Getal & Ruimte (12e editie) - vwo wiskunde B

'Differentiëren'.

vwo wiskunde B 2.3 Limiet en afgeleide

Differentiëren (5)

opgave 1

Differentieer.

2p

a

\(f(x) = 8 x^{2} + x + 4\)

Machtsfunctie (1)
009w - Differentiëren - basis - basis - 1ms - dynamic variables

a

\(f'(x) = 8 ⋅ 2 ⋅ x^{1} + 1 \text{.}\)

1p

\(f'(x) = 16 x + 1 \text{.}\)

1p

2p

b

\(f(p) = -7 p^{6} + 5 p^{4} - 9\)

Machtsfunctie (2)
009x - Differentiëren - basis - basis - 4ms - dynamic variables

b

\(f'(p) = -7 ⋅ 6 ⋅ p^{5} + 5 ⋅ 4 ⋅ p^{3} \text{.}\)

1p

\(f'(p) = -42 p^{5} + 20 p^{3} \text{.}\)

1p

2p

c

\(f(a) = \frac{3}{7} a^{8} + 2\frac{1}{2} a^{6} + \frac{3}{4} a^{4} + 2\frac{1}{4} a^{3}\)

Machtsfunctie (3)
009y - Differentiëren - basis - basis - 1ms - dynamic variables

c

\(f'(a) = \frac{3}{7} ⋅ 8 ⋅ a^{7} + 2\frac{1}{2} ⋅ 6 ⋅ a^{5} + \frac{3}{4} ⋅ 4 ⋅ a^{3} + 2\frac{1}{4} ⋅ 3 ⋅ a^{2} \text{.}\)

1p

\(f'(a) = 3\frac{3}{7} a^{7} + 15 a^{5} + 3 a^{3} + 6\frac{3}{4} a^{2} \text{.}\)

1p

2p

d

\(f(x) = (8 x^{4} + 2) (x + 6)\)

HaakjesUitwerken (1)
00df - Differentiëren - basis - eind - 0ms - dynamic variables

d

(Haakjes wegwerken)
\(f(x) = (8 x^{4} + 2) (x + 6) = 8 x^{5} + 48 x^{4} + 2 x + 12\)

1p

(Differentiëren)
\(f'(x) = 40 x^{4} + 192 x^{3} + 2 \text{.}\)

1p

opgave 2

Differentieer.

2p

\(f(a) = (5 a^{4} + 1)^{2}\)

HaakjesUitwerken (2)
00dg - Differentiëren - basis - eind - 0ms - dynamic variables

(Haakjes wegwerken)
\(f(a) = (5 a^{4} + 1)^{2} = 25 a^{8} + 10 a^{4} + 1\)

1p

(Differentiëren)
\(f'(a) = 200 a^{7} + 40 a^{3} \text{.}\)

1p

vwo wiskunde B 2.4 Toepassingen van de afgeleide

Differentiëren (4)

opgave 1

Differentieer met behulp van de productregel.

2p

a

\(f(a) = (-4 a - 3) (9 a^{2} + 4 a)\)

Productregel (1)
009z - Differentiëren - basis - basis - 1ms - dynamic variables

a

(Productregel)
\(f'(a) = -4 (9 a^{2} + 4 a) + (-4 a - 3) (18 a + 4) \text{.}\)

2p

2p

b

\(f(x) = (9 x^{2} + 6 x) (7 x^{2} + x + 5)\)

Productregel (2)
00a0 - Differentiëren - basis - basis - 1ms - dynamic variables

b

(Productregel)
\(f'(x) = (18 x + 6) (7 x^{2} + x + 5) + (9 x^{2} + 6 x) (14 x + 1) \text{.}\)

2p

opgave 2

Differentieer.

2p

a

\(f(x) = {-7 x - 9 \over x + 7}\)

Quotientregel (1)
00a1 - Differentiëren - basis - eind - 1ms - dynamic variables

a

(Quotiëntregel)
\(f'(x) = {(x + 7) ⋅ -7 - (-7 x - 9) ⋅ 1 \over (x + 7)^{2}} \text{.}\)

1p

\(f'(x) = {(-7 x - 49) - (-7 x - 9) \over (x + 7)^{2}} = {-40 \over (x + 7)^{2}} \text{.}\)

1p

2p

b

\(f(p) = {-3 p^{2} \over -8 p + 1}\)

Quotientregel (2)
00a2 - Differentiëren - basis - eind - 1ms - dynamic variables

b

(Quotiëntregel)
\(f'(p) = {(-8 p + 1) ⋅ -6 p - -3 p^{2} ⋅ -8 \over (-8 p + 1)^{2}} \text{.}\)

1p

\(f'(p) = {(48 p^{2} - 6 p) - 24 p^{2} \over (-8 p + 1)^{2}} = {24 p^{2} - 6 p \over (-8 p + 1)^{2}} \text{.}\)

1p

vwo wiskunde B 6.2 De afgeleide van machtsfuncties

Differentiëren (6)

opgave 1

Differentieer.

