Getal & Ruimte (12e editie) - havo wiskunde B
'Sinus, cosinus en tangens'.
| 3 havo | 6.3 Berekeningen met de tangens |
opgave 13p a Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}Q = 38 \text{,}\) \(\angle P = 36\degree\) en \(\angle Q = 90\degree \text{.}\) Tangens (1) 007m - Sinus, cosinus en tangens - basis - 0ms a Tangens in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\tan(\angle P) = {Q\kern{-.8pt}R \over P\kern{-.8pt}Q}\) ofwel \(\tan(36\degree) = {Q\kern{-.8pt}R \over 38} \text{.}\) 1p ○ Hieruit volgt \(Q\kern{-.8pt}R = 38 ⋅ \tan(36\degree) \text{.}\) 1p ○ Dus \(Q\kern{-.8pt}R ≈ 27{,}6 \text{.}\) 1p 3p b Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}Q = 34 \text{,}\) \(\angle R = 54\degree\) en \(\angle P = 90\degree \text{.}\) Tangens (2) 007n - Sinus, cosinus en tangens - basis - 0ms b Tangens in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\tan(\angle R) = {P\kern{-.8pt}Q \over P\kern{-.8pt}R}\) ofwel \(\tan(54\degree) = {34 \over P\kern{-.8pt}R} \text{.}\) 1p ○ Hieruit volgt \(P\kern{-.8pt}R = {34 \over \tan(54\degree)} \text{.}\) 1p ○ Dus \(P\kern{-.8pt}R ≈ 24{,}7 \text{.}\) 1p 3p c Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(L\kern{-.8pt}M = 34 \text{,}\) \(K\kern{-.8pt}M = 46\) en \(\angle M = 90\degree \text{.}\) Tangens (3) 007o - Sinus, cosinus en tangens - basis - 0ms c Tangens in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\tan(\angle L) = {K\kern{-.8pt}M \over L\kern{-.8pt}M}\) ofwel \(\tan(\angle L) = {46 \over 34} \text{.}\) 1p ○ Hieruit volgt \(\angle L = \tan^{-1}({46 \over 34}) \text{.}\) 1p ○ Dus \(\angle L ≈ 53{,}5\degree \text{.}\) 1p |
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| 3 havo | 6.4 De sinus en de cosinus |
opgave 13p a Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}L = 41 \text{,}\) \(\angle L = 54\degree\) en \(\angle M = 90\degree \text{.}\) Sinus (1) 007g - Sinus, cosinus en tangens - basis - 0ms a Sinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\sin(\angle L) = {K\kern{-.8pt}M \over K\kern{-.8pt}L}\) ofwel \(\sin(54\degree) = {K\kern{-.8pt}M \over 41} \text{.}\) 1p ○ Hieruit volgt \(K\kern{-.8pt}M = 41 ⋅ \sin(54\degree) \text{.}\) 1p ○ Dus \(K\kern{-.8pt}M ≈ 33{,}2 \text{.}\) 1p 3p b Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}Q = 50 \text{,}\) \(\angle R = 55\degree\) en \(\angle P = 90\degree \text{.}\) Sinus (2) 007h - Sinus, cosinus en tangens - basis - 0ms b Sinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\sin(\angle R) = {P\kern{-.8pt}Q \over Q\kern{-.8pt}R}\) ofwel \(\sin(55\degree) = {50 \over Q\kern{-.8pt}R} \text{.}\) 1p ○ Hieruit volgt \(Q\kern{-.8pt}R = {50 \over \sin(55\degree)} \text{.}\) 1p ○ Dus \(Q\kern{-.8pt}R ≈ 61{,}0 \text{.}\) 1p 3p c Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}M = 60 \text{,}\) \(K\kern{-.8pt}L = 79\) en \(\angle M = 90\degree \text{.}\) Sinus (3) 007i - Sinus, cosinus en tangens - basis - 0ms c Sinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\sin(\angle L) = {K\kern{-.8pt}M \over K\kern{-.8pt}L}\) ofwel \(\sin(\angle L) = {60 \over 79} \text{.}\) 1p ○ Hieruit volgt \(\angle L = \sin^{-1}({60 \over 79}) \text{.}\) 1p ○ Dus \(\angle L ≈ 49{,}4\degree \text{.}\) 1p 3p d Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}M = 69 \text{,}\) \(\angle K = 32\degree\) en \(\angle L = 90\degree \text{.}\) Cosinus (1) 007j - Sinus, cosinus en tangens - basis - 0ms d Cosinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\cos(\angle K) = {K\kern{-.8pt}L \over K\kern{-.8pt}M}\) ofwel \(\cos(32\degree) = {K\kern{-.8pt}L \over 69} \text{.}\) 1p ○ Hieruit volgt \(K\kern{-.8pt}L = 69 ⋅ \cos(32\degree) \text{.}\) 1p ○ Dus \(K\kern{-.8pt}L ≈ 58{,}5 \text{.}\) 1p opgave 23p a Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}L = 42 \text{,}\) \(\angle K = 36\degree\) en \(\angle L = 90\degree \text{.}\) Cosinus (2) 007k - Sinus, cosinus en tangens - basis - 0ms a Cosinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\cos(\angle K) = {K\kern{-.8pt}L \over K\kern{-.8pt}M}\) ofwel \(\cos(36\degree) = {42 \over K\kern{-.8pt}M} \text{.}\) 1p ○ Hieruit volgt \(K\kern{-.8pt}M = {42 \over \cos(36\degree)} \text{.}\) 1p ○ Dus \(K\kern{-.8pt}M ≈ 51{,}9 \text{.}\) 1p 3p b Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}B = 58 \text{,}\) \(A\kern{-.8pt}C = 65\) en \(\angle B = 90\degree \text{.}\) Cosinus (3) 007l - Sinus, cosinus en tangens - basis - 0ms b Cosinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\cos(\angle A) = {A\kern{-.8pt}B \over A\kern{-.8pt}C}\) ofwel \(\cos(\angle A) = {58 \over 65} \text{.}\) 1p ○ Hieruit volgt \(\angle A = \cos^{-1}({58 \over 65}) \text{.}\) 1p ○ Dus \(\angle A ≈ 26{,}8\degree \text{.}\) 1p |