Getal & Ruimte (13e editie) - 1 havo/vwo
'Rekenvolgorde'.
| 1 havo/vwo | 2.1 Bewerkingen |
opgave 1Bereken. 1p a \(24 : 4 : 3\) PositiefDrieDelen (1) 00ah - Rekenvolgorde - basis - 0ms a \(24 : 4 : 3 = 6 : 3 = 2 \text{.}\) 1p 1p b \(7 + 3 ⋅ 2\) PositiefDrieDelen (2) 00ai - Rekenvolgorde - basis - 0ms b \(7 + 3 ⋅ 2 = 7 + 6 = 13 \text{.}\) 1p 1p c \((7 + 9) ⋅ 4\) PositiefDrieDelen (3) 00aj - Rekenvolgorde - basis - 0ms c \((7 + 9) ⋅ 4 = 16 ⋅ 4 = 64 \text{.}\) 1p 1p d \(36 : 9 ⋅ 2\) PositiefDrieDelen (4) 00ak - Rekenvolgorde - basis - 0ms d \(36 : 9 ⋅ 2 = 4 ⋅ 2 = 8 \text{.}\) 1p opgave 2Bereken. 1p a \(9 - 40 : 5\) PositiefDrieDelen (5) 00al - Rekenvolgorde - basis - 0ms a \(9 - 40 : 5 = 9 - 8 = 1 \text{.}\) 1p 1p b \(7 + 5 ⋅ (2 + 3)\) PositiefVierDelen (1) 00am - Rekenvolgorde - basis - 0ms b \(7 + 5 ⋅ (2 + 3) = 7 + 5 ⋅ 5 = 7 + 25 = 32 \text{.}\) 1p 1p c \((2 + 3) ⋅ (7 + 4)\) PositiefVierDelen (2) 00an - Rekenvolgorde - basis - 0ms c \((2 + 3) ⋅ (7 + 4) = 5 ⋅ 11 = 55 \text{.}\) 1p 1p d \(14 - 5 ⋅ 2 + 3\) PositiefVierDelen (3) 00ao - Rekenvolgorde - basis - 0ms d \(14 - 5 ⋅ 2 + 3 = 14 - 10 + 3 = 4 + 3 = 7 \text{.}\) 1p opgave 3Bereken. 1p \((16 - (5 + 3)) ⋅ 6\) PositiefVierDelen (4) 00ap - Rekenvolgorde - basis - 0ms ○ \((16 - (5 + 3)) ⋅ 6 = (16 - 8) ⋅ 6 = 8 ⋅ 6 = 48 \text{.}\) 1p |