Getal & Ruimte (12e editie) - havo wiskunde B
'Sinus, cosinus en tangens'.
| 3 havo | 6.3 Berekeningen met de tangens |
opgave 13p a Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}L = 54 \text{,}\) \(\angle K = 56\degree\) en \(\angle L = 90\degree \text{.}\) Tangens (1) 007m - Sinus, cosinus en tangens - basis - 0ms a Tangens in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\tan(\angle K) = {L\kern{-.8pt}M \over K\kern{-.8pt}L}\) ofwel \(\tan(56\degree) = {L\kern{-.8pt}M \over 54} \text{.}\) 1p ○ Hieruit volgt \(L\kern{-.8pt}M = 54 ⋅ \tan(56\degree) \text{.}\) 1p ○ Dus \(L\kern{-.8pt}M ≈ 80{,}1 \text{.}\) 1p 3p b Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(B\kern{-.8pt}C = 51 \text{,}\) \(\angle A = 42\degree\) en \(\angle B = 90\degree \text{.}\) Tangens (2) 007n - Sinus, cosinus en tangens - basis - 0ms b Tangens in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\tan(\angle A) = {B\kern{-.8pt}C \over A\kern{-.8pt}B}\) ofwel \(\tan(42\degree) = {51 \over A\kern{-.8pt}B} \text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}B = {51 \over \tan(42\degree)} \text{.}\) 1p ○ Dus \(A\kern{-.8pt}B ≈ 56{,}6 \text{.}\) 1p 3p c Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}R = 28 \text{,}\) \(P\kern{-.8pt}Q = 45\) en \(\angle P = 90\degree \text{.}\) Tangens (3) 007o - Sinus, cosinus en tangens - basis - 0ms c Tangens in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\tan(\angle R) = {P\kern{-.8pt}Q \over P\kern{-.8pt}R}\) ofwel \(\tan(\angle R) = {45 \over 28} \text{.}\) 1p ○ Hieruit volgt \(\angle R = \tan^{-1}({45 \over 28}) \text{.}\) 1p ○ Dus \(\angle R ≈ 58{,}1\degree \text{.}\) 1p |
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| 3 havo | 6.4 De sinus en de cosinus |
opgave 13p a Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}B = 47 \text{,}\) \(\angle B = 36\degree\) en \(\angle C = 90\degree \text{.}\) Sinus (1) 007g - Sinus, cosinus en tangens - basis - 0ms a Sinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\sin(\angle B) = {A\kern{-.8pt}C \over A\kern{-.8pt}B}\) ofwel \(\sin(36\degree) = {A\kern{-.8pt}C \over 47} \text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}C = 47 ⋅ \sin(36\degree) \text{.}\) 1p ○ Dus \(A\kern{-.8pt}C ≈ 27{,}6 \text{.}\) 1p 3p b Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}Q = 43 \text{,}\) \(\angle R = 32\degree\) en \(\angle P = 90\degree \text{.}\) Sinus (2) 007h - Sinus, cosinus en tangens - basis - 0ms b Sinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\sin(\angle R) = {P\kern{-.8pt}Q \over Q\kern{-.8pt}R}\) ofwel \(\sin(32\degree) = {43 \over Q\kern{-.8pt}R} \text{.}\) 1p ○ Hieruit volgt \(Q\kern{-.8pt}R = {43 \over \sin(32\degree)} \text{.}\) 1p ○ Dus \(Q\kern{-.8pt}R ≈ 81{,}1 \text{.}\) 1p 3p c Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}Q = 39 \text{,}\) \(Q\kern{-.8pt}R = 44\) en \(\angle P = 90\degree \text{.}\) Sinus (3) 007i - Sinus, cosinus en tangens - basis - 0ms c Sinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\sin(\angle R) = {P\kern{-.8pt}Q \over Q\kern{-.8pt}R}\) ofwel \(\sin(\angle R) = {39 \over 44} \text{.}\) 1p ○ Hieruit volgt \(\angle R = \sin^{-1}({39 \over 44}) \text{.}\) 1p ○ Dus \(\angle R ≈ 62{,}4\degree \text{.}\) 1p 3p d Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}C = 49 \text{,}\) \(\angle A = 56\degree\) en \(\angle B = 90\degree \text{.}\) Cosinus (1) 007j - Sinus, cosinus en tangens - basis - 0ms d Cosinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\cos(\angle A) = {A\kern{-.8pt}B \over A\kern{-.8pt}C}\) ofwel \(\cos(56\degree) = {A\kern{-.8pt}B \over 49} \text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}B = 49 ⋅ \cos(56\degree) \text{.}\) 1p ○ Dus \(A\kern{-.8pt}B ≈ 27{,}4 \text{.}\) 1p opgave 23p a Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}R = 47 \text{,}\) \(\angle R = 52\degree\) en \(\angle P = 90\degree \text{.}\) Cosinus (2) 007k - Sinus, cosinus en tangens - basis - 0ms a Cosinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\cos(\angle R) = {P\kern{-.8pt}R \over Q\kern{-.8pt}R}\) ofwel \(\cos(52\degree) = {47 \over Q\kern{-.8pt}R} \text{.}\) 1p ○ Hieruit volgt \(Q\kern{-.8pt}R = {47 \over \cos(52\degree)} \text{.}\) 1p ○ Dus \(Q\kern{-.8pt}R ≈ 76{,}3 \text{.}\) 1p 3p b Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(Q\kern{-.8pt}R = 32 \text{,}\) \(P\kern{-.8pt}Q = 59\) en \(\angle R = 90\degree \text{.}\) Cosinus (3) 007l - Sinus, cosinus en tangens - basis - 0ms b Cosinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\cos(\angle Q) = {Q\kern{-.8pt}R \over P\kern{-.8pt}Q}\) ofwel \(\cos(\angle Q) = {32 \over 59} \text{.}\) 1p ○ Hieruit volgt \(\angle Q = \cos^{-1}({32 \over 59}) \text{.}\) 1p ○ Dus \(\angle Q ≈ 57{,}2\degree \text{.}\) 1p |