Getal & Ruimte (12e editie) - havo wiskunde B
'Breuken herleiden'.
| 2 havo/vwo | 1.2 Breuken optellen |
opgave 1Herleid tot één breuk. 1p a \({2 \over 7 x} + {3 \over 7 x}\) Optellen (1) 008u - Breuken herleiden - basis - 0ms - dynamic variables a \({2 \over 7 x} + {3 \over 7 x} = {5 \over 7 x}\) 1p 1p b \({8 \over x} + {5 \over 9 x}\) Optellen (2) 008v - Breuken herleiden - basis - 0ms - dynamic variables b \({8 \over x} + {5 \over 9 x} = {72 \over 9 x} + {5 \over 9 x} = {77 \over 9 x}\) 1p 1p c \({5 \over 7 p} - {3 \over 8 q}\) Optellen (3) 008w - Breuken herleiden - basis - 0ms - dynamic variables c \({5 \over 7 p} - {3 \over 8 q} = {40 q \over 56 p q} - {21 p \over 56 p q} = {40 q - 21 p \over 56 p q}\) 1p 1p d \(2 - {8 \over 9 a}\) Optellen (4) 008x - Breuken herleiden - basis - 0ms - dynamic variables d \(2 - {8 \over 9 a} = {2 \over 1} - {8 \over 9 a} = {18 a \over 9 a} - {8 \over 9 a} = {18 a - 8 \over 9 a}\) 1p opgave 2Herleid tot één breuk. 1p a \(6 a + {2 \over 7 a}\) Optellen (5) 008y - Breuken herleiden - basis - 0ms - dynamic variables a \(6 a + {2 \over 7 a} = {6 a \over 1} ⋅ {7 a \over 7 a} + {2 \over 7 a} = {42 a^{2} \over 7 a} + {2 \over 7 a} = {42 a^{2} + 2 \over 7 a}\) 1p 1p b \({6 a \over b} - {7 \over 5 b}\) Optellen (6) 008z - Breuken herleiden - basis - 0ms - dynamic variables b \({6 a \over b} - {7 \over 5 b} = {30 a \over 5 b} - {7 \over 5 b} = {30 a - 7 \over 5 b}\) 1p 1p c \({5 q \over 9 p} + {6 p \over 3 q}\) Optellen (7) 0090 - Breuken herleiden - basis - 0ms - dynamic variables c \({5 q \over 9 p} + {6 p \over 3 q} = {5 q^{2} \over 9 p q} + {18 p^{2} \over 9 p q} = {18 p^{2} + 5 q^{2} \over 9 p q}\) 1p opgave 3Herleid. 1p a \({6 a \over a}\) Vereenvoudigen (1) 00h5 - Breuken herleiden - basis - 0ms - dynamic variables a \({6 a \over a} = {6 \over 1} = 6\) 1p 1p b \({x \over 4 x}\) Vereenvoudigen (2) 00h6 - Breuken herleiden - basis - 0ms - dynamic variables b \({x \over 4 x} = {1 \over 4}\) 1p 1p c \({21 x \over 27 x}\) Vereenvoudigen (3) 00h7 - Breuken herleiden - basis - 0ms - dynamic variables c \({21 x \over 27 x} = \frac{7}{9}\) 1p 1p d \({18 a \over -3 a}\) Vereenvoudigen (4) 00h8 - Breuken herleiden - basis - 0ms - dynamic variables d \({18 a \over -3 a} = -6\) 1p opgave 4Herleid. 1p a \({4 x y \over -18 x z}\) Vereenvoudigen (5) 00h9 - Breuken herleiden - basis - 0ms - dynamic variables a \({4 x y \over -18 x z} = -{2 y \over 9 z}\) 1p 1p b \({9 q \over -24 p q}\) Vereenvoudigen (6) 00ha - Breuken herleiden - basis - 0ms - dynamic variables b \({9 q \over -24 p q} = -{3 \over 8 p}\) 1p 1p c \({-24 a b c \over -4 b c}\) Vereenvoudigen (7) 00hb - Breuken herleiden - basis - 0ms - dynamic variables c \({-24 a b c \over -4 b c} = 6 a\) 1p 1p d \({3 x y \over y} - {2 x z \over z}\) Vereenvoudigen (8) 00hc - Breuken herleiden - basis - 0ms - dynamic variables d \({3 x y \over y} - {2 x z \over z} = 3 x - 2 x = x\) 1p |
