Getal & Ruimte (13e editie) - 1 havo/vwo
'Rekenvolgorde'.
| 1 havo/vwo | 2.1 Bewerkingen |
opgave 1Bereken. 1p a \(120 : 5 : 3\) PositiefDrieDelen (1) 00ah - Rekenvolgorde - basis - 0ms a \(120 : 5 : 3 = 24 : 3 = 8 \text{.}\) 1p 1p b \(5 + 2 ⋅ 3\) PositiefDrieDelen (2) 00ai - Rekenvolgorde - basis - 0ms b \(5 + 2 ⋅ 3 = 5 + 6 = 11 \text{.}\) 1p 1p c \((2 + 4) ⋅ 3\) PositiefDrieDelen (3) 00aj - Rekenvolgorde - basis - 0ms c \((2 + 4) ⋅ 3 = 6 ⋅ 3 = 18 \text{.}\) 1p 1p d \(14 : 2 ⋅ 3\) PositiefDrieDelen (4) 00ak - Rekenvolgorde - basis - 0ms d \(14 : 2 ⋅ 3 = 7 ⋅ 3 = 21 \text{.}\) 1p opgave 2Bereken. 1p a \(7 - 6 : 2\) PositiefDrieDelen (5) 00al - Rekenvolgorde - basis - 0ms a \(7 - 6 : 2 = 7 - 3 = 4 \text{.}\) 1p 1p b \(9 + 3 ⋅ (5 + 2)\) PositiefVierDelen (1) 00am - Rekenvolgorde - basis - 0ms b \(9 + 3 ⋅ (5 + 2) = 9 + 3 ⋅ 7 = 9 + 21 = 30 \text{.}\) 1p 1p c \((2 + 4) ⋅ (8 + 3)\) PositiefVierDelen (2) 00an - Rekenvolgorde - basis - 0ms c \((2 + 4) ⋅ (8 + 3) = 6 ⋅ 11 = 66 \text{.}\) 1p 1p d \(35 - 9 ⋅ 3 + 2\) PositiefVierDelen (3) 00ao - Rekenvolgorde - basis - 0ms d \(35 - 9 ⋅ 3 + 2 = 35 - 27 + 2 = 8 + 2 = 10 \text{.}\) 1p opgave 3Bereken. 1p \((17 - (6 + 3)) ⋅ 2\) PositiefVierDelen (4) 00ap - Rekenvolgorde - basis - 0ms ○ \((17 - (6 + 3)) ⋅ 2 = (17 - 9) ⋅ 2 = 8 ⋅ 2 = 16 \text{.}\) 1p |