\(\sqrt{1} = 1\)

\(\sqrt{25} = 5\)

\(\sqrt{144} = 12\)

\(\sqrt{25} - \sqrt{16} = 5 - 4 = 1\)

\(3 \sqrt{144} - 11 \sqrt{64} = 3 ⋅ 12 - 11 ⋅ 8 = -52\)

\(\sqrt{4} ⋅ \sqrt{49} = 2 ⋅ 7 = 14\)

\(\sqrt{6^{2} + 13} = \sqrt{36 + 13} = \sqrt{49} = 7\)

\(-\sqrt{49} = -7\)

\(\sqrt{-9}\) kan niet.

\(\sqrt{4^{2}} = 4\)

\(\sqrt{(-4)^{2}} = \sqrt{16} = 4\)

\(5 ⋅ \sqrt{64} = 5 ⋅ 8 = 40\)

\({3 \sqrt{7} \over 2} = 1\frac{1}{2} \sqrt{7} \text{.}\)

\(2 \sqrt{3} - \sqrt{3} = \sqrt{3}\)

\(8 \sqrt{3} - 4 \sqrt{5}\) kan niet korter.

\(4 \sqrt{3} ⋅ 5 \sqrt{12} = 20 ⋅ \sqrt{36} = 20 ⋅ 6 = 120\)

\(2 \sqrt{5} ⋅ 3 \sqrt{3} = 6 \sqrt{15}\)

\({\sqrt{6} \over \sqrt{3}} = \sqrt{2}\)

\({48 \sqrt{21} \over 8 \sqrt{3}} = {48 \over 8} ⋅ {\sqrt{21} \over \sqrt{3}} = 6 \sqrt{7}\)

\({24 \sqrt{90} \over 6 \sqrt{10}} = {24 \over 6} ⋅ {\sqrt{90} \over \sqrt{10}} = 4 ⋅ \sqrt{9} = 4 ⋅ 3 = 12\)

\((9 \sqrt{6})^{2} = 9^{2} ⋅ \sqrt{6}^{2} = 81 ⋅ 6 = 486 \text{.}\)

\((\sqrt{6})^{2} = 6 \text{.}\)

\(8 (\sqrt{3})^{2} = 8 ⋅ 3 = 24 \text{.}\)

\((3 \sqrt{7})^{2} - 5 (\sqrt{6})^{2} = 3^{2} ⋅ (\sqrt{7})^{2} - 5 ⋅ (\sqrt{6})^{2} = 9 ⋅ 7 - 5 ⋅ 6 = 33 \text{.}\)