Getal & Ruimte (12e editie) - vwo wiskunde B
'Sinus, cosinus en tangens'.
| 3 vwo | 6.3 Berekeningen met de tangens |
opgave 13p a Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}B=51\text{,}\) \(\angle A=47\degree\) en \(\angle B=90\degree\text{.}\) Tangens (1) 007m - Sinus, cosinus en tangens - basis - 0ms a Tangens in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\tan(\angle A)={B\kern{-.8pt}C \over A\kern{-.8pt}B}\) ofwel \(\tan(47\degree)={B\kern{-.8pt}C \over 51}\text{.}\) 1p ○ Hieruit volgt \(B\kern{-.8pt}C=51⋅\tan(47\degree)\text{.}\) 1p ○ Dus \(B\kern{-.8pt}C≈54{,}7\text{.}\) 1p 3p b Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}B=56\text{,}\) \(\angle C=35\degree\) en \(\angle A=90\degree\text{.}\) Tangens (2) 007n - Sinus, cosinus en tangens - basis - 0ms b Tangens in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\tan(\angle C)={A\kern{-.8pt}B \over A\kern{-.8pt}C}\) ofwel \(\tan(35\degree)={56 \over A\kern{-.8pt}C}\text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}C={56 \over \tan(35\degree)}\text{.}\) 1p ○ Dus \(A\kern{-.8pt}C≈80{,}0\text{.}\) 1p 3p c Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}R=52\text{,}\) \(P\kern{-.8pt}Q=43\) en \(\angle P=90\degree\text{.}\) Tangens (3) 007o - Sinus, cosinus en tangens - basis - 0ms c Tangens in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\tan(\angle R)={P\kern{-.8pt}Q \over P\kern{-.8pt}R}\) ofwel \(\tan(\angle R)={43 \over 52}\text{.}\) 1p ○ Hieruit volgt \(\angle R=\tan^{-1}({43 \over 52})\text{.}\) 1p ○ Dus \(\angle R≈39{,}6\degree\text{.}\) 1p |
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| 3 vwo | 6.4 De sinus en de cosinus |
opgave 13p a Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(B\kern{-.8pt}C=70\text{,}\) \(\angle C=33\degree\) en \(\angle A=90\degree\text{.}\) Sinus (1) 007g - Sinus, cosinus en tangens - basis - 0ms a Sinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\sin(\angle C)={A\kern{-.8pt}B \over B\kern{-.8pt}C}\) ofwel \(\sin(33\degree)={A\kern{-.8pt}B \over 70}\text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}B=70⋅\sin(33\degree)\text{.}\) 1p ○ Dus \(A\kern{-.8pt}B≈38{,}1\text{.}\) 1p 3p b Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}C=36\text{,}\) \(\angle B=43\degree\) en \(\angle C=90\degree\text{.}\) Sinus (2) 007h - Sinus, cosinus en tangens - basis - 0ms b Sinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\sin(\angle B)={A\kern{-.8pt}C \over A\kern{-.8pt}B}\) ofwel \(\sin(43\degree)={36 \over A\kern{-.8pt}B}\text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}B={36 \over \sin(43\degree)}\text{.}\) 1p ○ Dus \(A\kern{-.8pt}B≈52{,}8\text{.}\) 1p 3p c Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}R=34\text{,}\) \(P\kern{-.8pt}Q=42\) en \(\angle R=90\degree\text{.}\) Sinus (3) 007i - Sinus, cosinus en tangens - basis - 0ms c Sinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\sin(\angle Q)={P\kern{-.8pt}R \over P\kern{-.8pt}Q}\) ofwel \(\sin(\angle Q)={34 \over 42}\text{.}\) 1p ○ Hieruit volgt \(\angle Q=\sin^{-1}({34 \over 42})\text{.}\) 1p ○ Dus \(\angle Q≈54{,}0\degree\text{.}\) 1p 3p d Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}M=61\text{,}\) \(\angle K=59\degree\) en \(\angle L=90\degree\text{.}\) Cosinus (1) 007j - Sinus, cosinus en tangens - basis - 0ms d Cosinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\cos(\angle K)={K\kern{-.8pt}L \over K\kern{-.8pt}M}\) ofwel \(\cos(59\degree)={K\kern{-.8pt}L \over 61}\text{.}\) 1p ○ Hieruit volgt \(K\kern{-.8pt}L=61⋅\cos(59\degree)\text{.}\) 1p ○ Dus \(K\kern{-.8pt}L≈31{,}4\text{.}\) 1p opgave 23p a Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}M=54\text{,}\) \(\angle M=59\degree\) en \(\angle K=90\degree\text{.}\) Cosinus (2) 007k - Sinus, cosinus en tangens - basis - 0ms a Cosinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\cos(\angle M)={K\kern{-.8pt}M \over L\kern{-.8pt}M}\) ofwel \(\cos(59\degree)={54 \over L\kern{-.8pt}M}\text{.}\) 1p ○ Hieruit volgt \(L\kern{-.8pt}M={54 \over \cos(59\degree)}\text{.}\) 1p ○ Dus \(L\kern{-.8pt}M≈104{,}8\text{.}\) 1p 3p b Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}B=27\text{,}\) \(A\kern{-.8pt}C=41\) en \(\angle B=90\degree\text{.}\) Cosinus (3) 007l - Sinus, cosinus en tangens - basis - 0ms b Cosinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\cos(\angle A)={A\kern{-.8pt}B \over A\kern{-.8pt}C}\) ofwel \(\cos(\angle A)={27 \over 41}\text{.}\) 1p ○ Hieruit volgt \(\angle A=\cos^{-1}({27 \over 41})\text{.}\) 1p ○ Dus \(\angle A≈48{,}8\degree\text{.}\) 1p |