\({2 \over 6 x} + {8 \over 6 x} = {10 \over 6 x} = {5 \over 3 x}\)

\({9 \over p} + {6 \over 7 p} = {63 \over 7 p} + {6 \over 7 p} = {69 \over 7 p}\)

\({4 \over 5 x} + {3 \over 2 y} = {8 y \over 10 x y} + {15 x \over 10 x y} = {8 y + 15 x \over 10 x y}\)

\(3 + {5 \over 2 a} = {3 \over 1} + {5 \over 2 a} = {6 a \over 2 a} + {5 \over 2 a} = {6 a + 5 \over 2 a}\)

\({8 a \over b} - {2 \over 4 b} = {32 a \over 4 b} - {2 \over 4 b} = {32 a - 2 \over 4 b} = {16 a - 1 \over 2 b}\)

\({6 x \over x} = {6 \over 1} = 6\)

\({a \over 4 a} = {1 \over 4}\)

\({12 p \over -28 p} = -\frac{3}{7}\)

\({45 a \over -5 a} = -9\)

\({6 x y \over 9 x z} = {2 y \over 3 z}\)

\({-16 y \over -28 x y} = {4 \over 7 x}\)

\({35 p q r \over -5 q r} = -7 p\)

\({3 a b \over b} - {6 a c \over c} = 3 a - 6 a = -3 a\)

\(5 x - {7 \over 4 x} = {5 x \over 1} ⋅ {4 x \over 4 x} - {7 \over 4 x} = {20 x^{2} \over 4 x} - {7 \over 4 x} = {20 x^{2} - 7 \over 4 x}\)

\({5 b \over 6 a} - {2 a \over 7 b} = {35 b^{2} \over 42 a b} - {12 a^{2} \over 42 a b} = {-12 a^{2} + 35 b^{2} \over 42 a b}\)

\({3 \over a} ⋅ {2 \over b} = {6 \over a b}\)

\({x \over 2} ⋅ {7 \over y} = {7 x \over 2 y}\)

\({8 \over 9} ⋅ p = {8 p \over 9}\)

\({7 b \over a} ⋅ {a - 6 \over 2} = {7 b (a - 6) \over 2 a} = {7 a b - 42 b \over 2 a}\)

\({6 \over x} : {8 \over y} = {6 \over x} ⋅ {y \over 8} = {6 y \over 8 x} = {3 y \over 4 x}\)

\(-{2 \over 5} : a = -{2 \over 5} : {a \over 1} = -{2 \over 5} ⋅ {1 \over a} = -{2 \over 5 a}\)

\(-{4 \over 3} : {x - 8 y \over y} = -{4 \over 3} ⋅ {y \over x - 8 y} = -{4 y \over 3 (x - 8 y)} = -{4 y \over 3 x - 24 y}\)

\({p \over 5} + {p + 9 \over 4} = {4 p \over 20} + {5 (p + 9) \over 20} = {4 p + 5 (p + 9) \over 20} = {9 p + 45 \over 20}\)

\({-6 p - 7 \over -2 p + 5} - 3 = {-6 p - 7 \over -2 p + 5} + {-3 (-2 p + 5) \over -2 p + 5} = {-6 p - 7 - 3 (-2 p + 5) \over -2 p + 5} = {-6 p - 7 + 6 p - 15 \over -2 p + 5} = {-22 \over -2 p + 5}\)

\({3 x^{2} - 8 x - 5 \over 6 x^{2}} = {3 x^{2} \over 6 x^{2}} - {8 x \over 6 x^{2}} - {5 \over 6 x^{2}} = \frac{1}{2} - {4 \over 3 x} - {5 \over 6 x^{2}}\)