\({3 \over 5 x} + {7 \over 5 x} = {10 \over 5 x} = {2 \over x}\)

\({7 \over a} - {2 \over 5 a} = {35 \over 5 a} - {2 \over 5 a} = {33 \over 5 a}\)

\({2 \over 3 p} + {6 \over 5 q} = {10 q \over 15 p q} + {18 p \over 15 p q} = {10 q + 18 p \over 15 p q}\)

\(6 + {2 \over 5 a} = {6 \over 1} + {2 \over 5 a} = {30 a \over 5 a} + {2 \over 5 a} = {30 a + 2 \over 5 a}\)

\({7 x \over y} + {2 \over 4 y} = {28 x \over 4 y} + {2 \over 4 y} = {28 x + 2 \over 4 y} = {14 x + 1 \over 2 y}\)

\({4 x \over x} = {4 \over 1} = 4\)

\({x \over 3 x} = {1 \over 3}\)

\({-25 p \over -40 p} = \frac{5}{8}\)

\({35 a \over 5 a} = 7\)

\({-15 a b \over 24 a c} = -{5 b \over 8 c}\)

\({4 b \over 6 a b} = {2 \over 3 a}\)

\({-45 p q r \over -5 q r} = 9 p\)

\({5 x y \over y} - {4 x z \over z} = 5 x - 4 x = x\)

\(9 x - {7 \over 4 x} = {9 x \over 1} ⋅ {4 x \over 4 x} - {7 \over 4 x} = {36 x^{2} \over 4 x} - {7 \over 4 x} = {36 x^{2} - 7 \over 4 x}\)

\({2 q \over 8 p} + {5 p \over 4 q} = {2 q^{2} \over 8 p q} + {10 p^{2} \over 8 p q} = {10 p^{2} + 2 q^{2} \over 8 p q} = {5 p^{2} + q^{2} \over 4 p q}\)

\({8 \over a} ⋅ {9 \over b} = {72 \over a b}\)

\({x \over 5} ⋅ {8 \over y} = {8 x \over 5 y}\)

\({2 \over 3} ⋅ a = {2 a \over 3}\)

\({7 b \over a} ⋅ {a + 8 \over 6} = {7 b (a + 8) \over 6 a} = {7 a b + 56 b \over 6 a}\)

\({8 \over x} : {9 \over y} = {8 \over x} ⋅ {y \over 9} = {8 y \over 9 x}\)

\(-{4 \over 9} : p = -{4 \over 9} : {p \over 1} = -{4 \over 9} ⋅ {1 \over p} = -{4 \over 9 p}\)

\({1 \over 4} : {a - 2 b \over b} = {1 \over 4} ⋅ {b \over a - 2 b} = {b \over 4 (a - 2 b)} = {b \over 4 a - 8 b}\)

\({9 x \over 7} + {x + 5 \over 4} = {36 x \over 28} + {7 (x + 5) \over 28} = {36 x + 7 (x + 5) \over 28} = {43 x + 35 \over 28}\)

\({7 p + 4 \over -3 p + 1} - 5 = {7 p + 4 \over -3 p + 1} + {-5 (-3 p + 1) \over -3 p + 1} = {7 p + 4 - 5 (-3 p + 1) \over -3 p + 1} = {7 p + 4 + 15 p - 5 \over -3 p + 1} = {22 p - 1 \over -3 p + 1}\)

\({x^{2} + 2 x + 30 \over x} = {x^{2} \over x} + {2 x \over x} + {30 \over x} = x + 2 + {30 \over x}\)

\({2 x^{2} + 4 x + 5 \over 6 x^{2}} = {2 x^{2} \over 6 x^{2}} + {4 x \over 6 x^{2}} + {5 \over 6 x^{2}} = \frac{1}{3} + {2 \over 3 x} + {5 \over 6 x^{2}}\)