Getal & Ruimte (12e editie) - vwo wiskunde B

'Wortels vereenvoudigen'.

2 vwo 5.3 Wortels herleiden

Wortels vereenvoudigen (5)

opgave 1

Herleid.

2p

a

\(\sqrt{200}+\sqrt{8}\)

Optellen (5)
0085 - Wortels vereenvoudigen - basis - 0ms

a

\(\sqrt{200}+\sqrt{8}=\sqrt{100}⋅\sqrt{2}+\sqrt{4}⋅\sqrt{2}=10\sqrt{2}+2\sqrt{2}\text{.}\)

1p

\(10\sqrt{2}+2\sqrt{2}=12\sqrt{2}\text{.}\)

1p

1p

b

\(\sqrt{18}\)

FactorVoorWortelteken (1)
0086 - Wortels vereenvoudigen - basis - 0ms

b

\(\sqrt{18}=\sqrt{9}⋅\sqrt{2}=3\sqrt{2}\text{.}\)

1p

1p

c

\(6\sqrt{8}\)

FactorVoorWortelteken (2)
0087 - Wortels vereenvoudigen - basis - 0ms

c

\(6\sqrt{8}=6⋅\sqrt{4}⋅\sqrt{2}=6⋅2⋅\sqrt{2}=12\sqrt{2}\text{.}\)

1p

2p

d

\(3\sqrt{18}+5\sqrt{32}\)

Optellen (6)
0088 - Wortels vereenvoudigen - basis - 1ms

d

\(3\sqrt{18}+5\sqrt{32}=3⋅\sqrt{9}⋅\sqrt{2}+5⋅\sqrt{16}⋅\sqrt{2}\text{.}\)

1p

\(3⋅3⋅\sqrt{2}+5⋅4⋅\sqrt{2}=9\sqrt{2}+20\sqrt{2}=29\sqrt{2}\text{.}\)

1p

opgave 2

Herleid.

1p

\(\sqrt{\frac{4}{49}}\)

BreukInWortel (1)
008b - Wortels vereenvoudigen - basis - 68ms

\(\sqrt{\frac{4}{49}}={\sqrt{4} \over \sqrt{49}}=\frac{2}{7}\text{.}\)

1p

3 vwo 5.5 Wortels herleiden

Wortels vereenvoudigen (6)

opgave 1

Herleid.

1p

a

\({2 \over 9\sqrt{7}}\)

WortelInNoemer
0089 - Wortels vereenvoudigen - basis - 1ms

a

\({2 \over 9\sqrt{7}}={2 \over 9\sqrt{7}}⋅{\sqrt{7} \over \sqrt{7}}={2\sqrt{7} \over 9⋅7}=\frac{2}{63}\sqrt{7}\text{.}\)

1p

1p

b

\(\sqrt{4\frac{1}{16}}\)

BreukInWortel (2)
008c - Wortels vereenvoudigen - basis - 1ms

b

\(\sqrt{4\frac{1}{16}}=\sqrt{\frac{65}{16}}={\sqrt{65} \over \sqrt{16}}={\sqrt{65} \over 4}=\frac{1}{4}\sqrt{65}\text{.}\)

1p

1p

c

\(\sqrt{\frac{9}{41}}\)

BreukInWortel (3)
008d - Wortels vereenvoudigen - basis - 1ms

c

\(\sqrt{\frac{9}{41}}={\sqrt{9} \over \sqrt{41}}={3 \over \sqrt{41}}⋅{\sqrt{41} \over \sqrt{41}}={3\sqrt{41} \over 41}=\frac{3}{41}\sqrt{41}\text{.}\)

1p

1p

d

\(\sqrt{6\frac{2}{3}}\)

BreukInWortel (4)
008e - Wortels vereenvoudigen - basis - 1ms

d

\(\sqrt{6\frac{2}{3}}=\sqrt{\frac{20}{3}}={\sqrt{20} \over \sqrt{3}}⋅{\sqrt{3} \over \sqrt{3}}={\sqrt{60} \over 3}=\frac{1}{3}\sqrt{60}=\frac{1}{3}⋅2⋅\sqrt{15}=\frac{2}{3}\sqrt{15}\text{.}\)

1p

opgave 2

Herleid.

1p

a

\({42\sqrt{72} \over 6\sqrt{3}}\)

Delen (4)
00dc - Wortels vereenvoudigen - basis - 10ms

a

\({42\sqrt{72} \over 6\sqrt{3}}={42 \over 6}⋅{\sqrt{72} \over \sqrt{3}}=7\sqrt{24}=7⋅\sqrt{4}⋅\sqrt{6}=7⋅2⋅\sqrt{6}=14\sqrt{6}\)

1p

1p

b

\(3\sqrt{14}⋅4\sqrt{7}\)

Vermenigvuldigen (5)
00dd - Wortels vereenvoudigen - basis - 3ms - data pool: #22 (3ms)

b

\(3\sqrt{14}⋅4\sqrt{7}=12\sqrt{98}=12⋅\sqrt{49}⋅\sqrt{2}=12⋅7⋅\sqrt{2}=84\sqrt{2}\)

1p

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