\({4 \over 5 x} + {7 \over 5 x} = {11 \over 5 x}\)

\({5 \over a} - {6 \over 2 a} = {10 \over 2 a} - {6 \over 2 a} = {4 \over 2 a} = {2 \over a}\)

\({3 \over 6 x} - {5 \over 4 y} = {6 y \over 12 x y} - {15 x \over 12 x y} = {6 y - 15 x \over 12 x y} = {2 y - 5 x \over 4 x y}\)

\(5 + {3 \over 8 p} = {5 \over 1} + {3 \over 8 p} = {40 p \over 8 p} + {3 \over 8 p} = {40 p + 3 \over 8 p}\)

\({4 a \over b} + {9 \over 2 b} = {8 a \over 2 b} + {9 \over 2 b} = {8 a + 9 \over 2 b}\)

\({6 a \over a} = {6 \over 1} = 6\)

\({x \over 5 x} = {1 \over 5}\)

\({4 a \over -10 a} = -\frac{2}{5}\)

\({36 p \over -4 p} = -9\)

\({-6 x y \over 27 x z} = -{2 y \over 9 z}\)

\({-10 q \over -12 p q} = {5 \over 6 p}\)

\({-40 a b c \over -5 b c} = 8 a\)

\({7 x y \over y} + {5 x z \over z} = 7 x + 5 x = 12 x\)

\(7 a + {2 \over 9 a} = {7 a \over 1} ⋅ {9 a \over 9 a} + {2 \over 9 a} = {63 a^{2} \over 9 a} + {2 \over 9 a} = {63 a^{2} + 2 \over 9 a}\)

\({4 y \over 5 x} + {8 x \over 9 y} = {36 y^{2} \over 45 x y} + {40 x^{2} \over 45 x y} = {40 x^{2} + 36 y^{2} \over 45 x y}\)

\({5 \over a} ⋅ -{9 \over b} = -{45 \over a b}\)

\({p \over 5} ⋅ -{6 \over q} = -{6 p \over 5 q}\)

\({8 \over 5} ⋅ x = {8 x \over 5}\)

\({7 q \over p} ⋅ {p - 4 \over 5} = {7 q (p - 4) \over 5 p} = {7 p q - 28 q \over 5 p}\)

\({4 \over x} : {5 \over y} = {4 \over x} ⋅ {y \over 5} = {4 y \over 5 x}\)

\(-{8 \over 7} : x = -{8 \over 7} : {x \over 1} = -{8 \over 7} ⋅ {1 \over x} = -{8 \over 7 x}\)

\(-{7 \over 3} : {a + b \over b} = -{7 \over 3} ⋅ {b \over a + b} = -{7 b \over 3 (a + b)} = -{7 b \over 3 a + 3 b}\)

\({6 a \over 5} + {a - 3 \over 8} = {48 a \over 40} + {5 (a - 3) \over 40} = {48 a + 5 (a - 3) \over 40} = {53 a - 15 \over 40}\)

\({-8 x + 9 \over 3 x - 4} + 7 = {-8 x + 9 \over 3 x - 4} + {7 (3 x - 4) \over 3 x - 4} = {-8 x + 9 + 7 (3 x - 4) \over 3 x - 4} = {-8 x + 9 + 21 x - 28 \over 3 x - 4} = {13 x - 19 \over 3 x - 4}\)

\({2 a^{2} - 4 a - 60 \over 2 a} = {2 a^{2} \over 2 a} - {4 a \over 2 a} - {60 \over 2 a} = a - 2 - {30 \over a}\)

\({6 a^{2} - a - 8 \over 7 a^{2}} = {6 a^{2} \over 7 a^{2}} - {a \over 7 a^{2}} - {8 \over 7 a^{2}} = \frac{6}{7} - {1 \over 7 a} - {8 \over 7 a^{2}}\)