Getal & Ruimte (13e editie) - 1 vwo
'Rekenvolgorde'.
| 1 vwo | 2.1 Bewerkingen |
opgave 1Bereken. 1p a \(120 : 5 : 4\) PositiefDrieDelen (1) 00ah - Rekenvolgorde - basis - 0ms a \(120 : 5 : 4 = 24 : 4 = 6 \text{.}\) 1p 1p b \(3 + 4 ⋅ 5\) PositiefDrieDelen (2) 00ai - Rekenvolgorde - basis - 0ms b \(3 + 4 ⋅ 5 = 3 + 20 = 23 \text{.}\) 1p 1p c \((7 + 9) ⋅ 6\) PositiefDrieDelen (3) 00aj - Rekenvolgorde - basis - 0ms c \((7 + 9) ⋅ 6 = 16 ⋅ 6 = 96 \text{.}\) 1p 1p d \(36 : 4 ⋅ 8\) PositiefDrieDelen (4) 00ak - Rekenvolgorde - basis - 0ms d \(36 : 4 ⋅ 8 = 9 ⋅ 8 = 72 \text{.}\) 1p opgave 2Bereken. 1p a \(8 - 35 : 5\) PositiefDrieDelen (5) 00al - Rekenvolgorde - basis - 0ms a \(8 - 35 : 5 = 8 - 7 = 1 \text{.}\) 1p 1p b \(8 + 2 ⋅ (4 + 6)\) PositiefVierDelen (1) 00am - Rekenvolgorde - basis - 0ms b \(8 + 2 ⋅ (4 + 6) = 8 + 2 ⋅ 10 = 8 + 20 = 28 \text{.}\) 1p 1p c \((2 + 9) ⋅ (7 + 6)\) PositiefVierDelen (2) 00an - Rekenvolgorde - basis - 0ms c \((2 + 9) ⋅ (7 + 6) = 11 ⋅ 13 = 143 \text{.}\) 1p 1p d \(19 - 5 ⋅ 2 + 8\) PositiefVierDelen (3) 00ao - Rekenvolgorde - basis - 0ms d \(19 - 5 ⋅ 2 + 8 = 19 - 10 + 8 = 9 + 8 = 17 \text{.}\) 1p opgave 3Bereken. 1p \((18 - (9 + 2)) ⋅ 5\) PositiefVierDelen (4) 00ap - Rekenvolgorde - basis - 0ms ○ \((18 - (9 + 2)) ⋅ 5 = (18 - 11) ⋅ 5 = 7 ⋅ 5 = 35 \text{.}\) 1p |