Getal & Ruimte (13e editie) - 1 vwo
'Rekenvolgorde'.
| 1 vwo | 2.1 Bewerkingen |
opgave 1Bereken. 1p a \(72 : 4 : 3\) PositiefDrieDelen (1) 00ah - Rekenvolgorde - basis - 0ms a \(72 : 4 : 3 = 18 : 3 = 6 \text{.}\) 1p 1p b \(9 + 3 ⋅ 5\) PositiefDrieDelen (2) 00ai - Rekenvolgorde - basis - 0ms b \(9 + 3 ⋅ 5 = 9 + 15 = 24 \text{.}\) 1p 1p c \((6 + 8) ⋅ 9\) PositiefDrieDelen (3) 00aj - Rekenvolgorde - basis - 0ms c \((6 + 8) ⋅ 9 = 14 ⋅ 9 = 126 \text{.}\) 1p 1p d \(54 : 9 ⋅ 4\) PositiefDrieDelen (4) 00ak - Rekenvolgorde - basis - 0ms d \(54 : 9 ⋅ 4 = 6 ⋅ 4 = 24 \text{.}\) 1p opgave 2Bereken. 1p a \(9 - 8 : 2\) PositiefDrieDelen (5) 00al - Rekenvolgorde - basis - 0ms a \(9 - 8 : 2 = 9 - 4 = 5 \text{.}\) 1p 1p b \(3 + 8 ⋅ (9 + 5)\) PositiefVierDelen (1) 00am - Rekenvolgorde - basis - 0ms b \(3 + 8 ⋅ (9 + 5) = 3 + 8 ⋅ 14 = 3 + 112 = 115 \text{.}\) 1p 1p c \((9 + 3) ⋅ (2 + 7)\) PositiefVierDelen (2) 00an - Rekenvolgorde - basis - 0ms c \((9 + 3) ⋅ (2 + 7) = 12 ⋅ 9 = 108 \text{.}\) 1p 1p d \(59 - 8 ⋅ 7 + 2\) PositiefVierDelen (3) 00ao - Rekenvolgorde - basis - 0ms d \(59 - 8 ⋅ 7 + 2 = 59 - 56 + 2 = 3 + 2 = 5 \text{.}\) 1p opgave 3Bereken. 1p \((15 - (7 + 5)) ⋅ 4\) PositiefVierDelen (4) 00ap - Rekenvolgorde - basis - 0ms ○ \((15 - (7 + 5)) ⋅ 4 = (15 - 12) ⋅ 4 = 3 ⋅ 4 = 12 \text{.}\) 1p |