3p

a

\(f(a) = {7 \over 5 a^{2}}\)

NegatieveMacht
00de - Differentiëren - basis - basis - 0ms - dynamic variables

a

(Herleiden)
\(f(a) = {7 \over 5 a^{2}} = \frac{7}{5} a^{-2}\)

1p

(Differentiëren)
\(f'(a) = \frac{7}{5} ⋅ -2 ⋅ a^{-3} = -\frac{14}{5} ⋅ a^{-3}\)

1p

(Herleiden)
\(f'(a) = -\frac{14}{5} ⋅ {1 \over a^{3}} = -{14 \over 5 a^{3}}\)

1p

3p

b

\(f(a) = -4 a^{3} ⋅ \sqrt[9]{a^{7}}\)

GebrokenMacht
00dl - Differentiëren - basis - basis - 0ms - dynamic variables

b

(Herleiden)
\(f(a) = -4 a^{3} ⋅ \sqrt[9]{a^{7}} = -4 ⋅ a^{3} ⋅ a^{\frac{7}{9}} = -4 ⋅ a^{3\frac{7}{9}}\)

1p

(Differentiëren)
\(f'(a) = -4 ⋅ 3\frac{7}{9} ⋅ a^{2\frac{7}{9}}\)

1p

(Herleiden)
\(f'(a) = -15\frac{1}{9} ⋅ a^{2} ⋅ a^{\frac{7}{9}} = -15\frac{1}{9} a^{2} ⋅ \sqrt[9]{a^{7}}\)

1p

3p

c

\(f(p) = {p^{6} - 4 p^{2} \over 5 p^{3}}\)

Uitdelen (1)
00dm - Differentiëren - basis - eind - 0ms - dynamic variables

c

(Uitdelen)
\(f(p) = {p^{6} \over 5 p^{3}} - {4 p^{2} \over 5 p^{3}} = \frac{1}{5} p^{3} - \frac{4}{5} p^{-1}\)

1p

(Differentiëren)
\(f'(p) = \frac{1}{5} ⋅ 3 ⋅ p^{2} - \frac{4}{5} ⋅ -1 ⋅ p^{-2}\)

1p

(Herleiden)
\(f'(p) = \frac{3}{5} p^{2} + {4 \over 5 p^{2}}\)

1p

4p

d

\(f(x) = {x^{4} + 2 \over \sqrt[5]{x}}\)

Uitdelen (2)
00dn - Differentiëren - basis - eind - 0ms - dynamic variables

d

(Herleiden)
\(f(x) = {x^{4} + 2 \over x^{\frac{1}{5}}}\)

1p

(Uitdelen)
\(f(x) = {x^{4} \over x^{\frac{1}{5}}} + {2 \over x^{\frac{1}{5}}} = x^{3\frac{4}{5}} + 2 x^{-\frac{1}{5}}\)

1p

(Differentiëren)
\(f'(x) = 3\frac{4}{5} ⋅ x^{2\frac{4}{5}} + 2 ⋅ -\frac{1}{5} ⋅ x^{-1\frac{1}{5}}\)

1p

(Herleiden)
\(f'(x) = 3\frac{4}{5} x^{2} ⋅ \sqrt[5]{x^{4}} - {2 \over 5 x ⋅ \sqrt[5]{x}}\)

1p

opgave 2

Differentieer.

3p

a

\(f(x) = {3 \over 8 \sqrt{x}} - 3 \sqrt{x}\)

GebrokenWortel
00do - Differentiëren - basis - eind - 0ms - dynamic variables

a

(Herleiden)
\(f(x) = {3 \over 8 \sqrt{x}} - 3 \sqrt{x} = \frac{3}{8} x^{-\frac{1}{2}} - 3 x^{\frac{1}{2}}\)

1p

(Differentiëren)
\(f'(x) = \frac{3}{8} ⋅ -\frac{1}{2} ⋅ x^{-1\frac{1}{2}} - 3 ⋅ \frac{1}{2} ⋅ x^{-\frac{1}{2}}\)

1p

(Herleiden)
\(f'(x) = -{3 \over 16 x \sqrt{x}} - {3 \over 2 \sqrt{x}}\)

1p

4p

b

\(f(a) = {2 a - 4 \over a^{3} ⋅ \sqrt{a}}\)

Uitdelen (3)
00dp - Differentiëren - basis - eind - 0ms - dynamic variables

b

(Herleiden)
\(f(a) = {2 a - 4 \over a^{3\frac{1}{2}}}\)

1p

(Uitdelen)
\(f(a) = {2 a \over a^{3\frac{1}{2}}} - {4 \over a^{3\frac{1}{2}}} = 2 a^{-2\frac{1}{2}} - 4 a^{-3\frac{1}{2}}\)

1p

(Differentiëren)
\(f'(a) = 2 ⋅ -2\frac{1}{2} ⋅ a^{-3\frac{1}{2}} - 4 ⋅ -3\frac{1}{2} ⋅ a^{-4\frac{1}{2}}\)

1p

(Herleiden)
\(f'(a) = -{5 \over a^{3} ⋅ \sqrt{a}} + {14 \over a^{4} ⋅ \sqrt{a}}\)

1p

vwo wiskunde B 6.3 De kettingregel

Differentiëren (5)

opgave 1

Differentieer.

