Optellen geeft \(4 x = 2 \text{,}\) dus \(x = \frac{1}{2} \text{.}\)

\(\begin{rcases}3 x - 3 y = 3 \\ x = \frac{1}{2}\end{rcases} \begin{matrix}3 ⋅ \frac{1}{2} - 3 y = 3 \\ -3 y = 1\frac{1}{2} \\ y = -\frac{1}{2}\end{matrix}\)

De oplossing is \((x , y) = (\frac{1}{2} , -\frac{1}{2}) \text{.}\)

\(\begin{cases}3 a + 6 b = -6 \\ a + b = 1\end{cases}\) \(\begin{vmatrix}1 \\ 6\end{vmatrix}\) geeft \(\begin{cases}3 a + 6 b = -6 \\ 6 a + 6 b = 6\end{cases}\)

Aftrekken geeft \(-3 a = -12 \text{,}\) dus \(a = 4 \text{.}\)

\(\begin{rcases}3 a + 6 b = -6 \\ a = 4\end{rcases} \begin{matrix}3 ⋅ 4 + 6 b = -6 \\ 6 b = -18 \\ b = -3\end{matrix}\)

De oplossing is \((a , b) = (4 , -3) \text{.}\)

\(\begin{cases}4 x - 3 y = 2 \\ 3 x - 2 y = -4\end{cases}\) \(\begin{vmatrix}2 \\ 3\end{vmatrix}\) geeft \(\begin{cases}8 x - 6 y = 4 \\ 9 x - 6 y = -12\end{cases}\)

Aftrekken geeft \(-x = 16 \text{,}\) dus \(x = -16 \text{.}\)

\(\begin{rcases}4 x - 3 y = 2 \\ x = -16\end{rcases} \begin{matrix}4 ⋅ -16 - 3 y = 2 \\ -3 y = 66 \\ y = -22\end{matrix}\)

De oplossing is \((x , y) = (-16 , -22) \text{.}\)