\({7 \over 8 p} + {4 \over 8 p} = {11 \over 8 p}\)

\({2 \over x} - {4 \over 9 x} = {18 \over 9 x} - {4 \over 9 x} = {14 \over 9 x}\)

\({7 \over 9 x} + {5 \over 3 y} = {7 y \over 9 x y} + {15 x \over 9 x y} = {7 y + 15 x \over 9 x y}\)

\(2 - {3 \over 4 a} = {2 \over 1} - {3 \over 4 a} = {8 a \over 4 a} - {3 \over 4 a} = {8 a - 3 \over 4 a}\)

\({2 a \over b} + {6 \over 5 b} = {10 a \over 5 b} + {6 \over 5 b} = {10 a + 6 \over 5 b}\)

\({9 x \over x} = {9 \over 1} = 9\)

\({p \over 6 p} = {1 \over 6}\)

\({8 x \over 12 x} = \frac{2}{3}\)

\({-15 a \over -3 a} = 5\)

\({-15 a b \over 27 a c} = -{5 b \over 9 c}\)

\({8 y \over 28 x y} = {2 \over 7 x}\)

\({24 x y z \over -4 y z} = -6 x\)

\({5 a b \over b} - {7 a c \over c} = 5 a - 7 a = -2 a\)

\(2 x - {7 \over 4 x} = {2 x \over 1} ⋅ {4 x \over 4 x} - {7 \over 4 x} = {8 x^{2} \over 4 x} - {7 \over 4 x} = {8 x^{2} - 7 \over 4 x}\)

\({3 b \over 4 a} - {2 a \over 9 b} = {27 b^{2} \over 36 a b} - {8 a^{2} \over 36 a b} = {-8 a^{2} + 27 b^{2} \over 36 a b}\)

\({9 \over a} ⋅ -{7 \over b} = -{63 \over a b}\)

\({p \over 3} ⋅ -{4 \over q} = -{4 p \over 3 q}\)

\({2 \over 3} ⋅ x = {2 x \over 3}\)

\({8 y \over x} ⋅ {x + 5 \over 4} = {8 y (x + 5) \over 4 x} = {2 y (x + 5) \over x} = {2 x y + 10 y \over x}\)

\({6 \over a} : {4 \over b} = {6 \over a} ⋅ {b \over 4} = {6 b \over 4 a} = {3 b \over 2 a}\)

\(-{4 \over 3} : x = -{4 \over 3} : {x \over 1} = -{4 \over 3} ⋅ {1 \over x} = -{4 \over 3 x}\)

\({2 \over 9} : {a - b \over b} = {2 \over 9} ⋅ {b \over a - b} = {2 b \over 9 (a - b)} = {2 b \over 9 a - 9 b}\)

\({2 p \over 3} + {p - 6 \over 5} = {10 p \over 15} + {3 (p - 6) \over 15} = {10 p + 3 (p - 6) \over 15} = {13 p - 18 \over 15}\)

\({-4 p + 5 \over 2 p + 3} - 7 = {-4 p + 5 \over 2 p + 3} - {7 (2 p + 3) \over 2 p + 3} = {-4 p + 5 - 7 (2 p + 3) \over 2 p + 3} = {-4 p + 5 - 14 p - 21 \over 2 p + 3} = {-18 p - 16 \over 2 p + 3}\)