Getal & Ruimte (12e editie) - vwo wiskunde A
'Breuken herleiden'.
| 1 vwo | 6.6 Herleiden van breuken |
opgave 1Herleid tot één breuk. 1p a \({3 \over 6 x} - {8 \over 6 x}\) Optellen (1) 008u - Breuken herleiden - basis - 0ms - dynamic variables a \({3 \over 6 x} - {8 \over 6 x} = -{5 \over 6 x}\) 1p 1p b \({5 \over a} + {7 \over 4 a}\) Optellen (2) 008v - Breuken herleiden - basis - 0ms - dynamic variables b \({5 \over a} + {7 \over 4 a} = {20 \over 4 a} + {7 \over 4 a} = {27 \over 4 a}\) 1p 1p c \({4 \over 7 x} + {3 \over 2 y}\) Optellen (3) 008w - Breuken herleiden - basis - 0ms - dynamic variables c \({4 \over 7 x} + {3 \over 2 y} = {8 y \over 14 x y} + {21 x \over 14 x y} = {8 y + 21 x \over 14 x y}\) 1p 1p d \(7 + {4 \over 9 a}\) Optellen (4) 008x - Breuken herleiden - basis - 0ms - dynamic variables d \(7 + {4 \over 9 a} = {7 \over 1} + {4 \over 9 a} = {63 a \over 9 a} + {4 \over 9 a} = {63 a + 4 \over 9 a}\) 1p opgave 2Herleid tot één breuk. 1p \({3 p \over q} + {9 \over 4 q}\) Optellen (6) 008z - Breuken herleiden - basis - 0ms - dynamic variables ○ \({3 p \over q} + {9 \over 4 q} = {12 p \over 4 q} + {9 \over 4 q} = {12 p + 9 \over 4 q}\) 1p opgave 3Herleid. 1p a \({6 x \over x}\) Vereenvoudigen (1) 00h5 - Breuken herleiden - basis - 0ms - dynamic variables a \({6 x \over x} = {6 \over 1} = 6\) 1p 1p b \({a \over 6 a}\) Vereenvoudigen (2) 00h6 - Breuken herleiden - basis - 0ms - dynamic variables b \({a \over 6 a} = {1 \over 6}\) 1p 1p c \({10 x \over 35 x}\) Vereenvoudigen (3) 00h7 - Breuken herleiden - basis - 0ms - dynamic variables c \({10 x \over 35 x} = \frac{2}{7}\) 1p 1p d \({36 a \over -4 a}\) Vereenvoudigen (4) 00h8 - Breuken herleiden - basis - 0ms - dynamic variables d \({36 a \over -4 a} = -9\) 1p opgave 4Herleid. 1p a \({-10 p q \over -14 p r}\) Vereenvoudigen (5) 00h9 - Breuken herleiden - basis - 0ms - dynamic variables a \({-10 p q \over -14 p r} = {5 q \over 7 r}\) 1p 1p b \({4 y \over -6 x y}\) Vereenvoudigen (6) 00ha - Breuken herleiden - basis - 0ms - dynamic variables b \({4 y \over -6 x y} = -{2 \over 3 x}\) 1p 1p c \({-21 a b c \over -3 b c}\) Vereenvoudigen (7) 00hb - Breuken herleiden - basis - 0ms - dynamic variables c \({-21 a b c \over -3 b c} = 7 a\) 1p 1p d \({2 p q \over q} + {6 p r \over r}\) Vereenvoudigen (8) 00hc - Breuken herleiden - basis - 0ms - dynamic variables d \({2 p q \over q} + {6 p r \over r} = 2 p + 6 p = 8 p\) 1p |
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| 2 vwo | 1.2 Herleiden van breuken |
