\({5 \over 8 p} - {3 \over 8 p} = {2 \over 8 p} = {1 \over 4 p}\)

\({6 \over a} - {9 \over 4 a} = {24 \over 4 a} - {9 \over 4 a} = {15 \over 4 a}\)

\({2 \over 4 x} + {5 \over 8 y} = {4 y \over 8 x y} + {5 x \over 8 x y} = {4 y + 5 x \over 8 x y}\)

\(5 - {4 \over 3 a} = {5 \over 1} - {4 \over 3 a} = {15 a \over 3 a} - {4 \over 3 a} = {15 a - 4 \over 3 a}\)

\(9 x + {7 \over 5 x} = {9 x \over 1} ⋅ {5 x \over 5 x} + {7 \over 5 x} = {45 x^{2} \over 5 x} + {7 \over 5 x} = {45 x^{2} + 7 \over 5 x}\)

\({8 x \over y} + {4 \over 2 y} = {16 x \over 2 y} + {4 \over 2 y} = {16 x + 4 \over 2 y} = {8 x + 2 \over y}\)

\({2 q \over 3 p} + {7 p \over 4 q} = {8 q^{2} \over 12 p q} + {21 p^{2} \over 12 p q} = {21 p^{2} + 8 q^{2} \over 12 p q}\)

\({9 a \over a} = {9 \over 1} = 9\)

\({x \over 6 x} = {1 \over 6}\)

\({8 a \over -12 a} = -\frac{2}{3}\)

\({-14 x \over 2 x} = -7\)

\({40 a b \over -45 a c} = -{8 b \over 9 c}\)

\({28 b \over -32 a b} = -{7 \over 8 a}\)

\({-27 p q r \over 3 q r} = -9 p\)

\({7 x y \over y} - {6 x z \over z} = 7 x - 6 x = x\)

\({2 \over p} ⋅ {8 \over q} = {16 \over p q}\)

\({x \over 4} ⋅ {9 \over y} = {9 x \over 4 y}\)

\(-{7 \over 4} ⋅ x = -{7 x \over 4}\)

\({9 \over a} : {4 \over b} = {9 \over a} ⋅ {b \over 4} = {9 b \over 4 a}\)

\(-{1 \over 9} : a = -{1 \over 9} : {a \over 1} = -{1 \over 9} ⋅ {1 \over a} = -{1 \over 9 a}\)

\({9 p \over 7} + {p + 6 \over 4} = {36 p \over 28} + {7 (p + 6) \over 28} = {36 p + 7 (p + 6) \over 28} = {43 p + 42 \over 28}\)

\({6 b \over a} ⋅ {a + 4 \over 8} = {6 b (a + 4) \over 8 a} = {3 b (a + 4) \over 4 a} = {3 a b + 12 b \over 4 a}\)

\(-{3 \over 2} : {x - y \over y} = -{3 \over 2} ⋅ {y \over x - y} = -{3 y \over 2 (x - y)} = -{3 y \over 2 x - 2 y}\)

\({2 x^{2} + 3 x - 10 \over x} = {2 x^{2} \over x} + {3 x \over x} - {10 \over x} = 2 x + 3 - {10 \over x}\)

\({2 a^{2} - 9 a + 7 \over 6 a^{2}} = {2 a^{2} \over 6 a^{2}} - {9 a \over 6 a^{2}} + {7 \over 6 a^{2}} = \frac{1}{3} - {3 \over 2 a} + {7 \over 6 a^{2}}\)