\({6 \over 5 a} + {4 \over 5 a} = {10 \over 5 a} = {2 \over a}\)

\({8 \over p} - {9 \over 3 p} = {24 \over 3 p} - {9 \over 3 p} = {15 \over 3 p} = {5 \over p}\)

\({3 \over 9 a} + {5 \over 2 b} = {6 b \over 18 a b} + {45 a \over 18 a b} = {6 b + 45 a \over 18 a b} = {2 b + 15 a \over 6 a b}\)

\(9 + {8 \over 7 x} = {9 \over 1} + {8 \over 7 x} = {63 x \over 7 x} + {8 \over 7 x} = {63 x + 8 \over 7 x}\)

\({8 x \over y} - {7 \over 9 y} = {72 x \over 9 y} - {7 \over 9 y} = {72 x - 7 \over 9 y}\)

\({4 p \over p} = {4 \over 1} = 4\)

\({a \over 9 a} = {1 \over 9}\)

\({-10 x \over -14 x} = \frac{5}{7}\)

\({-16 x \over -2 x} = 8\)

\({-16 a b \over 36 a c} = -{4 b \over 9 c}\)

\({21 y \over -24 x y} = -{7 \over 8 x}\)

\({-12 x y z \over 3 y z} = -4 x\)

\({6 a b \over b} + {4 a c \over c} = 6 a + 4 a = 10 a\)

\(4 x - {2 \over 5 x} = {4 x \over 1} ⋅ {5 x \over 5 x} - {2 \over 5 x} = {20 x^{2} \over 5 x} - {2 \over 5 x} = {20 x^{2} - 2 \over 5 x}\)

\({5 b \over 6 a} + {7 a \over 9 b} = {15 b^{2} \over 18 a b} + {14 a^{2} \over 18 a b} = {14 a^{2} + 15 b^{2} \over 18 a b}\)

\({6 \over p} ⋅ -{9 \over q} = -{54 \over p q}\)

\({x \over 2} ⋅ -{8 \over y} = -{8 x \over 2 y} = -{4 x \over y}\)

\(-{2 \over 9} ⋅ a = -{2 a \over 9}\)

\({2 b \over a} ⋅ {a + 3 \over 8} = {2 b (a + 3) \over 8 a} = {b (a + 3) \over 4 a} = {a b + 3 b \over 4 a}\)

\({4 \over x} : {7 \over y} = {4 \over x} ⋅ {y \over 7} = {4 y \over 7 x}\)

\({6 \over 7} : a = {6 \over 7} : {a \over 1} = {6 \over 7} ⋅ {1 \over a} = {6 \over 7 a}\)

\(-{1 \over 7} : {x - 9 y \over y} = -{1 \over 7} ⋅ {y \over x - 9 y} = -{y \over 7 (x - 9 y)} = -{y \over 7 x - 63 y}\)

\({3 p \over 2} + {p + 5 \over 9} = {27 p \over 18} + {2 (p + 5) \over 18} = {27 p + 2 (p + 5) \over 18} = {29 p + 10 \over 18}\)

\({6 a + 3 \over 2 a + 5} + 4 = {6 a + 3 \over 2 a + 5} + {4 (2 a + 5) \over 2 a + 5} = {6 a + 3 + 4 (2 a + 5) \over 2 a + 5} = {6 a + 3 + 8 a + 20 \over 2 a + 5} = {14 a + 23 \over 2 a + 5}\)