\({4 \over 7 p} - {9 \over 7 p} = -{5 \over 7 p}\)

\({6 \over x} - {3 \over 7 x} = {42 \over 7 x} - {3 \over 7 x} = {39 \over 7 x}\)

\({8 \over 3 a} - {7 \over 2 b} = {16 b \over 6 a b} - {21 a \over 6 a b} = {16 b - 21 a \over 6 a b}\)

\(7 - {8 \over 3 x} = {7 \over 1} - {8 \over 3 x} = {21 x \over 3 x} - {8 \over 3 x} = {21 x - 8 \over 3 x}\)

\(8 a + {5 \over 6 a} = {8 a \over 1} ⋅ {6 a \over 6 a} + {5 \over 6 a} = {48 a^{2} \over 6 a} + {5 \over 6 a} = {48 a^{2} + 5 \over 6 a}\)

\({6 x \over y} - {3 \over 9 y} = {54 x \over 9 y} - {3 \over 9 y} = {54 x - 3 \over 9 y} = {18 x - 1 \over 3 y}\)

\({7 b \over 6 a} + {4 a \over 8 b} = {28 b^{2} \over 24 a b} + {12 a^{2} \over 24 a b} = {12 a^{2} + 28 b^{2} \over 24 a b} = {3 a^{2} + 7 b^{2} \over 6 a b}\)

\({9 p \over p} = {9 \over 1} = 9\)

\({x \over 7 x} = {1 \over 7}\)

\({16 a \over -20 a} = -\frac{4}{5}\)

\({9 a \over 3 a} = 3\)

\({-12 p q \over -28 p r} = {3 q \over 7 r}\)

\({-21 y \over -27 x y} = {7 \over 9 x}\)

\({24 a b c \over 4 b c} = 6 a\)

\({2 x y \over y} + {7 x z \over z} = 2 x + 7 x = 9 x\)

\({4 \over p} ⋅ {3 \over q} = {12 \over p q}\)

\({a \over 3} ⋅ {7 \over b} = {7 a \over 3 b}\)

\(-{2 \over 9} ⋅ x = -{2 x \over 9}\)

\({3 \over a} : {9 \over b} = {3 \over a} ⋅ {b \over 9} = {3 b \over 9 a} = {b \over 3 a}\)

\(-{3 \over 7} : x = -{3 \over 7} : {x \over 1} = -{3 \over 7} ⋅ {1 \over x} = -{3 \over 7 x}\)

\({5 p \over 2} + {p - 1 \over 7} = {35 p \over 14} + {2 (p - 1) \over 14} = {35 p + 2 (p - 1) \over 14} = {37 p - 2 \over 14}\)

\({-2 x + 8 \over 4 x + 3} + 7 = {-2 x + 8 \over 4 x + 3} + {7 (4 x + 3) \over 4 x + 3} = {-2 x + 8 + 7 (4 x + 3) \over 4 x + 3} = {-2 x + 8 + 28 x + 21 \over 4 x + 3} = {26 x + 29 \over 4 x + 3}\)

\({2 a^{2} - a - 30 \over a} = {2 a^{2} \over a} - {a \over a} - {30 \over a} = 2 a - 1 - {30 \over a}\)

\({8 p^{2} + 4 p - 3 \over 5 p^{2}} = {8 p^{2} \over 5 p^{2}} + {4 p \over 5 p^{2}} - {3 \over 5 p^{2}} = 1\frac{3}{5} + {4 \over 5 p} - {3 \over 5 p^{2}}\)