Getal & Ruimte (12e editie) - vwo wiskunde B
'Wortels vereenvoudigen'.
| 2 vwo | 5.3 Wortels herleiden |
opgave 1Herleid. 2p a \(\sqrt{200}+\sqrt{8}\) Optellen (5) 0085 - Wortels vereenvoudigen - basis - 0ms a \(\sqrt{200}+\sqrt{8}=\sqrt{100}⋅\sqrt{2}+\sqrt{4}⋅\sqrt{2}=10\sqrt{2}+2\sqrt{2}\text{.}\) 1p ○ \(10\sqrt{2}+2\sqrt{2}=12\sqrt{2}\text{.}\) 1p 1p b \(\sqrt{18}\) FactorVoorWortelteken (1) 0086 - Wortels vereenvoudigen - basis - 0ms b \(\sqrt{18}=\sqrt{9}⋅\sqrt{2}=3\sqrt{2}\text{.}\) 1p 1p c \(6\sqrt{8}\) FactorVoorWortelteken (2) 0087 - Wortels vereenvoudigen - basis - 0ms c \(6\sqrt{8}=6⋅\sqrt{4}⋅\sqrt{2}=6⋅2⋅\sqrt{2}=12\sqrt{2}\text{.}\) 1p 2p d \(3\sqrt{18}+5\sqrt{32}\) Optellen (6) 0088 - Wortels vereenvoudigen - basis - 1ms d \(3\sqrt{18}+5\sqrt{32}=3⋅\sqrt{9}⋅\sqrt{2}+5⋅\sqrt{16}⋅\sqrt{2}\text{.}\) 1p ○ \(3⋅3⋅\sqrt{2}+5⋅4⋅\sqrt{2}=9\sqrt{2}+20\sqrt{2}=29\sqrt{2}\text{.}\) 1p opgave 2Herleid. 1p \(\sqrt{\frac{4}{49}}\) BreukInWortel (1) 008b - Wortels vereenvoudigen - basis - 68ms ○ \(\sqrt{\frac{4}{49}}={\sqrt{4} \over \sqrt{49}}=\frac{2}{7}\text{.}\) 1p |
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| 3 vwo | 5.5 Wortels herleiden |
opgave 1Herleid. 1p a \({2 \over 9\sqrt{7}}\) WortelInNoemer 0089 - Wortels vereenvoudigen - basis - 1ms a \({2 \over 9\sqrt{7}}={2 \over 9\sqrt{7}}⋅{\sqrt{7} \over \sqrt{7}}={2\sqrt{7} \over 9⋅7}=\frac{2}{63}\sqrt{7}\text{.}\) 1p 1p b \(\sqrt{4\frac{1}{16}}\) BreukInWortel (2) 008c - Wortels vereenvoudigen - basis - 1ms b \(\sqrt{4\frac{1}{16}}=\sqrt{\frac{65}{16}}={\sqrt{65} \over \sqrt{16}}={\sqrt{65} \over 4}=\frac{1}{4}\sqrt{65}\text{.}\) 1p 1p c \(\sqrt{\frac{9}{41}}\) BreukInWortel (3) 008d - Wortels vereenvoudigen - basis - 1ms c \(\sqrt{\frac{9}{41}}={\sqrt{9} \over \sqrt{41}}={3 \over \sqrt{41}}⋅{\sqrt{41} \over \sqrt{41}}={3\sqrt{41} \over 41}=\frac{3}{41}\sqrt{41}\text{.}\) 1p 1p d \(\sqrt{6\frac{2}{3}}\) BreukInWortel (4) 008e - Wortels vereenvoudigen - basis - 1ms d \(\sqrt{6\frac{2}{3}}=\sqrt{\frac{20}{3}}={\sqrt{20} \over \sqrt{3}}⋅{\sqrt{3} \over \sqrt{3}}={\sqrt{60} \over 3}=\frac{1}{3}\sqrt{60}=\frac{1}{3}⋅2⋅\sqrt{15}=\frac{2}{3}\sqrt{15}\text{.}\) 1p opgave 2Herleid. 1p a \({42\sqrt{72} \over 6\sqrt{3}}\) Delen (4) 00dc - Wortels vereenvoudigen - basis - 10ms a \({42\sqrt{72} \over 6\sqrt{3}}={42 \over 6}⋅{\sqrt{72} \over \sqrt{3}}=7\sqrt{24}=7⋅\sqrt{4}⋅\sqrt{6}=7⋅2⋅\sqrt{6}=14\sqrt{6}\) 1p 1p b \(3\sqrt{14}⋅4\sqrt{7}\) Vermenigvuldigen (5) 00dd - Wortels vereenvoudigen - basis - 3ms - data pool: #22 (3ms) b \(3\sqrt{14}⋅4\sqrt{7}=12\sqrt{98}=12⋅\sqrt{49}⋅\sqrt{2}=12⋅7⋅\sqrt{2}=84\sqrt{2}\) 1p |