Getal & Ruimte (12e editie) - vwo wiskunde C
'Breuken herleiden'.
| 1 vwo | 6.6 Herleiden van breuken |
opgave 1Herleid tot één breuk. 1p a \({5 \over 6 x} - {3 \over 6 x}\) Optellen (1) 008u - Breuken herleiden - basis - 0ms - dynamic variables a \({5 \over 6 x} - {3 \over 6 x} = {2 \over 6 x} = {1 \over 3 x}\) 1p 1p b \({7 \over x} + {5 \over 6 x}\) Optellen (2) 008v - Breuken herleiden - basis - 0ms - dynamic variables b \({7 \over x} + {5 \over 6 x} = {42 \over 6 x} + {5 \over 6 x} = {47 \over 6 x}\) 1p 1p c \({7 \over 6 p} + {4 \over 8 q}\) Optellen (3) 008w - Breuken herleiden - basis - 0ms - dynamic variables c \({7 \over 6 p} + {4 \over 8 q} = {28 q \over 24 p q} + {12 p \over 24 p q} = {28 q + 12 p \over 24 p q} = {7 q + 3 p \over 6 p q}\) 1p 1p d \(5 - {7 \over 6 a}\) Optellen (4) 008x - Breuken herleiden - basis - 0ms - dynamic variables d \(5 - {7 \over 6 a} = {5 \over 1} - {7 \over 6 a} = {30 a \over 6 a} - {7 \over 6 a} = {30 a - 7 \over 6 a}\) 1p opgave 2Herleid tot één breuk. 1p \({4 a \over b} - {3 \over 9 b}\) Optellen (6) 008z - Breuken herleiden - basis - 0ms - dynamic variables ○ \({4 a \over b} - {3 \over 9 b} = {36 a \over 9 b} - {3 \over 9 b} = {36 a - 3 \over 9 b} = {12 a - 1 \over 3 b}\) 1p opgave 3Herleid. 1p a \({5 a \over a}\) Vereenvoudigen (1) 00h5 - Breuken herleiden - basis - 0ms - dynamic variables a \({5 a \over a} = {5 \over 1} = 5\) 1p 1p b \({x \over 7 x}\) Vereenvoudigen (2) 00h6 - Breuken herleiden - basis - 0ms - dynamic variables b \({x \over 7 x} = {1 \over 7}\) 1p 1p c \({9 x \over 15 x}\) Vereenvoudigen (3) 00h7 - Breuken herleiden - basis - 0ms - dynamic variables c \({9 x \over 15 x} = \frac{3}{5}\) 1p 1p d \({-24 a \over -4 a}\) Vereenvoudigen (4) 00h8 - Breuken herleiden - basis - 0ms - dynamic variables d \({-24 a \over -4 a} = 6\) 1p opgave 4Herleid. 1p a \({10 p q \over -12 p r}\) Vereenvoudigen (5) 00h9 - Breuken herleiden - basis - 0ms - dynamic variables a \({10 p q \over -12 p r} = -{5 q \over 6 r}\) 1p 1p b \({6 y \over 15 x y}\) Vereenvoudigen (6) 00ha - Breuken herleiden - basis - 0ms - dynamic variables b \({6 y \over 15 x y} = {2 \over 5 x}\) 1p 1p c \({8 a b c \over -2 b c}\) Vereenvoudigen (7) 00hb - Breuken herleiden - basis - 0ms - dynamic variables c \({8 a b c \over -2 b c} = -4 a\) 1p 1p d \({4 x y \over y} - {5 x z \over z}\) Vereenvoudigen (8) 00hc - Breuken herleiden - basis - 0ms - dynamic variables d \({4 x y \over y} - {5 x z \over z} = 4 x - 5 x = -x\) 1p |
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| 2 vwo | 1.2 Herleiden van breuken |
