Getal & Ruimte (13e editie) - 2 vwo
'Ontbinden in factoren'.
| 2 vwo | 7.1 Buiten haakjes brengen |
opgave 1Ontbind in factoren. 1p a \(x^{2} + 3 x\) BuitenHaakjes (1) 00hd - Ontbinden in factoren - basis - 0ms - dynamic variables a \(x^{2} + 3 x = x (x + 3)\) 1p 1p b \(12 x^{2} + 16 x\) BuitenHaakjes (2) 00he - Ontbinden in factoren - basis - 0ms - dynamic variables b \(12 x^{2} + 16 x = 4 x (3 x + 4)\) 1p 1p c \(16 a b + 20 a\) BuitenHaakjes (3) 00hf - Ontbinden in factoren - basis - 0ms - dynamic variables c \(16 a b + 20 a = 4 a (4 b + 5)\) 1p 1p d \(4 a b + 10 a c\) BuitenHaakjes (4) 00hg - Ontbinden in factoren - basis - 0ms - dynamic variables d \(4 a b + 10 a c = 2 a (2 b + 5 c)\) 1p opgave 2Ontbind in factoren. 1p a \(21 p q r + 27 p q\) BuitenHaakjes (5) 00hh - Ontbinden in factoren - basis - 0ms - dynamic variables a \(21 p q r + 27 p q = 3 p q (7 r + 9)\) 1p 1p b \(12 a^{2} + 27 a^{5}\) BuitenHaakjes (6) 00hi - Ontbinden in factoren - basis - 0ms - dynamic variables b \(12 a^{2} + 27 a^{5} = 3 a^{2} (4 + 9 a^{3})\) 1p 1p c \(8 x + 9 x^{2} + x^{6}\) BuitenHaakjes (7) 00hj - Ontbinden in factoren - basis - 0ms - dynamic variables c \(8 x + 9 x^{2} + x^{6} = x (8 + 9 x + x^{5})\) 1p 1p d \(8 x^{2} y^{2} + 12 x^{3} y\) BuitenHaakjes (8) 00hk - Ontbinden in factoren - basis - 0ms - dynamic variables d \(8 x^{2} y^{2} + 12 x^{3} y = 4 x^{2} y (2 y + 3 x)\) 1p opgave 3Ontbind in factoren. 1p a \(a^{2} - 121\) Verschil2Kwadraten (1) 00hl - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} - 121 = (a - 11) (a + 11)\) 1p 1p b \(9 p^{2} - 100\) Verschil2Kwadraten (2) 00hm - Ontbinden in factoren - basis - 0ms - dynamic variables b \(9 p^{2} - 100 = (3 p - 10) (3 p + 10)\) 1p 1p c \(121 - 144 a^{2}\) Verschil2Kwadraten (3) 00hs - Ontbinden in factoren - basis - 0ms - dynamic variables c \(121 - 144 a^{2} = (11 - 12 a) (11 + 12 a)\) 1p 1p d \(9 p^{14} - 121\) Verschil2Kwadraten (4) 00ht - Ontbinden in factoren - basis - 0ms - dynamic variables d \(9 p^{14} - 121 = (3 p^{7} - 11) (3 p^{7} + 11)\) 1p opgave 4Ontbind in factoren. 1p a \(48 a^{2} - 3\) Verschil2Kwadraten (5) 00hu - Ontbinden in factoren - basis - 0ms - dynamic variables a \(48 a^{2} - 3 = 3 (16 a^{2} - 1) = 3 (4 a - 1) (4 a + 1)\) 1p 1p b \(80 x^{4} - 45 x^{2}\) Verschil2Kwadraten (6) 00hv - Ontbinden in factoren - basis - 0ms - dynamic variables b \(80 x^{4} - 45 x^{2} = 5 x^{2} (16 x^{2} - 9) = 5 x^{2} (4 x - 3) (4 x + 3)\) 1p 1p c \(x^{4} - 1\) Verschil2Kwadraten (7) 00hw - Ontbinden in factoren - basis - 0ms - dynamic variables c \(x^{4} - 1 = (x^{2} - 1) (x^{2} + 1) = (x - 1) (x + 1) (x^{2} + 1)\) 1p 1p d \(a^{14} - 81 a^{2}\) Verschil2Kwadraten (8) 00hx - Ontbinden in factoren - basis - 0ms - dynamic variables d \(a^{14} - 81 a^{2} = a^{2} (a^{12} - 81) = a^{2} (a^{6} - 9) (a^{6} + 9) = a^{2} (a^{3} - 3) (a^{3} + 3) (a^{6} + 9)\) 1p opgave 5Ontbind in factoren. 1p \(x^{12} y^{8} - 9 z^{10}\) Verschil2Kwadraten (9) 00hz - Ontbinden in factoren - basis - 0ms - dynamic variables ○ \(x^{12} y^{8} - 9 z^{10} = (x^{6} y^{4} - 3 z^{5}) (x^{6} y^{4} + 3 z^{5})\) 1p |
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| 2 vwo | 7.2 De product-som methode |
opgave 1Ontbind in factoren. 1p a \(x^{2} + 15 x + 56\) SomProductmethode (1) 00hn - Ontbinden in factoren - basis - 0ms - dynamic variables a \(x^{2} + 15 x + 56 = (x + 7) (x + 8)\) 1p 1p b \(p^{2} - p - 2\) SomProductmethode (2) 00ho - Ontbinden in factoren - basis - 0ms - dynamic variables b \(p^{2} - p - 2 = (p + 1) (p - 2)\) 1p 1p c \(a^{2} - 9 a + 20\) SomProductmethode (3) 00hp - Ontbinden in factoren - basis - 0ms - dynamic variables c \(a^{2} - 9 a + 20 = (a - 4) (a - 5)\) 1p 1p d \(x^{2} + 14 x + 49\) SomProductmethode (4) 00hq - Ontbinden in factoren - basis - 0ms - dynamic variables d \(x^{2} + 14 x + 49 = (x + 7) (x + 7)\) 1p opgave 2Ontbind in factoren. 1p a \(2 a^{5} - 2 a^{4} - 60 a^{3}\) SomProductmethode (5) 00hr - Ontbinden in factoren - basis - 0ms - dynamic variables a \(2 a^{5} - 2 a^{4} - 60 a^{3} = 2 a^{3} (a^{2} - a - 30) = 2 a^{3} (a + 5) (a - 6)\) 1p 1p b \(x^{14} - 12 x^{7} + 32\) SomProductmethode (6) 00hy - Ontbinden in factoren - basis - 0ms - dynamic variables b \(x^{14} - 12 x^{7} + 32 = (x^{7} - 8) (x^{7} - 4)\) 1p |