\({9 \over 5x}-{6 \over 5x}={3 \over 5x}\)

\({6 \over a}-{9 \over 4a}={24 \over 4a}-{9 \over 4a}={15 \over 4a}\)

\({3 \over 6x}-{4 \over 2y}={3y \over 6xy}-{12x \over 6xy}={3y-12x \over 6xy}={y-4x \over 2xy}\)

\(5-{7 \over 3a}={5 \over 1}-{7 \over 3a}={15a \over 3a}-{7 \over 3a}={15a-7 \over 3a}\)

\({8p \over q}+{7 \over 4q}={32p \over 4q}+{7 \over 4q}={32p+7 \over 4q}\)

\({8p \over p}={8 \over 1}=8\)

\({a \over 9a}={1 \over 9}\)

\({25x \over -35x}=-\frac{5}{7}\)

\({-12a \over -4a}=3\)

\({-32xy \over -36xz}={8y \over 9z}\)

\({21y \over -27xy}=-{7 \over 9x}\)

\({45pqr \over 5qr}=9p\)

\({6ab \over b}+{3ac \over c}=6a+3a=9a\)

\(7a+{3 \over 4a}={7a \over 1}⋅{4a \over 4a}+{3 \over 4a}={28a^2 \over 4a}+{3 \over 4a}={28a^2+3 \over 4a}\)

\({2b \over 4a}-{8a \over 7b}={14b^2 \over 28ab}-{32a^2 \over 28ab}={-32a^2+14b^2 \over 28ab}={-16a^2+7b^2 \over 14ab}\)

\({3 \over p}⋅-{2 \over q}=-{6 \over pq}\)

\({x \over 2}⋅{3 \over y}={3x \over 2y}\)

\(-{5 \over 4}⋅x=-{5x \over 4}\)

\({8y \over x}⋅{x-4 \over 5}={8y(x-4) \over 5x}={8xy-32y \over 5x}\)

\({8 \over a}:{7 \over b}={8 \over a}⋅{b \over 7}={8b \over 7a}\)

\({5 \over 9}:a={5 \over 9}:{a \over 1}={5 \over 9}⋅{1 \over a}={5 \over 9a}\)

\(-{6 \over 7}:{p-3q \over q}=-{6 \over 7}⋅{q \over p-3q}=-{6q \over 7(p-3q)}=-{6q \over 7p-21q}\)

\({8x \over 3}+{x-4 \over 7}={56x \over 21}+{3(x-4) \over 21}={56x+3(x-4) \over 21}={59x-12 \over 21}\)

\({2p^2+3p-6 \over p^2}={2p^2 \over p^2}+{3p \over p^2}-{6 \over p^2}=2+{3 \over p}-{6 \over p^2}\)