opgave 1Herleid tot één breuk. 1p a \(4 p - {9 \over 5 p}\) Optellen (5) 008y - Breuken herleiden - basis - 0ms - dynamic variables a \(4 p - {9 \over 5 p} = {4 p \over 1} ⋅ {5 p \over 5 p} - {9 \over 5 p} = {20 p^{2} \over 5 p} - {9 \over 5 p} = {20 p^{2} - 9 \over 5 p}\) 1p 1p b \({8 b \over 3 a} + {7 a \over 2 b}\) Optellen (7) 0090 - Breuken herleiden - basis - 0ms - dynamic variables b \({8 b \over 3 a} + {7 a \over 2 b} = {16 b^{2} \over 6 a b} + {21 a^{2} \over 6 a b} = {21 a^{2} + 16 b^{2} \over 6 a b}\) 1p 1p c \({8 \over x} ⋅ -{3 \over y}\) Vermenigvuldiging (1) 0091 - Breuken herleiden - basis - 0ms - dynamic variables c \({8 \over x} ⋅ -{3 \over y} = -{24 \over x y}\) 1p 1p d \({x \over 6} ⋅ -{2 \over y}\) Vermenigvuldiging (2) 0092 - Breuken herleiden - basis - 0ms - dynamic variables d \({x \over 6} ⋅ -{2 \over y} = -{2 x \over 6 y} = -{x \over 3 y}\) 1p opgave 2Herleid tot één breuk. 1p a \(-{5 \over 3} ⋅ a\) Vermenigvuldiging (3) 0093 - Breuken herleiden - basis - 0ms - dynamic variables a \(-{5 \over 3} ⋅ a = -{5 a \over 3}\) 1p 1p b \({5 y \over x} ⋅ {x + 7 \over 6}\) Vermenigvuldiging (4) 0094 - Breuken herleiden - basis - 0ms - dynamic variables b \({5 y \over x} ⋅ {x + 7 \over 6} = {5 y (x + 7) \over 6 x} = {5 x y + 35 y \over 6 x}\) 1p 1p c \({2 \over a} : {3 \over b}\) Deling (1) 0095 - Breuken herleiden - basis - 0ms - dynamic variables c \({2 \over a} : {3 \over b} = {2 \over a} ⋅ {b \over 3} = {2 b \over 3 a}\) 1p 1p d \({9 \over 7} : x\) Deling (2) 0096 - Breuken herleiden - basis - 0ms - dynamic variables d \({9 \over 7} : x = {9 \over 7} : {x \over 1} = {9 \over 7} ⋅ {1 \over x} = {9 \over 7 x}\) 1p opgave 3Herleid tot één breuk. 1p a \({9 \over 4} : {p + 6 q \over q}\) Deling (3) 0097 - Breuken herleiden - basis - 0ms - dynamic variables a \({9 \over 4} : {p + 6 q \over q} = {9 \over 4} ⋅ {q \over p + 6 q} = {9 q \over 4 (p + 6 q)} = {9 q \over 4 p + 24 q}\) 1p 1p b \({8 a \over 7} + {a + 5 \over 6}\) Optellen (8) 0098 - Breuken herleiden - basis - 0ms - dynamic variables b \({8 a \over 7} + {a + 5 \over 6} = {48 a \over 42} + {7 (a + 5) \over 42} = {48 a + 7 (a + 5) \over 42} = {55 a + 35 \over 42}\) 1p |
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| 3 vwo | 5.3 Breuken met letters herleiden |
opgave 1Herleid tot één breuk. 1p \({7 p + 1 \over -6 p + 5} - 2\) Optellen (9) 00eh - Breuken herleiden - basis - 1ms - dynamic variables ○ \({7 p + 1 \over -6 p + 5} - 2 = {7 p + 1 \over -6 p + 5} + {-2 (-6 p + 5) \over -6 p + 5} = {7 p + 1 - 2 (-6 p + 5) \over -6 p + 5} = {7 p + 1 + 12 p - 10 \over -6 p + 5} = {19 p - 9 \over -6 p + 5}\) 1p |