\({7 \over 4x}-{6 \over 4x}={1 \over 4x}\)

\({2 \over a}-{8 \over 5a}={10 \over 5a}-{8 \over 5a}={2 \over 5a}\)

\({4 \over 8p}-{7 \over 6q}={12q \over 24pq}-{28p \over 24pq}={12q-28p \over 24pq}={3q-7p \over 6pq}\)

\(3-{9 \over 8x}={3 \over 1}-{9 \over 8x}={24x \over 8x}-{9 \over 8x}={24x-9 \over 8x}\)

\(5a-{4 \over 7a}={5a \over 1}⋅{7a \over 7a}-{4 \over 7a}={35a^2 \over 7a}-{4 \over 7a}={35a^2-4 \over 7a}\)

\({8a \over b}+{3 \over 7b}={56a \over 7b}+{3 \over 7b}={56a+3 \over 7b}\)

\({3q \over 4p}+{7p \over 2q}={3q^2 \over 4pq}+{14p^2 \over 4pq}={14p^2+3q^2 \over 4pq}\)

\({7a \over a}={7 \over 1}=7\)

\({x \over 3x}={1 \over 3}\)

\({8x \over -12x}=-\frac{2}{3}\)

\({-30p \over 5p}=-6\)

\({-16ab \over -20ac}={4b \over 5c}\)

\({15b \over 40ab}={3 \over 8a}\)

\({-6xyz \over 2yz}=-3x\)

\({6xy \over y}+{5xz \over z}=6x+5x=11x\)

\({3 \over x}⋅{8 \over y}={24 \over xy}\)

\({p \over 6}⋅{5 \over q}={5p \over 6q}\)

\(-{2 \over 3}⋅a=-{2a \over 3}\)

\({6 \over a}:{8 \over b}={6 \over a}⋅{b \over 8}={6b \over 8a}={3b \over 4a}\)

\({6 \over 5}:x={6 \over 5}:{x \over 1}={6 \over 5}⋅{1 \over x}={6 \over 5x}\)

\({8a \over 7}+{a+1 \over 3}={24a \over 21}+{7(a+1) \over 21}={24a+7(a+1) \over 21}={31a+7 \over 21}\)

\({-5x-1 \over 8x+6}+3={-5x-1 \over 8x+6}+{3(8x+6) \over 8x+6}={-5x-1+3(8x+6) \over 8x+6}={-5x-1+24x+18 \over 8x+6}={19x+17 \over 8x+6}\)

\({4x^2+6x-20 \over 2x}={4x^2 \over 2x}+{6x \over 2x}-{20 \over 2x}=2x+3-{10 \over x}\)

\({p^2-6p-3 \over 7p^2}={p^2 \over 7p^2}-{6p \over 7p^2}-{3 \over 7p^2}=\frac{1}{7}-{6 \over 7p}-{3 \over 7p^2}\)