\(\sqrt{48} = \sqrt{16} ⋅ \sqrt{3} = 4 \sqrt{3} \text{.}\)

\(4 \sqrt{112} = 4 ⋅ \sqrt{16} ⋅ \sqrt{7} = 4 ⋅ 4 ⋅ \sqrt{7} = 16 \sqrt{7} \text{.}\)

\(\sqrt{2\frac{1}{4}} = \sqrt{\frac{9}{4}} = {\sqrt{9} \over \sqrt{4}} = \frac{3}{2} = 1\frac{1}{2} \text{.}\)

\({10 \sqrt{120} \over 2 \sqrt{5}} = {10 \over 2} ⋅ {\sqrt{120} \over \sqrt{5}} = 5 \sqrt{24} = 5 ⋅ \sqrt{4} ⋅ \sqrt{6} = 5 ⋅ 2 ⋅ \sqrt{6} = 10 \sqrt{6}\)