\({4 \over 3 p} - {8 \over 3 p} = -{4 \over 3 p}\)

\({2 \over x} - {9 \over 8 x} = {16 \over 8 x} - {9 \over 8 x} = {7 \over 8 x}\)

\({9 \over 2 x} + {5 \over 4 y} = {18 y \over 4 x y} + {5 x \over 4 x y} = {18 y + 5 x \over 4 x y}\)

\(7 - {9 \over 8 a} = {7 \over 1} - {9 \over 8 a} = {56 a \over 8 a} - {9 \over 8 a} = {56 a - 9 \over 8 a}\)

\(4 a + {5 \over 3 a} = {4 a \over 1} ⋅ {3 a \over 3 a} + {5 \over 3 a} = {12 a^{2} \over 3 a} + {5 \over 3 a} = {12 a^{2} + 5 \over 3 a}\)

\({3 x \over y} + {2 \over 6 y} = {18 x \over 6 y} + {2 \over 6 y} = {18 x + 2 \over 6 y} = {9 x + 1 \over 3 y}\)

\({2 y \over 6 x} - {5 x \over 3 y} = {2 y^{2} \over 6 x y} - {10 x^{2} \over 6 x y} = {-10 x^{2} + 2 y^{2} \over 6 x y} = {-5 x^{2} + y^{2} \over 3 x y}\)

\({4 p \over p} = {4 \over 1} = 4\)

\({a \over 5 a} = {1 \over 5}\)

\({16 a \over 28 a} = \frac{4}{7}\)

\({-6 x \over 2 x} = -3\)

\({16 x y \over 36 x z} = {4 y \over 9 z}\)

\({-12 q \over 28 p q} = -{3 \over 7 p}\)

\({15 a b c \over -5 b c} = -3 a\)

\({6 a b \over b} + {4 a c \over c} = 6 a + 4 a = 10 a\)

\({9 \over x} ⋅ {2 \over y} = {18 \over x y}\)

\({x \over 9} ⋅ {5 \over y} = {5 x \over 9 y}\)

\({8 \over 3} ⋅ p = {8 p \over 3}\)

\({5 \over a} : {9 \over b} = {5 \over a} ⋅ {b \over 9} = {5 b \over 9 a}\)

\({4 \over 5} : a = {4 \over 5} : {a \over 1} = {4 \over 5} ⋅ {1 \over a} = {4 \over 5 a}\)

\({6 a \over 5} + {a - 2 \over 8} = {48 a \over 40} + {5 (a - 2) \over 40} = {48 a + 5 (a - 2) \over 40} = {53 a - 10 \over 40}\)

\({4 y \over x} ⋅ {x + 9 \over 7} = {4 y (x + 9) \over 7 x} = {4 x y + 36 y \over 7 x}\)

\(-{3 \over 7} : {p - 2 q \over q} = -{3 \over 7} ⋅ {q \over p - 2 q} = -{3 q \over 7 (p - 2 q)} = -{3 q \over 7 p - 14 q}\)

\({3 x^{2} + 9 x + 60 \over 3 x} = {3 x^{2} \over 3 x} + {9 x \over 3 x} + {60 \over 3 x} = x + 3 + {20 \over x}\)

\({9 p^{2} + 8 p + 1 \over 4 p^{2}} = {9 p^{2} \over 4 p^{2}} + {8 p \over 4 p^{2}} + {1 \over 4 p^{2}} = 2\frac{1}{4} + {2 \over p} + {1 \over 4 p^{2}}\)