 + 7 a^{2} b)\) 1p opgave 3Ontbind in factoren. 1p a \(p^{2} - 9\) Verschil2Kwadraten (1) 00hl - Ontbinden in factoren - basis - 0ms - dynamic variables a \(p^{2} - 9 = (p - 3) (p + 3)\) 1p 1p b \(25 x^{2} - 64\) Verschil2Kwadraten (2) 00hm - Ontbinden in factoren - basis - 0ms - dynamic variables b \(25 x^{2} - 64 = (5 x - 8) (5 x + 8)\) 1p 1p c \(4 - 25 a^{2}\) Verschil2Kwadraten (3) 00hs - Ontbinden in factoren - basis - 0ms - dynamic variables c \(4 - 25 a^{2} = (2 - 5 a) (2 + 5 a)\) 1p 1p d \(100 x^{8} - 49\) Verschil2Kwadraten (4) 00ht - Ontbinden in factoren - basis - 0ms - dynamic variables d \(100 x^{8} - 49 = (10 x^{4} - 7) (10 x^{4} + 7)\) 1p opgave 4Ontbind in factoren. 1p a \(100 x^{2} - 16\) Verschil2Kwadraten (5) 00hu - Ontbinden in factoren - basis - 0ms - dynamic variables a \(100 x^{2} - 16 = 4 (25 x^{2} - 4) = 4 (5 x - 2) (5 x + 2)\) 1p 1p b \(5 a^{3} - 80 a\) Verschil2Kwadraten (6) 00hv - Ontbinden in factoren - basis - 0ms - dynamic variables b \(5 a^{3} - 80 a = 5 a (a^{2} - 16) = 5 a (a - 4) (a + 4)\) 1p 1p c \(p^{8} - 16\) Verschil2Kwadraten (7) 00hw - Ontbinden in factoren - basis - 0ms - dynamic variables c \(p^{8} - 16 = (p^{4} - 4) (p^{4} + 4) = (p^{2} - 2) (p^{2} + 2) (p^{4} + 4)\) 1p 1p d \(p^{10} - 81 p^{2}\) Verschil2Kwadraten (8) 00hx - Ontbinden in factoren - basis - 0ms - dynamic variables d \(p^{10} - 81 p^{2} = p^{2} (p^{8} - 81) = p^{2} (p^{4} - 9) (p^{4} + 9) = p^{2} (p^{2} - 3) (p^{2} + 3) (p^{4} + 9)\) 1p opgave 5Ontbind in factoren. 1p \(a^{12} b^{2} - 64 c^{6}\) Verschil2Kwadraten (9) 00hz - Ontbinden in factoren - basis - 0ms - dynamic variables ○ \(a^{12} b^{2} - 64 c^{6} = (a^{6} b - 8 c^{3}) (a^{6} b + 8 c^{3})\) 1p |
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| 2 vwo | 7.2 De product-som methode |
opgave 1Ontbind in factoren. 1p a \(a^{2} + 11 a + 24\) SomProductmethode (1) 00hn - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} + 11 a + 24 = (a + 8) (a + 3)\) 1p 1p b \(x^{2} + 4 x - 12\) SomProductmethode (2) 00ho - Ontbinden in factoren - basis - 0ms - dynamic variables b \(x^{2} + 4 x - 12 = (x - 2) (x + 6)\) 1p 1p c \(x^{2} - 17 x + 72\) SomProductmethode (3) 00hp - Ontbinden in factoren - basis - 0ms - dynamic variables c \(x^{2} - 17 x + 72 = (x - 8) (x - 9)\) 1p 1p d \(p^{2} + 18 p + 81\) SomProductmethode (4) 00hq - Ontbinden in factoren - basis - 0ms - dynamic variables d \(p^{2} + 18 p + 81 = (p + 9) (p + 9)\) 1p opgave 2Ontbind in factoren. 1p a \(2 a^{3} - 20 a^{2} + 48 a\) SomProductmethode (5) 00hr - Ontbinden in factoren - basis - 0ms - dynamic variables a \(2 a^{3} - 20 a^{2} + 48 a = 2 a (a^{2} - 10 a + 24) = 2 a (a - 6) (a - 4)\) 1p 1p b \(x^{6} - x^{3} - 56\) SomProductmethode (6) 00hy - Ontbinden in factoren - basis - 0ms - dynamic variables b \(x^{6} - x^{3} - 56 = (x^{3} + 7) (x^{3} - 8)\) 1p |