\({2 \over 7p}+{4 \over 7p}={6 \over 7p}\)

\({4 \over x}+{9 \over 5x}={20 \over 5x}+{9 \over 5x}={29 \over 5x}\)

\({6 \over 5x}-{8 \over 3y}={18y \over 15xy}-{40x \over 15xy}={18y-40x \over 15xy}\)

\(7+{6 \over 5a}={7 \over 1}+{6 \over 5a}={35a \over 5a}+{6 \over 5a}={35a+6 \over 5a}\)

\(2a-{8 \over 3a}={2a \over 1}⋅{3a \over 3a}-{8 \over 3a}={6a^2 \over 3a}-{8 \over 3a}={6a^2-8 \over 3a}\)

\({4x \over y}-{2 \over 8y}={32x \over 8y}-{2 \over 8y}={32x-2 \over 8y}={16x-1 \over 4y}\)

\({6q \over 8p}-{3p \over 5q}={30q^2 \over 40pq}-{24p^2 \over 40pq}={-24p^2+30q^2 \over 40pq}={-12p^2+15q^2 \over 20pq}\)

\({9x \over x}={9 \over 1}=9\)

\({a \over 2a}={1 \over 2}\)

\({15a \over 21a}=\frac{5}{7}\)

\({-18a \over -2a}=9\)

\({25xy \over 40xz}={5y \over 8z}\)

\({-8b \over -18ab}={4 \over 9a}\)

\({12pqr \over 2qr}=6p\)

\({4xy \over y}-{7xz \over z}=4x-7x=-3x\)

\({3 \over a}⋅-{6 \over b}=-{18 \over ab}\)

\({p \over 2}⋅{8 \over q}={8p \over 2q}={4p \over q}\)

\(-{3 \over 7}⋅x=-{3x \over 7}\)

\({8 \over x}:{3 \over y}={8 \over x}⋅{y \over 3}={8y \over 3x}\)

\({5 \over 4}:a={5 \over 4}:{a \over 1}={5 \over 4}⋅{1 \over a}={5 \over 4a}\)

\({p \over 9}+{p+6 \over 5}={5p \over 45}+{9(p+6) \over 45}={5p+9(p+6) \over 45}={14p+54 \over 45}\)

\({5x-6 \over -2x-8}-4={5x-6 \over -2x-8}+{-4(-2x-8) \over -2x-8}={5x-6-4(-2x-8) \over -2x-8}={5x-6+8x+32 \over -2x-8}={13x+26 \over -2x-8}\)

\({3p^2-2p+10 \over p}={3p^2 \over p}-{2p \over p}+{10 \over p}=3p-2+{10 \over p}\)

\({9x^2+7x-8 \over 4x^2}={9x^2 \over 4x^2}+{7x \over 4x^2}-{8 \over 4x^2}=2\frac{1}{4}+{7 \over 4x}-{2 \over x^2}\)