\({7 \over 9a}-{8 \over 9a}=-{1 \over 9a}\)

\({8 \over x}+{5 \over 3x}={24 \over 3x}+{5 \over 3x}={29 \over 3x}\)

\({6 \over 7x}+{3 \over 2y}={12y \over 14xy}+{21x \over 14xy}={12y+21x \over 14xy}\)

\(8-{9 \over 4a}={8 \over 1}-{9 \over 4a}={32a \over 4a}-{9 \over 4a}={32a-9 \over 4a}\)

\({3p \over q}+{8 \over 2q}={6p \over 2q}+{8 \over 2q}={6p+8 \over 2q}={3p+4 \over q}\)

\({5x \over x}={5 \over 1}=5\)

\({p \over 3p}={1 \over 3}\)

\({-24a \over -28a}=\frac{6}{7}\)

\({-16x \over 4x}=-4\)

\({-30ab \over 35ac}=-{6b \over 7c}\)

\({20y \over -35xy}=-{4 \over 7x}\)

\({6xyz \over 3yz}=2x\)

\({5ab \over b}-{2ac \over c}=5a-2a=3a\)

\(8x-{5 \over 4x}={8x \over 1}⋅{4x \over 4x}-{5 \over 4x}={32x^2 \over 4x}-{5 \over 4x}={32x^2-5 \over 4x}\)

\({7y \over 5x}+{9x \over 8y}={56y^2 \over 40xy}+{45x^2 \over 40xy}={45x^2+56y^2 \over 40xy}\)

\({7 \over p}⋅-{2 \over q}=-{14 \over pq}\)

\({a \over 5}⋅-{3 \over b}=-{3a \over 5b}\)

\({7 \over 3}⋅a={7a \over 3}\)

\({7y \over x}⋅{x+3 \over 9}={7y(x+3) \over 9x}={7xy+21y \over 9x}\)

\({5 \over x}:{4 \over y}={5 \over x}⋅{y \over 4}={5y \over 4x}\)

\({5 \over 8}:a={5 \over 8}:{a \over 1}={5 \over 8}⋅{1 \over a}={5 \over 8a}\)

\(-{7 \over 5}:{p-4q \over q}=-{7 \over 5}⋅{q \over p-4q}=-{7q \over 5(p-4q)}=-{7q \over 5p-20q}\)

\({a \over 6}+{a+7 \over 5}={5a \over 30}+{6(a+7) \over 30}={5a+6(a+7) \over 30}={11a+42 \over 30}\)

\({4x-6 \over 9x+3}-1={4x-6 \over 9x+3}-{1(9x+3) \over 9x+3}={4x-6-1(9x+3) \over 9x+3}={4x-6-9x-3 \over 9x+3}={-5x-9 \over 9x+3}\)

\({6a^2+4a-20 \over 2a}={6a^2 \over 2a}+{4a \over 2a}-{20 \over 2a}=3a+2-{10 \over a}\)

\({9x^2+2x-3 \over 6x^2}={9x^2 \over 6x^2}+{2x \over 6x^2}-{3 \over 6x^2}=1\frac{1}{2}+{1 \over 3x}-{1 \over 2x^2}\)