Getal & Ruimte (13e editie) - 1 havo/vwo
'Rekenvolgorde'.
| 1 havo/vwo | 2.1 Bewerkingen |
opgave 1Bereken. 1p a \(135 : 5 : 3\) PositiefDrieDelen (1) 00ah - Rekenvolgorde - basis - 0ms a \(135 : 5 : 3 = 27 : 3 = 9 \text{.}\) 1p 1p b \(9 + 6 ⋅ 2\) PositiefDrieDelen (2) 00ai - Rekenvolgorde - basis - 0ms b \(9 + 6 ⋅ 2 = 9 + 12 = 21 \text{.}\) 1p 1p c \((5 + 6) ⋅ 2\) PositiefDrieDelen (3) 00aj - Rekenvolgorde - basis - 0ms c \((5 + 6) ⋅ 2 = 11 ⋅ 2 = 22 \text{.}\) 1p 1p d \(12 : 3 ⋅ 6\) PositiefDrieDelen (4) 00ak - Rekenvolgorde - basis - 0ms d \(12 : 3 ⋅ 6 = 4 ⋅ 6 = 24 \text{.}\) 1p opgave 2Bereken. 1p a \(9 - 24 : 3\) PositiefDrieDelen (5) 00al - Rekenvolgorde - basis - 0ms a \(9 - 24 : 3 = 9 - 8 = 1 \text{.}\) 1p 1p b \(7 + 5 ⋅ (4 + 8)\) PositiefVierDelen (1) 00am - Rekenvolgorde - basis - 0ms b \(7 + 5 ⋅ (4 + 8) = 7 + 5 ⋅ 12 = 7 + 60 = 67 \text{.}\) 1p 1p c \((9 + 6) ⋅ (3 + 5)\) PositiefVierDelen (2) 00an - Rekenvolgorde - basis - 0ms c \((9 + 6) ⋅ (3 + 5) = 15 ⋅ 8 = 120 \text{.}\) 1p 1p d \(77 - 9 ⋅ 8 + 6\) PositiefVierDelen (3) 00ao - Rekenvolgorde - basis - 0ms d \(77 - 9 ⋅ 8 + 6 = 77 - 72 + 6 = 5 + 6 = 11 \text{.}\) 1p opgave 3Bereken. 1p \((15 - (3 + 7)) ⋅ 9\) PositiefVierDelen (4) 00ap - Rekenvolgorde - basis - 0ms ○ \((15 - (3 + 7)) ⋅ 9 = (15 - 10) ⋅ 9 = 5 ⋅ 9 = 45 \text{.}\) 1p |