2p

a

\(f(a) = 8 (\frac{5}{9} a + 6)^{5}\)

Kettingregel (1)
00dh - Differentiëren - basis - basis - 0ms - dynamic variables

a

(Kettingregel)
\(f'(a) = 8 ⋅ 5 ⋅ (\frac{5}{9} a + 6)^{4} ⋅ \frac{5}{9}\)

1p

(Herleiden)
\(f'(a) = 22\frac{2}{9} (\frac{5}{9} a + 6)^{4} \text{.}\)

1p

3p

b

\(f(a) = {4 \over (3 a - 1)^{5}}\)

KettingregelMetGebroken
00di - Differentiëren - basis - midden - 1ms - dynamic variables

b

(Herleiden)
\(f(a) = {4 \over (3 a - 1)^{5}} = 4 ⋅ (3 a - 1)^{-5}\)

1p

(Kettingregel)
\(f'(a) = 4 ⋅ -5 ⋅ (3 a - 1)^{-6} ⋅ 3\)

1p

(Herleiden)
\(f'(a) = -60 ⋅ (3 a - 1)^{-6} = -{60 \over (3 a - 1)^{6}}\)

1p

3p

c

\(f(p) = 3 \sqrt{5 p + 1}\)

KettingregelMetWortel
00dj - Differentiëren - basis - midden - 0ms - dynamic variables

c

(Herleiden)
\(f(p) = 3 \sqrt{5 p + 1} = 3 ⋅ (5 p + 1)^{\frac{1}{2}} \text{.}\)

1p

(Kettingregel)
\(f'(p) = 3 ⋅ \frac{1}{2} ⋅ (5 p + 1)^{-\frac{1}{2}} ⋅ 5\)

1p

(Herleiden)
\(f'(p) = \frac{15}{2} ⋅ (5 p + 1)^{-\frac{1}{2}} = {15 \over 2 \sqrt{5 p + 1}}\)

1p

3p

d

\(f(x) = {9 \over 7 \sqrt{5 x + 3}}\)

KettingregelMetGebrokenWortel
00dk - Differentiëren - basis - eind - 1ms - dynamic variables

d

(Herleiden)
\(f(x) = {9 \over 7 \sqrt{5 x + 3}} = \frac{9}{7} ⋅ (5 x + 3)^{-\frac{1}{2}}\)

1p

(Kettingregel)
\(f'(x) = \frac{9}{7} ⋅ -\frac{1}{2} ⋅ (5 x + 3)^{-1\frac{1}{2}} ⋅ 5\)

1p

(Herleiden)
\(f'(x) = -\frac{45}{14} ⋅ (5 x + 3)^{-1\frac{1}{2}} = -{45 \over 14 (5 x + 3) \sqrt{5 x + 3}}\)

1p

opgave 2

Differentieer.

2p

\(f(x) = 6 (x^{4} + 2 x^{3} + 3 x^{2})^{4}\)

Kettingregel (2)
00j9 - Differentiëren - basis - basis - 0ms - dynamic variables

(Kettingregel)
\(f'(x) = 6 ⋅ 4 ⋅ (x^{4} + 2 x^{3} + 3 x^{2})^{3} ⋅ (4 x^{3} + 6 x^{2} + 6 x)\)

1p

(Herleiden)
\(f'(x) = (96 x^{3} + 144 x^{2} + 144 x) ⋅ (x^{4} + 2 x^{3} + 3 x^{2})^{3}\)

1p

vwo wiskunde B 9.3 Het grondtal e

Differentiëren (1)

opgave 1

Differentieer.

2p

\(f(a) = (4 a^{2} - 3) ⋅ e^{-6 a + 1}\)

ExponentieelMetProductregel
00j8 - Differentiëren - basis - eind - 1ms - dynamic variables

\(f(a) = 8 a ⋅ e^{-6 a + 1} + (4 a^{2} - 3) ⋅ e^{-6 a + 1} ⋅ -6\)
\(\text{ } = 8 a ⋅ e^{-6 a + 1} + (-24 a^{2} + 18) ⋅ e^{-6 a + 1}\)
\(\text{ } = (-24 a^{2} + 8 a + 18) ⋅ e^{-6 a + 1}\)

2p

vwo wiskunde B 9.4 De natuurlijke logaritme

Differentiëren (1)

opgave 1

Differentieer.

2p

\(f(a) = -2 ⋅ 4^{5 a^{3} - 3 a}\)

Exponentieel
00j7 - Differentiëren - basis - eind - 2ms - dynamic variables

\(f(a) = -2 ⋅ 4^{5 a^{3} - 3 a} ⋅ \ln(4) ⋅ (15 a^{2} - 3) = (-30 a^{2} + 6) ⋅ 4^{5 a^{3} - 3 a} ⋅ \ln(4)\)

2p

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