\(\sqrt{18} = \sqrt{9} ⋅ \sqrt{2} = 3 \sqrt{2} \text{.}\)

\(2 \sqrt{700} = 2 ⋅ \sqrt{100} ⋅ \sqrt{7} = 2 ⋅ 10 ⋅ \sqrt{7} = 20 \sqrt{7} \text{.}\)

\(\sqrt{1\frac{19}{81}} = \sqrt{\frac{100}{81}} = {\sqrt{100} \over \sqrt{81}} = \frac{10}{9} = 1\frac{1}{9} \text{.}\)

\({6 \sqrt{240} \over 2 \sqrt{6}} = {6 \over 2} ⋅ {\sqrt{240} \over \sqrt{6}} = 3 \sqrt{40} = 3 ⋅ \sqrt{4} ⋅ \sqrt{10} = 3 ⋅ 2 ⋅ \sqrt{10} = 6 \sqrt{10}\)