Getal & Ruimte (12e editie) - vwo wiskunde A

'Differentiëren'.

vwo wiskunde A 8.3 Differentiëren

Differentiëren (5)

opgave 1

Differentieer.

2p

a

\(f(a) = a^{3} + 6 a + 9\)

Machtsfunctie (1)
009w - Differentiëren - basis - basis - 1ms - dynamic variables

a

\(f'(a) = 3 ⋅ a^{2} + 6 \text{.}\)

1p

\(f'(a) = 3 a^{2} + 6 \text{.}\)

1p

2p

b

\(f(a) = 8 a^{9} - a^{7} + 6 a\)

Machtsfunctie (2)
009x - Differentiëren - basis - basis - 4ms - dynamic variables

b

\(f'(a) = 8 ⋅ 9 ⋅ a^{8} - 1 ⋅ 7 ⋅ a^{6} + 6 \text{.}\)

1p

\(f'(a) = 72 a^{8} - 7 a^{6} + 6 \text{.}\)

1p

2p

c

\(f(x) = \frac{1}{8} x^{7} + 1\frac{2}{5} x^{5} + 1\frac{1}{2} x + 1\frac{1}{3}\)

Machtsfunctie (3)
009y - Differentiëren - basis - basis - 0ms - dynamic variables

c

\(f'(x) = \frac{1}{8} ⋅ 7 ⋅ x^{6} + 1\frac{2}{5} ⋅ 5 ⋅ x^{4} + 1\frac{1}{2} \text{.}\)

1p

\(f'(x) = \frac{7}{8} x^{6} + 7 x^{4} + 1\frac{1}{2} \text{.}\)

1p

2p

d

\(f(p) = (2 p^{5} + 6) (p - 4)\)

HaakjesUitwerken (1)
00df - Differentiëren - basis - eind - 1ms - dynamic variables

d

(Haakjes wegwerken)
\(f(p) = (2 p^{5} + 6) (p - 4) = 2 p^{6} - 8 p^{5} + 6 p - 24\)

1p

(Differentiëren)
\(f'(p) = 12 p^{5} - 40 p^{4} + 6 \text{.}\)

1p

opgave 2

Differentieer.

2p

\(f(x) = (4 x^{5} - 1)^{2}\)

HaakjesUitwerken (2)
00dg - Differentiëren - basis - eind - 1ms - dynamic variables

(Haakjes wegwerken)
\(f(x) = (4 x^{5} - 1)^{2} = 16 x^{10} - 8 x^{5} + 1\)

1p

(Differentiëren)
\(f'(x) = 160 x^{9} - 40 x^{4} \text{.}\)

1p

vwo wiskunde A 8.4 Notaties en regels voor de afgeleide

Differentiëren (8)

opgave 1

Differentieer.

3p

a

\(f(p) = {7 \over 2 p^{4}}\)

NegatieveMacht
00de - Differentiëren - basis - basis - 0ms - dynamic variables

a

(Herleiden)
\(f(p) = {7 \over 2 p^{4}} = \frac{7}{2} p^{-4}\)

1p

(Differentiëren)
\(f'(p) = \frac{7}{2} ⋅ -4 ⋅ p^{-5} = -14 ⋅ p^{-5}\)

1p

(Herleiden)
\(f'(p) = -14 ⋅ {1 \over p^{5}} = -{14 \over p^{5}}\)

1p

2p

b

\(f(x) = 2 (6 x + 9)^{3}\)

Kettingregel (1)
00dh - Differentiëren - basis - basis - 1ms - dynamic variables

b

(Kettingregel)
\(f'(x) = 2 ⋅ 3 ⋅ (6 x + 9)^{2} ⋅ 6\)

1p

(Herleiden)
\(f'(x) = 36 (6 x + 9)^{2} \text{.}\)

1p

3p

c

\(f(x) = {1 \over (5 x - 3)^{4}}\)

KettingregelMetGebroken
00di - Differentiëren - basis - midden - 1ms - dynamic variables

c

(Herleiden)
\(f(x) = {1 \over (5 x - 3)^{4}} = 1 ⋅ (5 x - 3)^{-4}\)

1p

(Kettingregel)
\(f'(x) = 1 ⋅ -4 ⋅ (5 x - 3)^{-5} ⋅ 5\)

1p

(Herleiden)
\(f'(x) = -20 ⋅ (5 x - 3)^{-5} = -{20 \over (5 x - 3)^{5}}\)

1p

3p

d

\(f(a) = -2 \sqrt{5 a - 4}\)

KettingregelMetWortel
00dj - Differentiëren - basis - midden - 1ms - dynamic variables

d

(Herleiden)
\(f(a) = -2 \sqrt{5 a - 4} = -2 ⋅ (5 a - 4)^{\frac{1}{2}} \text{.}\)

1p

(Kettingregel)
\(f'(a) = -2 ⋅ \frac{1}{2} ⋅ (5 a - 4)^{-\frac{1}{2}} ⋅ 5\)

1p

(Herleiden)
\(f'(a) = -5 ⋅ (5 a - 4)^{-\frac{1}{2}} = -{5 \over \sqrt{5 a - 4}}\)

1p

opgave 2

Differentieer.

