Getal & Ruimte (13e editie) - 1 havo/vwo
'Rekenvolgorde'.
| 1 havo/vwo | 2.1 Bewerkingen |
opgave 1Bereken. 1p a \(144 : 6 : 3\) PositiefDrieDelen (1) 00ah - Rekenvolgorde - basis - 1ms a \(144 : 6 : 3 = 24 : 3 = 8 \text{.}\) 1p 1p b \(5 + 6 ⋅ 4\) PositiefDrieDelen (2) 00ai - Rekenvolgorde - basis - 1ms b \(5 + 6 ⋅ 4 = 5 + 24 = 29 \text{.}\) 1p 1p c \((6 + 4) ⋅ 5\) PositiefDrieDelen (3) 00aj - Rekenvolgorde - basis - 0ms c \((6 + 4) ⋅ 5 = 10 ⋅ 5 = 50 \text{.}\) 1p 1p d \(48 : 6 ⋅ 2\) PositiefDrieDelen (4) 00ak - Rekenvolgorde - basis - 0ms d \(48 : 6 ⋅ 2 = 8 ⋅ 2 = 16 \text{.}\) 1p opgave 2Bereken. 1p a \(8 - 6 : 2\) PositiefDrieDelen (5) 00al - Rekenvolgorde - basis - 0ms a \(8 - 6 : 2 = 8 - 3 = 5 \text{.}\) 1p 1p b \(4 + 2 ⋅ (8 + 6)\) PositiefVierDelen (1) 00am - Rekenvolgorde - basis - 0ms b \(4 + 2 ⋅ (8 + 6) = 4 + 2 ⋅ 14 = 4 + 28 = 32 \text{.}\) 1p 1p c \((6 + 4) ⋅ (5 + 9)\) PositiefVierDelen (2) 00an - Rekenvolgorde - basis - 0ms c \((6 + 4) ⋅ (5 + 9) = 10 ⋅ 14 = 140 \text{.}\) 1p 1p d \(31 - 3 ⋅ 9 + 7\) PositiefVierDelen (3) 00ao - Rekenvolgorde - basis - 0ms d \(31 - 3 ⋅ 9 + 7 = 31 - 27 + 7 = 4 + 7 = 11 \text{.}\) 1p opgave 3Bereken. 1p \((18 - (9 + 5)) ⋅ 3\) PositiefVierDelen (4) 00ap - Rekenvolgorde - basis - 0ms ○ \((18 - (9 + 5)) ⋅ 3 = (18 - 14) ⋅ 3 = 4 ⋅ 3 = 12 \text{.}\) 1p |