Getal & Ruimte (13e editie) - 2 vwo
'Ontbinden in factoren'.
| 2 vwo | 7.1 Buiten haakjes brengen |
opgave 1Ontbind in factoren. 1p a \(a^{2} + 3 a\) BuitenHaakjes (1) 00hd - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} + 3 a = a (a + 3)\) 1p 1p b \(6 p^{2} + 10 p\) BuitenHaakjes (2) 00he - Ontbinden in factoren - basis - 0ms - dynamic variables b \(6 p^{2} + 10 p = 2 p (3 p + 5)\) 1p 1p c \(6 x y + 15 x\) BuitenHaakjes (3) 00hf - Ontbinden in factoren - basis - 0ms - dynamic variables c \(6 x y + 15 x = 3 x (2 y + 5)\) 1p 1p d \(9 a b + 24 a c\) BuitenHaakjes (4) 00hg - Ontbinden in factoren - basis - 0ms - dynamic variables d \(9 a b + 24 a c = 3 a (3 b + 8 c)\) 1p opgave 2Ontbind in factoren. 1p a \(10 x y z + 15 x y\) BuitenHaakjes (5) 00hh - Ontbinden in factoren - basis - 0ms - dynamic variables a \(10 x y z + 15 x y = 5 x y (2 z + 3)\) 1p 1p b \(12 p^{5} - 14 p^{3}\) BuitenHaakjes (6) 00hi - Ontbinden in factoren - basis - 0ms - dynamic variables b \(12 p^{5} - 14 p^{3} = 2 p^{3} (6 p^{2} - 7)\) 1p 1p c \(3 x^{5} + 5 x^{8} + x\) BuitenHaakjes (7) 00hj - Ontbinden in factoren - basis - 0ms - dynamic variables c \(3 x^{5} + 5 x^{8} + x = x (3 x^{4} + 5 x^{7} + 1)\) 1p 1p d \(12 a^{2} b^{4} - 14 a^{3} b\) BuitenHaakjes (8) 00hk - Ontbinden in factoren - basis - 0ms - dynamic variables d \(12 a^{2} b^{4} - 14 a^{3} b = 2 a^{2} b (6 b^{3} - 7 a)\) 1p opgave 3Ontbind in factoren. 1p a \(a^{2} - 1\) Verschil2Kwadraten (1) 00hl - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} - 1 = (a - 1) (a + 1)\) 1p 1p b \(36 x^{2} - 121\) Verschil2Kwadraten (2) 00hm - Ontbinden in factoren - basis - 1ms - dynamic variables b \(36 x^{2} - 121 = (6 x - 11) (6 x + 11)\) 1p 1p c \(1 - 100 p^{2}\) Verschil2Kwadraten (3) 00hs - Ontbinden in factoren - basis - 1ms - dynamic variables c \(1 - 100 p^{2} = (1 - 10 p) (1 + 10 p)\) 1p 1p d \(81 a^{4} - 100\) Verschil2Kwadraten (4) 00ht - Ontbinden in factoren - basis - 1ms - dynamic variables d \(81 a^{4} - 100 = (9 a^{2} - 10) (9 a^{2} + 10)\) 1p opgave 4Ontbind in factoren. 1p a \(36 a^{2} - 16\) Verschil2Kwadraten (5) 00hu - Ontbinden in factoren - basis - 1ms - dynamic variables a \(36 a^{2} - 16 = 4 (9 a^{2} - 4) = 4 (3 a - 2) (3 a + 2)\) 1p 1p b \(18 x^{3} - 50 x\) Verschil2Kwadraten (6) 00hv - Ontbinden in factoren - basis - 1ms - dynamic variables b \(18 x^{3} - 50 x = 2 x (9 x^{2} - 25) = 2 x (3 x - 5) (3 x + 5)\) 1p 1p c \(x^{8} - 81\) Verschil2Kwadraten (7) 00hw - Ontbinden in factoren - basis - 0ms - dynamic variables c \(x^{8} - 81 = (x^{4} - 9) (x^{4} + 9) = (x^{2} - 3) (x^{2} + 3) (x^{4} + 9)\) 1p 1p d \(2 x^{7} - 32 x^{3}\) Verschil2Kwadraten (8) 00hx - Ontbinden in factoren - basis - 1ms - dynamic variables d \(2 x^{7} - 32 x^{3} = 2 x^{3} (x^{4} - 16) = 2 x^{3} (x^{2} - 4) (x^{2} + 4) = 2 x^{3} (x - 2) (x + 2) (x^{2} + 4)\) 1p opgave 5Ontbind in factoren. 1p \(p^{4} q^{4} - 100 r^{2}\) Verschil2Kwadraten (9) 00hz - Ontbinden in factoren - basis - 0ms - dynamic variables ○ \(p^{4} q^{4} - 100 r^{2} = (p^{2} q^{2} - 10 r) (p^{2} q^{2} + 10 r)\) 1p |
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| 2 vwo | 7.2 De product-som methode |
opgave 1Ontbind in factoren. 1p a \(a^{2} + 9 a + 18\) SomProductmethode (1) 00hn - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} + 9 a + 18 = (a + 3) (a + 6)\) 1p 1p b \(p^{2} + 2 p - 48\) SomProductmethode (2) 00ho - Ontbinden in factoren - basis - 0ms - dynamic variables b \(p^{2} + 2 p - 48 = (p + 8) (p - 6)\) 1p 1p c \(a^{2} - 4 a + 3\) SomProductmethode (3) 00hp - Ontbinden in factoren - basis - 0ms - dynamic variables c \(a^{2} - 4 a + 3 = (a - 3) (a - 1)\) 1p 1p d \(x^{2} + 6 x + 9\) SomProductmethode (4) 00hq - Ontbinden in factoren - basis - 0ms - dynamic variables d \(x^{2} + 6 x + 9 = (x + 3) (x + 3)\) 1p opgave 2Ontbind in factoren. 1p a \(5 x^{5} + 15 x^{4} - 50 x^{3}\) SomProductmethode (5) 00hr - Ontbinden in factoren - basis - 1ms - dynamic variables a \(5 x^{5} + 15 x^{4} - 50 x^{3} = 5 x^{3} (x^{2} + 3 x - 10) = 5 x^{3} (x - 2) (x + 5)\) 1p 1p b \(a^{10} + 3 a^{5} - 54\) SomProductmethode (6) 00hy - Ontbinden in factoren - basis - 0ms - dynamic variables b \(a^{10} + 3 a^{5} - 54 = (a^{5} - 6) (a^{5} + 9)\) 1p |