\({4 \over 8x}+{9 \over 8x}={13 \over 8x}\)

\({6 \over x}+{5 \over 2x}={12 \over 2x}+{5 \over 2x}={17 \over 2x}\)

\({8 \over 2a}+{4 \over 5b}={40b \over 10ab}+{8a \over 10ab}={40b+8a \over 10ab}={20b+4a \over 5ab}\)

\(2+{5 \over 9p}={2 \over 1}+{5 \over 9p}={18p \over 9p}+{5 \over 9p}={18p+5 \over 9p}\)

\({5a \over b}-{2 \over 4b}={20a \over 4b}-{2 \over 4b}={20a-2 \over 4b}={10a-1 \over 2b}\)

\({8x \over x}={8 \over 1}=8\)

\({x \over 3x}={1 \over 3}\)

\({20p \over 35p}=\frac{4}{7}\)

\({-25a \over -5a}=5\)

\({-10ab \over -14ac}={5b \over 7c}\)

\({6b \over -10ab}=-{3 \over 5a}\)

\({-35xyz \over 5yz}=-7x\)

\({7ab \over b}-{6ac \over c}=7a-6a=a\)

\(7p-{5 \over 8p}={7p \over 1}⋅{8p \over 8p}-{5 \over 8p}={56p^2 \over 8p}-{5 \over 8p}={56p^2-5 \over 8p}\)

\({6y \over 4x}-{8x \over 3y}={18y^2 \over 12xy}-{32x^2 \over 12xy}={-32x^2+18y^2 \over 12xy}={-16x^2+9y^2 \over 6xy}\)

\({3 \over x}⋅-{6 \over y}=-{18 \over xy}\)

\({a \over 2}⋅-{7 \over b}=-{7a \over 2b}\)

\({2 \over 5}⋅a={2a \over 5}\)

\({3q \over p}⋅{p-5 \over 6}={3q(p-5) \over 6p}={q(p-5) \over 2p}={pq-5q \over 2p}\)

\({7 \over a}:{6 \over b}={7 \over a}⋅{b \over 6}={7b \over 6a}\)

\({1 \over 8}:a={1 \over 8}:{a \over 1}={1 \over 8}⋅{1 \over a}={1 \over 8a}\)

\({6 \over 7}:{x-9y \over y}={6 \over 7}⋅{y \over x-9y}={6y \over 7(x-9y)}={6y \over 7x-63y}\)

\({9x \over 4}+{x-3 \over 7}={63x \over 28}+{4(x-3) \over 28}={63x+4(x-3) \over 28}={67x-12 \over 28}\)

\({6a-5 \over 7a-3}+1={6a-5 \over 7a-3}+{1(7a-3) \over 7a-3}={6a-5+1(7a-3) \over 7a-3}={6a-5+7a-3 \over 7a-3}={13a-8 \over 7a-3}\)