Getal & Ruimte (13e editie) - 1 vwo
'Rekenvolgorde'.
| 1 vwo | 2.1 Bewerkingen |
opgave 1Bereken. 1p a \(24 : 3 : 2\) PositiefDrieDelen (1) 00ah - Rekenvolgorde - basis - 1ms a \(24 : 3 : 2 = 8 : 2 = 4 \text{.}\) 1p 1p b \(8 + 2 ⋅ 3\) PositiefDrieDelen (2) 00ai - Rekenvolgorde - basis - 1ms b \(8 + 2 ⋅ 3 = 8 + 6 = 14 \text{.}\) 1p 1p c \((4 + 6) ⋅ 5\) PositiefDrieDelen (3) 00aj - Rekenvolgorde - basis - 0ms c \((4 + 6) ⋅ 5 = 10 ⋅ 5 = 50 \text{.}\) 1p 1p d \(10 : 2 ⋅ 9\) PositiefDrieDelen (4) 00ak - Rekenvolgorde - basis - 0ms d \(10 : 2 ⋅ 9 = 5 ⋅ 9 = 45 \text{.}\) 1p opgave 2Bereken. 1p a \(9 - 56 : 7\) PositiefDrieDelen (5) 00al - Rekenvolgorde - basis - 0ms a \(9 - 56 : 7 = 9 - 8 = 1 \text{.}\) 1p 1p b \(4 + 2 ⋅ (5 + 6)\) PositiefVierDelen (1) 00am - Rekenvolgorde - basis - 0ms b \(4 + 2 ⋅ (5 + 6) = 4 + 2 ⋅ 11 = 4 + 22 = 26 \text{.}\) 1p 1p c \((6 + 9) ⋅ (5 + 7)\) PositiefVierDelen (2) 00an - Rekenvolgorde - basis - 0ms c \((6 + 9) ⋅ (5 + 7) = 15 ⋅ 12 = 180 \text{.}\) 1p 1p d \(39 - 4 ⋅ 8 + 6\) PositiefVierDelen (3) 00ao - Rekenvolgorde - basis - 0ms d \(39 - 4 ⋅ 8 + 6 = 39 - 32 + 6 = 7 + 6 = 13 \text{.}\) 1p opgave 3Bereken. 1p \((17 - (2 + 9)) ⋅ 4\) PositiefVierDelen (4) 00ap - Rekenvolgorde - basis - 0ms ○ \((17 - (2 + 9)) ⋅ 4 = (17 - 11) ⋅ 4 = 6 ⋅ 4 = 24 \text{.}\) 1p |