Getal & Ruimte (12e editie) - vwo wiskunde B

'Wortels vereenvoudigen'.

2 vwo 5.3 Wortels herleiden

Wortels vereenvoudigen (5)

opgave 1

Herleid.

2p

a

\(\sqrt{32} + \sqrt{200}\)

Optellen (5)
0085 - Wortels vereenvoudigen - basis - 0ms

a

\(\sqrt{32} + \sqrt{200} = \sqrt{16} ⋅ \sqrt{2} + \sqrt{100} ⋅ \sqrt{2} = 4 \sqrt{2} + 10 \sqrt{2} \text{.}\)

1p

\(4 \sqrt{2} + 10 \sqrt{2} = 14 \sqrt{2} \text{.}\)

1p

1p

b

\(\sqrt{80}\)

FactorVoorWortelteken (1)
0086 - Wortels vereenvoudigen - basis - 0ms

b

\(\sqrt{80} = \sqrt{16} ⋅ \sqrt{5} = 4 \sqrt{5} \text{.}\)

1p

1p

c

\(5 \sqrt{300}\)

FactorVoorWortelteken (2)
0087 - Wortels vereenvoudigen - basis - 0ms

c

\(5 \sqrt{300} = 5 ⋅ \sqrt{100} ⋅ \sqrt{3} = 5 ⋅ 10 ⋅ \sqrt{3} = 50 \sqrt{3} \text{.}\)

1p

2p

d

\(5 \sqrt{27} - 3 \sqrt{75}\)

Optellen (6)
0088 - Wortels vereenvoudigen - basis - 0ms

d

\(5 \sqrt{27} - 3 \sqrt{75} = 5 ⋅ \sqrt{9} ⋅ \sqrt{3} - 3 ⋅ \sqrt{25} ⋅ \sqrt{3} \text{.}\)

1p

\(5 ⋅ 3 ⋅ \sqrt{3} - 3 ⋅ 5 ⋅ \sqrt{3} = 15 \sqrt{3} - 15 \sqrt{3} = 0 \sqrt{3} \text{.}\)

1p

opgave 2

Herleid.

1p

\(\sqrt{\frac{1}{9}}\)

BreukInWortel (1)
008b - Wortels vereenvoudigen - basis - 47ms

\(\sqrt{\frac{1}{9}} = {\sqrt{1} \over \sqrt{9}} = \frac{1}{3} \text{.}\)

1p

3 vwo 5.5 Wortels herleiden

Wortels vereenvoudigen (6)

opgave 1

Herleid.

1p

a

\({8 \over 3 \sqrt{5}}\)

WortelInNoemer
0089 - Wortels vereenvoudigen - basis - 1ms

a

\({8 \over 3 \sqrt{5}} = {8 \over 3 \sqrt{5}} ⋅ {\sqrt{5} \over \sqrt{5}} = {8 \sqrt{5} \over 3 ⋅ 5} = \frac{8}{15} \sqrt{5} \text{.}\)

1p

1p

b

\(\sqrt{\frac{44}{49}}\)

BreukInWortel (2)
008c - Wortels vereenvoudigen - basis - 1ms

b

\(\sqrt{\frac{44}{49}} = {\sqrt{44} \over \sqrt{49}} = {\sqrt{44} \over 7} = \frac{1}{7} \sqrt{44} = \frac{1}{7} ⋅ 2 ⋅ \sqrt{11} = \frac{2}{7} \sqrt{11} \text{.}\)

1p

1p

c

\(\sqrt{2\frac{6}{47}}\)

BreukInWortel (3)
008d - Wortels vereenvoudigen - basis - 1ms

c

\(\sqrt{2\frac{6}{47}} = \sqrt{\frac{100}{47}} = {\sqrt{100} \over \sqrt{47}} = {10 \over \sqrt{47}} ⋅ {\sqrt{47} \over \sqrt{47}} = {10 \sqrt{47} \over 47} = \frac{10}{47} \sqrt{47} \text{.}\)

1p

1p

d

\(\sqrt{\frac{2}{19}}\)

BreukInWortel (4)
008e - Wortels vereenvoudigen - basis - 1ms

d

\(\sqrt{\frac{2}{19}} = {\sqrt{2} \over \sqrt{19}} ⋅ {\sqrt{19} \over \sqrt{19}} = {\sqrt{38} \over 19} = \frac{1}{19} \sqrt{38} \text{.}\)

1p

opgave 2

Herleid.

1p

a

\({15 \sqrt{84} \over 3 \sqrt{3}}\)

Delen (4)
00dc - Wortels vereenvoudigen - basis - 9ms

a

\({15 \sqrt{84} \over 3 \sqrt{3}} = {15 \over 3} ⋅ {\sqrt{84} \over \sqrt{3}} = 5 \sqrt{28} = 5 ⋅ \sqrt{4} ⋅ \sqrt{7} = 5 ⋅ 2 ⋅ \sqrt{7} = 10 \sqrt{7}\)

1p

1p

b

\(4 \sqrt{6} ⋅ 5 \sqrt{2}\)

Vermenigvuldigen (5)
00dd - Wortels vereenvoudigen - basis - 3ms - data pool: #22 (2ms)

b

\(4 \sqrt{6} ⋅ 5 \sqrt{2} = 20 \sqrt{12} = 20 ⋅ \sqrt{4} ⋅ \sqrt{3} = 20 ⋅ 2 ⋅ \sqrt{3} = 40 \sqrt{3}\)

1p

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