opgave 1Herleid tot één breuk. 1p a \(2 p + {5 \over 8 p}\) Optellen (5) 008y - Breuken herleiden - basis - 0ms - dynamic variables a \(2 p + {5 \over 8 p} = {2 p \over 1} ⋅ {8 p \over 8 p} + {5 \over 8 p} = {16 p^{2} \over 8 p} + {5 \over 8 p} = {16 p^{2} + 5 \over 8 p}\) 1p 1p b \({2 y \over 8 x} + {6 x \over 3 y}\) Optellen (7) 0090 - Breuken herleiden - basis - 0ms - dynamic variables b \({2 y \over 8 x} + {6 x \over 3 y} = {6 y^{2} \over 24 x y} + {48 x^{2} \over 24 x y} = {48 x^{2} + 6 y^{2} \over 24 x y} = {8 x^{2} + y^{2} \over 4 x y}\) 1p 1p c \({3 \over a} ⋅ -{5 \over b}\) Vermenigvuldiging (1) 0091 - Breuken herleiden - basis - 0ms - dynamic variables c \({3 \over a} ⋅ -{5 \over b} = -{15 \over a b}\) 1p 1p d \({x \over 3} ⋅ -{2 \over y}\) Vermenigvuldiging (2) 0092 - Breuken herleiden - basis - 0ms - dynamic variables d \({x \over 3} ⋅ -{2 \over y} = -{2 x \over 3 y}\) 1p opgave 2Herleid tot één breuk. 1p a \(-{2 \over 7} ⋅ a\) Vermenigvuldiging (3) 0093 - Breuken herleiden - basis - 0ms - dynamic variables a \(-{2 \over 7} ⋅ a = -{2 a \over 7}\) 1p 1p b \({3 b \over a} ⋅ {a + 8 \over 7}\) Vermenigvuldiging (4) 0094 - Breuken herleiden - basis - 0ms - dynamic variables b \({3 b \over a} ⋅ {a + 8 \over 7} = {3 b (a + 8) \over 7 a} = {3 a b + 24 b \over 7 a}\) 1p 1p c \({2 \over x} : {7 \over y}\) Deling (1) 0095 - Breuken herleiden - basis - 0ms - dynamic variables c \({2 \over x} : {7 \over y} = {2 \over x} ⋅ {y \over 7} = {2 y \over 7 x}\) 1p 1p d \(-{3 \over 8} : x\) Deling (2) 0096 - Breuken herleiden - basis - 0ms - dynamic variables d \(-{3 \over 8} : x = -{3 \over 8} : {x \over 1} = -{3 \over 8} ⋅ {1 \over x} = -{3 \over 8 x}\) 1p opgave 3Herleid tot één breuk. 1p a \({6 \over 7} : {p - q \over q}\) Deling (3) 0097 - Breuken herleiden - basis - 0ms - dynamic variables a \({6 \over 7} : {p - q \over q} = {6 \over 7} ⋅ {q \over p - q} = {6 q \over 7 (p - q)} = {6 q \over 7 p - 7 q}\) 1p 1p b \({3 a \over 2} + {a - 4 \over 7}\) Optellen (8) 0098 - Breuken herleiden - basis - 0ms - dynamic variables b \({3 a \over 2} + {a - 4 \over 7} = {21 a \over 14} + {2 (a - 4) \over 14} = {21 a + 2 (a - 4) \over 14} = {23 a - 8 \over 14}\) 1p |
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| 3 vwo | 5.3 Breuken met letters herleiden |
opgave 1Herleid tot één breuk. 1p \({2 p + 5 \over 6 p - 8} - 3\) Optellen (9) 00eh - Breuken herleiden - basis - 0ms - dynamic variables ○ \({2 p + 5 \over 6 p - 8} - 3 = {2 p + 5 \over 6 p - 8} - {3 (6 p - 8) \over 6 p - 8} = {2 p + 5 - 3 (6 p - 8) \over 6 p - 8} = {2 p + 5 - 18 p + 24 \over 6 p - 8} = {-16 p + 29 \over 6 p - 8}\) 1p |
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| vwo wiskunde A | 13.3 Formules herschrijven |
opgave 1Deel uit. 1p \({3 a^{2} + 9 a + 7 \over 6 a^{2}}\) Uitdelen (2) 00ej - Breuken herleiden - basis - 0ms - dynamic variables ○ \({3 a^{2} + 9 a + 7 \over 6 a^{2}} = {3 a^{2} \over 6 a^{2}} + {9 a \over 6 a^{2}} + {7 \over 6 a^{2}} = \frac{1}{2} + {3 \over 2 a} + {7 \over 6 a^{2}}\) 1p |