3p

a

\(f(a) = {7 \over 4 \sqrt{5 a + 4}}\)

KettingregelMetGebrokenWortel
00dk - Differentiëren - basis - eind - 1ms - dynamic variables

a

(Herleiden)
\(f(a) = {7 \over 4 \sqrt{5 a + 4}} = \frac{7}{4} ⋅ (5 a + 4)^{-\frac{1}{2}}\)

1p

(Kettingregel)
\(f'(a) = \frac{7}{4} ⋅ -\frac{1}{2} ⋅ (5 a + 4)^{-1\frac{1}{2}} ⋅ 5\)

1p

(Herleiden)
\(f'(a) = -\frac{35}{8} ⋅ (5 a + 4)^{-1\frac{1}{2}} = -{35 \over 8 (5 a + 4) \sqrt{5 a + 4}}\)

1p

3p

b

\(f(x) = 2 x^{2} ⋅ \sqrt[5]{x^{2}}\)

GebrokenMacht
00dl - Differentiëren - basis - basis - 0ms - dynamic variables

b

(Herleiden)
\(f(x) = 2 x^{2} ⋅ \sqrt[5]{x^{2}} = 2 ⋅ x^{2} ⋅ x^{\frac{2}{5}} = 2 ⋅ x^{2\frac{2}{5}}\)

1p

(Differentiëren)
\(f'(x) = 2 ⋅ 2\frac{2}{5} ⋅ x^{1\frac{2}{5}}\)

1p

(Herleiden)
\(f'(x) = 4\frac{4}{5} ⋅ x^{1} ⋅ x^{\frac{2}{5}} = 4\frac{4}{5} x ⋅ \sqrt[5]{x^{2}}\)

1p

3p

c

\(f(p) = {9 \over 7 \sqrt{p}} - 3 \sqrt{p}\)

GebrokenWortel
00do - Differentiëren - basis - eind - 0ms - dynamic variables

c

(Herleiden)
\(f(p) = {9 \over 7 \sqrt{p}} - 3 \sqrt{p} = \frac{9}{7} p^{-\frac{1}{2}} - 3 p^{\frac{1}{2}}\)

1p

(Differentiëren)
\(f'(p) = \frac{9}{7} ⋅ -\frac{1}{2} ⋅ p^{-1\frac{1}{2}} - 3 ⋅ \frac{1}{2} ⋅ p^{-\frac{1}{2}}\)

1p

(Herleiden)
\(f'(p) = -{9 \over 14 p \sqrt{p}} - {3 \over 2 \sqrt{p}}\)

1p

2p

d

\(f(x) = 2 (4 x^{4} + x^{2} + 6)^{5}\)

Kettingregel (2)
00j9 - Differentiëren - basis - basis - 1ms - dynamic variables

d

(Kettingregel)
\(f'(x) = 2 ⋅ 5 ⋅ (4 x^{4} + x^{2} + 6)^{4} ⋅ (16 x^{3} + 2 x)\)

1p

(Herleiden)
\(f'(x) = (160 x^{3} + 20 x) ⋅ (4 x^{4} + x^{2} + 6)^{4}\)

1p

vwo wiskunde A 10.5 Groeisnelheid

Differentiëren (1)

opgave 1

Differentieer.

2p

\(f(p) = 4 ⋅ 2^{3 p - 5}\)

Exponentieel
00j7 - Differentiëren - basis - eind - 2ms - dynamic variables

\(f(p) = 4 ⋅ 2^{3 p - 5} ⋅ \ln(2) ⋅ 3 = 12 ⋅ 2^{3 p - 5} ⋅ \ln(2)\)

2p

vwo wiskunde A 14.2 Regels voor de afgeleide

Differentiëren (2)

opgave 1

Differentieer.

2p

a

\(f(x) = {-2 x + 8 \over 2 x + 5}\)

Quotientregel (1)
00a1 - Differentiëren - basis - eind - 1ms - dynamic variables

a

(Quotiëntregel)
\(f'(x) = {(2 x + 5) ⋅ -2 - (-2 x + 8) ⋅ 2 \over (2 x + 5)^{2}} \text{.}\)

1p

\(f'(x) = {(-4 x - 10) - (-4 x + 16) \over (2 x + 5)^{2}} = {-26 \over (2 x + 5)^{2}} \text{.}\)

1p

2p

b

\(f(p) = {6 p^{2} \over -5 p - 3}\)

Quotientregel (2)
00a2 - Differentiëren - basis - eind - 1ms - dynamic variables

b

(Quotiëntregel)
\(f'(p) = {(-5 p - 3) ⋅ 12 p - 6 p^{2} ⋅ -5 \over (-5 p - 3)^{2}} \text{.}\)

1p

\(f'(p) = {(-60 p^{2} - 36 p) - -30 p^{2} \over (-5 p - 3)^{2}} = {-30 p^{2} - 36 p \over (-5 p - 3)^{2}} \text{.}\)

1p

"