\({8 \over 2 x} + {9 \over 2 x} = {17 \over 2 x}\)

\({9 \over x} - {5 \over 2 x} = {18 \over 2 x} - {5 \over 2 x} = {13 \over 2 x}\)

\({2 \over 7 a} - {5 \over 3 b} = {6 b \over 21 a b} - {35 a \over 21 a b} = {6 b - 35 a \over 21 a b}\)

\(7 - {5 \over 6 p} = {7 \over 1} - {5 \over 6 p} = {42 p \over 6 p} - {5 \over 6 p} = {42 p - 5 \over 6 p}\)

\(5 a + {7 \over 6 a} = {5 a \over 1} ⋅ {6 a \over 6 a} + {7 \over 6 a} = {30 a^{2} \over 6 a} + {7 \over 6 a} = {30 a^{2} + 7 \over 6 a}\)

\({7 x \over y} - {9 \over 2 y} = {14 x \over 2 y} - {9 \over 2 y} = {14 x - 9 \over 2 y}\)

\({7 b \over 2 a} - {5 a \over 3 b} = {21 b^{2} \over 6 a b} - {10 a^{2} \over 6 a b} = {-10 a^{2} + 21 b^{2} \over 6 a b}\)

\({6 a \over a} = {6 \over 1} = 6\)

\({x \over 7 x} = {1 \over 7}\)

\({-8 p \over -20 p} = \frac{2}{5}\)

\({-15 p \over -5 p} = 3\)

\({-8 a b \over -20 a c} = {2 b \over 5 c}\)

\({6 y \over -27 x y} = -{2 \over 9 x}\)

\({45 a b c \over 5 b c} = 9 a\)

\({3 x y \over y} + {2 x z \over z} = 3 x + 2 x = 5 x\)

\({8 \over a} ⋅ {2 \over b} = {16 \over a b}\)

\({p \over 4} ⋅ -{5 \over q} = -{5 p \over 4 q}\)

\({4 \over 9} ⋅ a = {4 a \over 9}\)

\({8 \over x} : {5 \over y} = {8 \over x} ⋅ {y \over 5} = {8 y \over 5 x}\)

\({5 \over 3} : x = {5 \over 3} : {x \over 1} = {5 \over 3} ⋅ {1 \over x} = {5 \over 3 x}\)

\({7 x \over 3} + {x + 5 \over 4} = {28 x \over 12} + {3 (x + 5) \over 12} = {28 x + 3 (x + 5) \over 12} = {31 x + 15 \over 12}\)

\({9 q \over p} ⋅ {p - 5 \over 8} = {9 q (p - 5) \over 8 p} = {9 p q - 45 q \over 8 p}\)

\(-{6 \over 5} : {a + 2 b \over b} = -{6 \over 5} ⋅ {b \over a + 2 b} = -{6 b \over 5 (a + 2 b)} = -{6 b \over 5 a + 10 b}\)

\({6 a^{2} + 9 a + 30 \over 3 a} = {6 a^{2} \over 3 a} + {9 a \over 3 a} + {30 \over 3 a} = 2 a + 3 + {10 \over a}\)

\({7 x^{2} + 5 x + 9 \over 4 x^{2}} = {7 x^{2} \over 4 x^{2}} + {5 x \over 4 x^{2}} + {9 \over 4 x^{2}} = 1\frac{3}{4} + {5 \over 4 x} + {9 \over 4 x^{2}}\)