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| 2 havo/vwo | 1.3 Breuken vermenigvuldigen en delen |
opgave 1Herleid tot één breuk. 1p a \({5 \over a} ⋅ {4 \over b}\) Vermenigvuldiging (1) 0091 - Breuken herleiden - basis - 0ms - dynamic variables a \({5 \over a} ⋅ {4 \over b} = {20 \over a b}\) 1p 1p b \({x \over 6} ⋅ -{7 \over y}\) Vermenigvuldiging (2) 0092 - Breuken herleiden - basis - 0ms - dynamic variables b \({x \over 6} ⋅ -{7 \over y} = -{7 x \over 6 y}\) 1p 1p c \({8 \over 5} ⋅ a\) Vermenigvuldiging (3) 0093 - Breuken herleiden - basis - 0ms - dynamic variables c \({8 \over 5} ⋅ a = {8 a \over 5}\) 1p 1p d \({6 \over p} : {9 \over q}\) Deling (1) 0095 - Breuken herleiden - basis - 0ms - dynamic variables d \({6 \over p} : {9 \over q} = {6 \over p} ⋅ {q \over 9} = {6 q \over 9 p} = {2 q \over 3 p}\) 1p opgave 2Herleid tot één breuk. 1p \({6 \over 5} : x\) Deling (2) 0096 - Breuken herleiden - basis - 0ms - dynamic variables ○ \({6 \over 5} : x = {6 \over 5} : {x \over 1} = {6 \over 5} ⋅ {1 \over x} = {6 \over 5 x}\) 1p |
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| 3 havo | 5.2 Breuken met letters herleiden |
opgave 1Herleid tot één breuk. 1p \({x \over 2} + {x + 8 \over 3}\) Optellen (8) 0098 - Breuken herleiden - basis - 0ms - dynamic variables ○ \({x \over 2} + {x + 8 \over 3} = {3 x \over 6} + {2 (x + 8) \over 6} = {3 x + 2 (x + 8) \over 6} = {5 x + 16 \over 6}\) 1p |
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| havo wiskunde B | 11.5 Gebroken functies |
opgave 1Herleid tot één breuk. 1p \({4 x - 1 \over -9 x - 3} - 7\) Optellen (9) 00eh - Breuken herleiden - basis - 0ms - dynamic variables ○ \({4 x - 1 \over -9 x - 3} - 7 = {4 x - 1 \over -9 x - 3} + {-7 (-9 x - 3) \over -9 x - 3} = {4 x - 1 - 7 (-9 x - 3) \over -9 x - 3} = {4 x - 1 + 63 x + 21 \over -9 x - 3} = {67 x + 20 \over -9 x - 3}\) 1p opgave 2Deel uit. 1p a \({6 x^{2} + 2 x - 40 \over 2 x}\) Uitdelen (1) 00ei - Breuken herleiden - basis - 0ms - dynamic variables a \({6 x^{2} + 2 x - 40 \over 2 x} = {6 x^{2} \over 2 x} + {2 x \over 2 x} - {40 \over 2 x} = 3 x + 1 - {20 \over x}\) 1p 1p b \({2 a^{2} + 5 a - 9 \over 4 a^{2}}\) Uitdelen (2) 00ej - Breuken herleiden - basis - 0ms - dynamic variables b \({2 a^{2} + 5 a - 9 \over 4 a^{2}} = {2 a^{2} \over 4 a^{2}} + {5 a \over 4 a^{2}} - {9 \over 4 a^{2}} = \frac{1}{2} + {5 \over 4 a} - {9 \over 4 a^{2}}\) 1p |